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11th Standard English Medium Maths Subject Binomial Theorem, Sequences and Series Book Back 1 Mark Questions with Solution Part - I

11th Standard

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Maths

Time : 01:00:00 Hrs
Total Marks : 10

    1 Marks

    10 x 1 = 10
  1. If a, 8, b are in AP, a, 4, b are in GP, and if a, x, b are in HP then x is

    (a)

    2

    (b)

    1

    (c)

    4

    (d)

    16

  2. The sequence \(\frac { 1 }{ \sqrt { 3 } } ,\frac { 1 }{ \sqrt { 3 } +\sqrt { 2 } }, \frac { 1 }{ \sqrt { 3 } +2\sqrt { 2 } },...... \)form an 

    (a)

    AP

    (b)

    GP

    (c)

    HP

    (d)

    AGP

  3. If Sn denotes the sum of n terms of an AP whose common difference is d, the value of S- 2Sn-1 + Sn-2 is

    (a)

    d

    (b)

    2d

    (c)

    4d

    (d)

    d2

  4. The remainder when 3815 is divided by 13 is

    (a)

    12

    (b)

    1

    (c)

    11

    (d)

    5

  5. The nth term of the sequence 1, 2, 4, 7, 11,... is

    (a)

    n+ 3n+ 2n

    (b)

    n3n+ 3n

    (c)

    \(\frac { n(n+1)(n+2) }{ 3 } \)

    (d)

    \(\frac { { n }^{ 2 }-n+2 }{ 2 } \)

  6. The sum up to n terms of the series \(\frac { 1 }{ \sqrt { 1 } +\sqrt { 3 } } +\frac { 1 }{ \sqrt { 3 } +\sqrt { 5 } } +\frac { 1 }{ \sqrt { 5 } +\sqrt { 7 } } +\)....is 

    (a)

    \(\sqrt { 2n+1 } \)

    (b)

    \(\frac { \sqrt { 2n+1 } }{ 2 } \)

    (c)

    \(\sqrt { 2n+1 } -1\)

    (d)

    \(\frac { \sqrt { 2n+1 } -1 }{ 2 } \)

  7. The nth term of the sequence \(\frac { 1 }{ 2 } ,\frac { 3 }{ 4 } ,\frac { 7 }{ 8 } ,\frac { 15 }{ 6 } \),......is

    (a)

    2- n - 1

    (b)

    1 - 2-n

    (c)

    2-n + n - 1

    (d)

    2n-1

  8. The sum up to n terms of the series \(\sqrt { 2 } +\sqrt { 8 } +\sqrt { 18 } +\sqrt { 32 } +\).....is

    (a)

    \(\frac { n(n+1) }{ 2 } \)

    (b)

    2n(n+1)

    (c)

    \(\frac { n(n+1) }{ \sqrt { 2 } } \)

    (d)

    1

  9. The value of the series\(\frac { 1 }{ 2 } +\frac { 7 }{ 4 } +\frac { 13 }{ 8 } +\frac { 19 }{ 16 } +\).....is

    (a)

    14

    (b)

    7

    (c)

    4

    (d)

    6

  10. The sum of an infinite GP is 18. If the first term is 6, the common ratio is

    (a)

    \(\frac { 1 }{ 3 } \)

    (b)

    \(\frac { 2 }{ 3 } \)

    (c)

    \(\frac { 1 }{ 6 } \)

    (d)

    \(\frac { 3 }{ 4 } \)

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