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Published on: 29/11/2019
Thermal Physics
Download Tamil Nadu 10th Standard Science question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Science Test1.
With an illustration, explain the method of Calculation for areal expansion of an object.
2.
Define and describe thermal expansion.
3.
Calculate the coefficient of cubical expansion of a zinc bar. Whose volume is increased 0.25 m3 from 0.3 m3 due to the change in its temperature of 50 K.
4.
Keeping the temperature as constant, a gas is compressed four times of its initial pressure. The volume of gas in the container changing from 20cc (V1 cc) to V2 cc. Find the final volume V2.
5.
6.
If the atoms or molecules of a gas do not interact with each other, then the gas is said to be ______.
a real gas
an ideal gas
a noble gas
a rare gas
7.
Linear expansion is the change in _____ when object is heated or cooled.
length
area
volume
density
8.
Temperature is the average ______ of the molecules of a substance
difference in K.E and P.E
sum of P.E and K.E
difference in T.E and P.E
difference in K.E and T.E
9.
The value of universal gas constant
3.81 J mol–1 K–1
8.03 J mol–1 K–1
1.38 J mol–1 K–1
8.31 J mol–1 K–1
10.
What is meant by real expansion?
11.
Define coefficient of linear expansion. Write its equation.
12.
What is thermal energy?
13.
Distinguish between ideal gas and real gas.
14.
State-the law of volume
15.
At 303 k the volume of an aluminium sphere is 0.3 m3. The coefficient linear expansion αL=24 K-1. If the final volume is 0.35 m3. What is the final temperature of aluminium sphere?
16.
An aluminium sheet of length 30 m is made into cone for temperature range ΔT = 300 k. Find the change in length of AI sheet?
17.
Does a substance that heats up quickly have a high or a low specific heat capacity?
1.
(i) If there is an increase in the area of a solid object due to heating, then the expansion is called superficial or areal expansion.
(ii) Superficial expansion is determined in terms of coefficient of superficial expansion. The ratio of increase in area of the body, per degree rise in temperature to its unit area is called coefficient of superficial expansion. Coefficient of superficial expansion is different for different materials. Its SI unit is also per Kelvin.
(iii) The equation relating to the change in area to the change in temperature is given below:

\(\frac { \triangle A }{ { A }_{ 0 } } \) =αA ΔT
ΔA - Change in area
A0 - Original area
ΔT - Change in area
αA - Coefficient of superficial expansion
2.
(i) When heat energy is supplied to a body, there can be an increase in the dimension of the object. This change in the dimension due to rise in temperature is called thermal expansion of the object.
(ii) The expansion of liquids (eg. mercury) can be seen when a thermometer is placed in warm water. All forms of matter (solid, liquid and gas) undergo expansion on heating.
(iii) When a solid is heated, the atoms gain energy and vibrate more vigorously. This results in the expansion of the solid.
(iv) The different types of expansion of solid are
i) Linear expansion
ii) Superficial expansion
iii) Cubical expansion
(v) When heated, the atoms in a liquid or gas gain energy and are forced further apart. The extent of expansion varies from substance to substance. For a given rise in temperature, a liquid will have more expansion than a solid and a gaseous substance has the highest expansion when compared with the other two.
3.
Change in volume \((\Delta V)=0.3-0.25 =0.05\mathrm{~m}^{3}\)
Original volume \(\left(V_{0}\right)=0.3 \mathrm{~m}^{3}\)
Change in Temperature \(\Delta \mathrm{T}=50 \mathrm{~K}\)
\(a_{\mathrm{V}} =? \)
\(\frac{\Delta V}{V_{0}} =a_{\mathrm{V}} \Delta \mathrm{T}\)
\(a_{\mathrm{V}} =\frac{0.05}{0.3 \times 50}=\frac{0.05}{15}=0.0033 \mathrm{~K}^{-1}\)
Co-efficient of cubical expansion of Zinc bar 0.0033
4.
Data:
Initial pressure (P1)= P
Final Pressure (P2) = 4P
Initial volume (V1) = 20cc = 20cm3
Final volume (V2) = ?
Using Boyle's Law, PV = constant
P1V1 = P2V2
\({ V }_{ 2 }=\frac { { P }_{ 1 } }{ { P }_{ 2 } } \times { v }_{ 1 }\)
\(=\frac { P }{ 4P } \times 20{ cm }^{ 3 }\)
V2 = 5 cm3
5.
(a)
6.
(b)
an ideal gas
7.
(a)
length
8.
(c)
difference in T.E and P.E
9.
(d)
8.31 J mol–1 K–1
10.
If a liquid is heated directly without using any container, then the expansion that we observe is termed as "real expansion" of the liquid.
11.
(i) Increase in length per unit of the length of the solid object per degree celsius rise in temperature is called 'coefficient of linear expansion'.
(ii) Its SI unit is per kelvin.
\(\frac { \triangle L }{ { L }_{ 0 } } ={ \alpha }_{ L }\triangle T\Rightarrow { \alpha }_{ L }\frac { \triangle L }{ \triangle T.L_{ 0 } } \)
ΔL - change in length
L0 - original length
ΔT - change in Temperature
αL - coefficient of Linear expansion
12.
Thermal energy is a form of energy which is transferred between any two objects due to the difference in their temperatures.
13.
| S. No |
Ideal gas |
Real gas |
|---|---|---|
| (i) | If the atoms or molecules of a gas do not interact with each other, then the gas is said to be an ideal gas or a perfect gas. | If the molecules or atoms of a gas interact with each other with a definite amount of intermolecular or interatomic force of attraction, then the gases are said to be a real gases. |
14.
Charles's law is otherwise called as the law of volume. It states that, when the pressure of gas is kept constant, the volume of the gas is directly proportional to the temperature of the gas.
\(\mathrm{V} \propto {T}\)
15.
The coefficient of linear expansion,
αL =24 K-1
The coefficient of cubical expansion,
αv =3αL= 3 x 24
= 72 K-1
The initial temperature, T1 = 303 K
The initial volume, V0 = 0.3 m3
The final volume, V1 = 0.35 m3
Change in volume ΔV = 0.35 - 0.30
= 0.05 m3
To find: The final temperature T2= ?
ΔV = αv. V0 (ΔT)
0.05 = 72 x 0.3 x (T2 - 303)
0.05 = 21.6 (T2 - 303)
= 21.6 T2 - 6544.8
21.6 T2 = 6544.8 - 0.05
T2 =\(\frac { 6544.8 }{ 21.6 } \)
Final temperature, T2 = 303K
16.
Length of AI sheet, L = 30 m
Coefficient of linear expansion, Δl = 23 x 10-6 K-1
Change in temperature ΔT = 300 k
To find: Change in length ΔL =?
ΔL = L αL ΔL
= 30 x 23 x 10-6 x 300
= 2.07 x 10-1
ΔL = 0.207 m
17.
A substance that heats up quickly has a low specific heat capacity. Higher the specific heat capacity of a substance, lower is the increase in its temperature.
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