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Published on: 04/10/2019
Optics
Download Tamil Nadu 10th Standard Science question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Science Test1.
Explain the refraction of light through a glass prism.
2.
Explain the types of Telescope.
3.
Write the sign convention for lenses.
4.
Explain Raman Scattering.
5.
State the laws of refraction.
6.
For a person with hypermetropia, the near point has moved to 1.5m. Calculate the focal length of the correction lens in order to make his eyes normal.
7.
A person with myopia can see objects placed at a distance of 4m. If he wants to see objects at a distance of 20m, what should be the focal length and power of the concave lens he must wear?
8.
A beam of light passing through a diverging lens of focal length 0.3m appear to be focused at a distance 0.2m behind the lens. Find the position of the object.
9.
Light rays travel from vacuum into a glass whose refractive index is 1.5. If the angle of incidence is 30°, calculate the angle of refraction inside the glass.
10.
Light in air enters a diamond at 45°. What is the angle of refraction? G.T μdia = 2.42.
1.
(i) When a beam of white light or composite light is refracted through any transparent media such as glass or water, it is split into its component colours.
(ii) This phenomenon is called as 'dispersion of light'.
(iii) The band of colours is termed as spectrum. This spectrum consists of following colours: Violet, Indigo, Blue, Green, Yellow, Orange, and Red. These colours are represented by the acronym "VIBGYOR".
(iv ) When white light is refracted by a transparent medium. Different coloured lights are bent through different angles. That is the angle of refraction is different for different colours.
(v) Angle of refraction is the smallest for red and the highest for violet.
(vi) From Snell's law, we know that the angle of refraction is determined in terms of the refractive index of the medium.
(vii) Hence, the refractive index of the medium is different for different coloured lights.
2.
According to optical property, it is classified into two types.
(i) Refracting telescope
(ii Reflecting telescope
(i) Refracting telescope: Lenses are used in this kind of telescopes. Galilean telescope, Keplerian telescope, Achromatic refractors, Apochromatic refractors are some Refracting telescope.
(ii) Reflecting telescope: Parabolic mirrors are used in these kind telescopes. Gregorian, Newtonian, Cassegrain telescope, Ritchey- Chretien telescope are some Reflecting telescopes. According to the things which are observed, Astronomical Telescope and Terrestrial Telescopes are the two major types of telescope.
3.
| S.No. | Convex Lens | Concave Lens |
| i | Focal length | + for convex lens - for concave lens |
| ii | Distance of object | - if the object is to the left object of the lens + if the object is to the right of the lens |
| iii | Distance of image | + if the image is formed on the right of the lens (real image) - if the image is formed one the left of the lens (virtual image) |
| iv | Magnification | + for erect images - for inverted images |
4.
(i) When a parallel beam of monochromatic (single coloured ) light passes through a gas or liquid or transparent solid, a part of light rays are scattered. This scattering is called Raman scattering (inelastic scattering).
(ii) Raman Scattering is defined as "The interaction of light ray with the particles of pure liquids or transparent solids, which leads to a change in wavelength or frequency".
(iii) The scattered light contains some additional frequencies (or wavelengths) other than that of incident frequency (or wavelength). This is known as Raman scattering or Raman Effect.
(iv) The modified lines are called 'Raman lines' and the unmodified lines are called as 'Rayleigh lines'. The lines having frequencies lower than the incident frequency is called stokes lines and the lines having frequencies higher than the incident frequency are called Anti-stokes lines.
5.
(i) First law of refraction : The incident ray of light, the refracted ray of light and the normal to the refracting surface all lie in the same plane.
(ii) Second law of refraction : The ratio of the sine of the angle of incidence and sine of the angle of refraction is equal to the ratio of refractive indices of the two media. This law is also known as Snell's law.
\(\frac{\operatorname{sin i}}{\sin x}=\frac{\mu_2}{\mu_1} .\).
6.
Given that, d = 1.5m; D = 25cm = 0.25m (For a normal eye).
From equation (2.8), the focal length of the correction lens is
\(f=\cfrac { d\times D }{ d-D } =\cfrac { 1.5\times 0.25 }{ 1.5-0.25 } =\cfrac { 0.375 }{ 1.25 } =0.3m\)
7.
Given that x = 4m and y = 20m.
Focal length of the correction lens is
\(f=\cfrac { xy }{ x-y } \)
\(f=\cfrac { 4\times 20 }{ 4-20 } =\cfrac { 80 }{ -16 } =-5m\)
Power of the correction lens
= \(\cfrac { 1 }{ f } =-\cfrac { 1 }{ 5 } =-0.2D\)
8.
f = -0.3m, v = -0.2m
\(\cfrac { 1 }{ f } =\cfrac { 1 }{ v } -\cfrac { 1 }{ u } \)
\(\cfrac { 1 }{ u } =\cfrac { 1 }{ v } -\cfrac { 1 }{ f } \)
\(\cfrac { 1 }{ u } =\cfrac { 1 }{ -0.2 } -\cfrac { 1 }{ -0.3 } =\cfrac { -10 }{ 6 } \)
\(u=\cfrac { -6 }{ 10 } =-0.6m\)
9.
According to Snell’s law,
\(\frac{\sin i}{\sin r}=\frac{\mu_2}{\mu_1}\)
\(\mu_1 \sin i=\mu_2 \sin r\)
Here \({ \mu }_{ 1 }=1.0,{ \mu }_{ 2 }=1.5,i\ ={ 30 }^{ 0 }\)
\(\begin{aligned} & (1.0) \sin 30^0=1.5 \sin r \end{aligned}\)
\(\begin{aligned} 1 \times \frac{1}{2}=1.5 \sin r \end{aligned}\)
\(\sin r=\frac{1}{2 \times 1.5}=\frac{1}{3}=(0.333)\)
r = sin-1(0.333)
r = 19.45o
10.
μa sin i = μdia sin r ............(1)
(Reactive index of air, μa = 1)
(Angle of incidence, i = 45°)
in (1)
(1) ⇒ (sin 450) =2.42 (sin r)
sin r=\(\left( \frac { sin{ 45 }^{ 0 } }{ 2.42 } \right) \)
r=sin-1\(\frac { \frac { 1 }{ \sqrt { 2 } } }{ 2.42 } \)
r=sin-1\(\left[ \frac { 1 }{ \sqrt { 2 } \times 2.42 } \right] \)
Angle of refraction,
r=16.977 =170.
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