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Published on: 12/06/2021
QB365 provides detailed and simple solution for every book back questions in class 10 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
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Questions + Answers key
Take MCQ Maths Test1.
The value of (13 + 23 + 33 +...+153) - (1 + 2 + 3 +...+ 15)is
14400
14200
14280
14520
2.
If the sequence t1, t2, t3... are in A.P. then the sequence t6, t12, t18,.... is
a Geometric Progression
an Arithmetic Progression
neither an Arithmetic Progression nor a Geometric Progression
a constant sequence
3.
The next term of the sequence \(\frac { 3 }{ 16 } ,\frac { 1 }{ 8 } ,\frac { 1 }{ 12 } ,\frac { 1 }{ 18 } \), ..... is
\(\frac { 1 }{ 24 } \)
\(\frac { 1 }{ 27 } \)
\(\frac { 2 }{ 3 } \)
\(\frac { 1 }{ 81 } \)
4.
If A = 265 and B = 264 + 263 + 262 +...+ 20 Which of the following is true?
B is 264 more than A
A and B are equal
B is larger than A by 1
A is larger than B by 1
5.
In an A.P., the first term is 1 and the common difference is 4. How many terms of the A.P. must be taken for their sum to be equal to 120?
6
7
8
9
1.
(c)
14280
2.
(b)
an Arithmetic Progression
3.
(b)
\(\frac { 1 }{ 27 } \)
4.
(i) To check if h is one – one, we assume that h(b1) = h(b2)
Then we get 2.47b1 + 54.10 = 2.47 b2 + 54.10
2.47b1 = 2.47b2 ⇒ b1 = b2
Thus, h(b1) = h(b2) ⇒ b1 = b2, So, the function h is one – one.
(ii) If the length of the thigh bone b = 50, then the height is
h(50) = (2.47 x 50) + 54.10 = 177.6 cms
(iii) If the height of a person is 147.96 cms, then h(b) =147.96 and so the length of the thigh bone is given by 2.47b + 54.10 = 147.96.
b = \(\frac { 93.86 }{ 2.47 } \)
Therefore, the length of the thigh bone is 38 cms.
5.
(c)
8
10th Standard Syllabus & Materials
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards
