10th Standard Syllabus & Materials
10th Standard
TN 10th English Prose - 4 - The Attic Important Questions And Answers Study Material - QB365 Set A
NEW10th Standard
TN 10th English Supplementary - 3 - The Story of Mulan Important Questions And Answers Study Material - QB365 Set A
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TN 10th English Poem - 3 - I am Every Woman Important Questions And Answers Study Material - QB365 Set A
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TN 10th English Prose - 3 - Empowered Women Navigating The World Important Questions And Answers Study Material - QB365 Set A
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TN 10th English Supplementary - 2 - Zigzag Important Questions And Answers Study Material - QB365 Set A
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TN 10th English Poem - 2 - The Grumble Family Important Questions And Answers Study Material - QB365 Set A

Published on: 03/07/2021
QB365 provides detailed and simple solution for every Creative Questions in class 10 Maths Subject. It will helps to get more idea about question pattern in every Creative questions with solution.
Download Tamil Nadu 10th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
If tanθ+sinθ=P; tanθ-sinθ=q P.T P2-q2=4\(\sqrt{pq}\)
2.
If 15tan2 θ+4 sec2 θ=23 then find the value of (secθ+cosecθ)2 -sin2 θ
3.
If ATB=90o then prove that
\(\sqrt { \frac { tanA\quad tanB+tanA\quad cotB }{ sinA\quad secB } } -\frac { { Sin }^{ 2 }A }{ { Cos }^{ 2 }A } =tanA\)
4.
Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
5.
Evaluate \(\frac { tan{ 65 }^{ o } }{ tan{ 25 }^{ o } } \)
1.
2.
3.
4.
cot 85° + cos 75°
= cot(90° - 5°) + cos(90° - 15°)
= tan 5° + sin 15°
5.
We know:
cot A = tan(90o - A)
So,
cot 25° = tan (90° - 25°) = tan 65°
\(\frac { tan{ 65 }^{ o } }{ tan{ 25 }^{ o } } \) = \(\frac { tan{ 65 }^{ o } }{ tan{ 25 }^{ o } } \) = 1
10th Standard Syllabus & Materials
10th Standard
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards