10th Standard Syllabus & Materials
10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Population, Transport, Communication and Trade Important Questions And Answers Study Material - QB365 Set C
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Population, Transport, Communication and Trade Important Questions And Answers Study Material - QB365 Set B
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Population, Transport, Communication and Trade Important Questions And Answers Study Material - QB365 Set A
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Resources and Industries Important Questions And Answers Study Material - QB365 Set C
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Resources and Industries Important Questions And Answers Study Material - QB365 Set B
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Resources and Industries Important Questions And Answers Study Material - QB365 Set A
Published on: 13/05/2022
QB365 provides detailed and simple solution for every Creative Questions in class 10 Maths Subject. It will helps to get more idea about question pattern in every Creative questions with solution.
latest Creative QuestionsDownload Tamil Nadu 10th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
If tanθ+sinθ=P; tanθ-sinθ=q P.T P2-q2=4\(\sqrt{pq}\)
2.
If 15tan2 θ+4 sec2 θ=23 then find the value of (secθ+cosecθ)2 -sin2 θ
3.
If ATB=90o then prove that
\(\sqrt { \frac { tanA\quad tanB+tanA\quad cotB }{ sinA\quad secB } } -\frac { { Sin }^{ 2 }A }{ { Cos }^{ 2 }A } =tanA\)
4.
Express cot 85° + cos 75° in terms of trigonometric ratios of angles between 0° and 45°.
5.
Evaluate \(\frac { tan{ 65 }^{ o } }{ tan{ 25 }^{ o } } \)
1.
2.
3.
4.
cot 85° + cos 75°
= cot(90° - 5°) + cos(90° - 15°)
= tan 5° + sin 15°
5.
We know:
cot A = tan(90o - A)
So,
cot 25° = tan (90° - 25°) = tan 65°
\(\frac { tan{ 65 }^{ o } }{ tan{ 25 }^{ o } } \) = \(\frac { tan{ 65 }^{ o } }{ tan{ 25 }^{ o } } \) = 1
10th Standard Syllabus & Materials
10th Standard
Tamilnadu 10th Standard Social Science GEO - Climate and Natural Vegetation of India Important Questions And Answers Study Material - QB365 Set C
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - Climate and Natural Vegetation of India Important Questions And Answers Study Material - QB365 Set B
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - Climate and Natural Vegetation of India Important Questions And Answers Study Material - QB365 Set A
NEW10th Standard
Tamilnadu 10th Standard Social Science GEO - India - Location, Relief and Drainage Important Questions And Answers Study Material - QB365 Set B
Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards
