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Published on: 04/07/2021
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Questions + Answers key
Take MCQ Science Test1.
A flask P contains 0.5 g mole of oxygen gas. Another flask Q contains 0.4 mole of ozone gas. Which of the two flasks contains greater number of oxygen atoms?
2.
Calculate the abundance of C-12 and C-13 are 98.90% and 1.10% respectively.
3.
Define average atomic mas of an element.
4.
Define RAM.
5.
Define Mass number.
1.
1 molecule of oxygen (O2) = 2 atoms of oxygen
1 molecule of ozone (O3) = 3 atoms of oxygen
In flask P:
1 mole of oxygen gas = 6.022 x 1023 molecules
0.5 mole of ozone gas = 6.022 x 1023 x 0.5 molecules
= 6.022 x 1023 x 0.5 x 2 atoms
= 6.022 x 1023 atoms
In flask Q:
1 mole of ozone gas = 6.022 x 1023 molecules
0.4 mole of ozone gas = 6.022 x 1023 x 0.4 molecules
= 6.022 x 1023 x 0.4 x 3 atoms
= 7.23 x 1023 atoms
∴ Flask Q has a greater number of oxygen atoms as compared to flask P.
2.
Average atomic mass of Carbon \(=12 \times\left(\frac{98.9}{100}\right)+13 \times\left(\frac{1.1}{100}\right)\)
=12 x 0.989 + 13 x 0.011
=11.868 + 0.143
=12.011 amu.
3.
The average atomic mass of an element in the weighted average of the masses of its naturally occurring isotopes.
Average atomic mass = (Mass of 1st Isotope x % abundance of 1st Isotope)+
(Mass of 2nd Isotope x % abundance of 2nd Isotope).
4.
Relative atomic mass of an element is the ratio between the average mass of its isotopes to 1/12th part of the mass of a Carbon-12 atom. It is denoted as A. It is otherwise called as Standard Atomic Weight.
AR = \(\frac{Average \ mass \ of \ the \ Isotopes \ of \ the \ element}{1/12th \ of \ the \ mass \ of \ one \ carbon \ atom}\)
5.
The sum of the number of protons and neutrons of an atom is called its mass number.
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards