I have a total of Rs. 300 in coins of denomination Rs. 1, Rs.2 and Rs. 5. The number of Rs. 2 coins is 3 times the number of Rs.5 coins. The total number of coins is 160.How many coins of each denomination are with me?

5

(a)

My age is four time the difference of my age after four years and three years before. How old am I?

5

(a)

Three prizes are to be distributed in a quiz contest. The value of the second prize is five-sixth the value of the first prize and the value of the third prize is four-fifth that of the second prize. If the total value of three prizes is Rs. 150, then find the value of each prize.

5

(a)

Abdul buys two kinds of cloth material for school uniforms, shirt material which costs him Rs. 50 per metre and trouser material that costs him Rs. 90 per metre. For every 2 m of the trouser material, he buys 3 m of the shirt material. He sells the material at 12% and 20% profit, respectively. His total sale is Rs. 38160. How much trouser material did he buy?

5

(a)

Denominator of a number is 4 less than its numerator. If 6 is added to the numerator, it becomes thrice the denominator. Find the fraction.

5

(a)

Hamid has three boxes of different fruits. Box A weights 2\(\frac { 1 }{ 2 } \) kg more than box B and box C weights 10 \(\frac { 1 }{ 4 } \)  kg more than box B. The total  weights of the three boxes is 48\(\frac { 3 }{ 4 } \)  How  many kilograms does box A weigh?  

5

(a)

In a rare coin collection, there is one gold coin for every three non-gold coins. If 10 more gold coins are added to the collection, the ratio of gold coins to non-gold coins becomes 1 : 2. Based on the information, find the total number of coins in the collection now?

5

(a)

Sahil and Suraj are close friends. Sahil's monthly salary is 3 times less than Suraj. Suaj helps Sahil every month with Rs.6000, after which Sahil is left with total money half of the money Suraj has. Then,
(a) find the salary of Sahil and Suraj.
(b) what type of value is depicted by Suraj

5

(a)

Solve: \({3x+10\over 5x+10}={5\over 7}\)

5

(a)

Solve: x² + 10x + 21 = x² + 4x + 81

5

(a)