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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Science Test1.
A source of sound is moving with a velocity of 50 m s–1 towards a stationary listener. The listener measures the frequency of the source as 1000 Hz. what will be the apparent frequency of the source when it is moving away from the listener after crossing him? (velocity of sound in the medium is 330 m s–1)
2.
A source producing a sound of frequency 90 Hz is approaching a stationary listener with a speed equal to (1/10) of the speed of sound. What will be the frequency heard by the listener?
3.
a) What do you understand by the term ‘ultrasonic vibration’?
b) State three uses of ultrasonic vibrations.
c) Name three animals which can hear ultrasonic vibrations.
4.
What are the factors that affect the speed of sound in gases?
5.
Suppose that a sound wave and a light wave have the same frequency, then which one has a longer wavelength?
a) Sound
b) Light
c) both a and b
d) data not sufficient.
1.
When the source is moving towards the stationary listener, the expression for apparent frequency is
\(n'=\left( \frac { v }{ v-{ v }_{ s } } \right) n\)
\(1000=\left( \frac { 330 }{ 330-50 } \right) \times n\)
\(n=\left( \frac { 1000 \times 280 }{ 330 } \right)\)
n = 848.48 Hz
The actual frequency of the sound is 848.48 Hz. When the source is moving away from the stationary listener, the expression for apparent frequency is
\(n'=\left( \frac { v }{ v+{ v }_{ s } } \right) n\)
=\(\left( \frac { 330 }{ 330+50 } \right) \times 848.48\)
= 736.84 Hz
2.
When the source is moving towards the stationary listener, the expression for apparent frequency is
\(n'=\left( \frac { v }{ v-{ v }_{ s } } \right) n\)
= \(\left( \frac { v }{ v-\left( \frac { 1 }{ 10 } \right) v } \right) n=\left( \frac { 10 }{ 9 } \right) n\)
= \(\left( \frac { 10 }{ 9 } \right) \times 90=100\) Hz
n'=100 Hz
3.
a) Ultrasonic Vibrations:
(i) The Vibrations produced by sound waves with a frequency greater than 20 KHz are called ultrasonic vibrations.
(ii) Human ear cannot detect these waves.
b) Uses of Ultrasonic vibration:
(i) Ultrasonic devices are used to detect objects and measure distances.
(ii) Ultrasound imaging or sonography is often used in medicine.
(iii) In the non destructive testing of products and structures. Ultra sound is used to detect invisible flaws.
c) Certain creatures like mosquitoes, dogs, bats and dolphins can detect these waves.
4.
Factors affecting velocity of sound:
(i) The following factors affect the velocity of sound waves.
Effect of density:
(i) The velocity of sound in a gas is inversely proportional to the square root of the density of the gas.
(ii) Hence, the velocity decreases as the density of the gas increases.
\(V \propto \frac{1}{\sqrt{d}}\)
Effect of temperature:
(i) The velocity of sound in a gas is directly proportional to the square root of its temperature.
(ii) The velocity of sound in a gas increases with the increase in temperature. \(v \propto \sqrt{\mathrm{T}}.\)
(iii) Velocity at temperature T is given by the following equation:
\(\mathrm{v}_{\mathrm{T}}=\left(\mathrm{v}_{0}+0.61 \mathrm{~T}\right) \mathrm{m} \mathrm{s}^{-1}\)
(i) Here, vo is the velocity of sound in the gas at \(0^{\circ} \mathrm{C}\).
(ii) For air, \(\mathrm{v}_{\mathrm{o}}=331 \mathrm{~m} \mathrm{~s}^{-1}\).
(iii) Hence, the velocity of sound changes by 0.61 ms-1 when the temperature changes by one degree celsius.
Effect of relative humidity:
(i) When humidity increases, the speed of sound increases.
(ii) That is why you can hear sound from long distances clearly during rainy seasons.
5.
b) Light
The light wave has a longer wave length. Because, it has much greater speed.
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