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12th Standard English Medium Maths Subject Inverse Trigonometric Functions Book Back 1 Mark Questions with Solution Part - I

12th Standard

    Reg.No. :
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Maths

Time : 01:00:00 Hrs
Total Marks : 5

    1 Marks

    5 x 1 = 5
  1. The domain of the function defined by \(f(x)=\sin ^{-1} \sqrt{x-1}\) is

    (a)

    [1, 2]

    (b)

    [-1, 1]

    (c)

    [0, 1]

    (d)

    [-1, 0]

  2. If \(x = \frac{1}{5}\), the value of cos (cos-1x+2sin-1x) is

    (a)

    \(-\sqrt { \frac { 24 }{ 25 } } \)

    (b)

    \(\sqrt { \frac { 24 }{ 25 } } \)

    (c)

    \(\frac{1}{5}\)

    (d)

    \(-\frac{1}{5}\)

  3. \(\tan ^{-1}\left(\frac{1}{4}\right)+\tan ^{-1}\left(\frac{2}{9}\right)\) is equal to

    (a)

    \(\frac { 1 }{ 2 } \ { cos }^{ -1 }\left( \frac { 3 }{ 5 } \right) \)

    (b)

    \(\frac { 1 }{ 2 } { sin }^{ -1 }\left( \frac { 3 }{ 5 } \right) \)

    (c)

    \(\frac { 1 }{ 2 } {tan }^{ -1 }\left( \frac { 3 }{ 5 } \right) \)

    (d)

    \({ tan}^{ -1 }\left( \frac { 1}{ 2 } \right) \)

  4. \(\sin ^{-1}\left(\tan \frac{\pi}{4}\right)-\sin ^{-1}\left(\sqrt{\frac{3}{x}}\right)=\frac{\pi}{6}\). Then x is a root of the equation

    (a)

    x2−x−6 = 0

    (b)

    x2−x−12 = 0

    (c)

    x2+x−12 = 0

    (d)

    x2+x−6 = 0

  5. sin (tan-1x), |x| < 1 is equal to

    (a)

    \(\frac{x}{\sqrt{1-x^2}}\)

    (b)

    \(\frac{1}{\sqrt{1-x^2}}\)

    (c)

    \(\frac{1}{\sqrt{1+x^2}}\)

    (d)

    \(\frac{x}{\sqrt{1+x^2}}\)

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