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Published on: 05/07/2021
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Questions + Answers key
Take MCQ Science Test1.
An electric heater works for 30 min at 120 V and takes energy of 1 - 2 kwh. What is the current drawn by the heater?
2.
The potential difference between two conductor is 110 V. How much work in moving 5 C charge from one conductor to the other?
3.
The amount of work done to move 20C charge from one point to another is 2201. What is the potential difference between these two points?
4.
A current of 6 A flows through metal wire. How many coulombs of charge pass through the wire in 2 miniatures?
5.
100 W bulb draws 680 mA current. How much time will be required to pass 30 C of charge through the bulb?
1.
Electrical energy,
E = 1.2 kwh = 1.2 x 103 wh
Time, t =30 min\(\frac{1}{2}\) hour
To find: Current drawn by the heater, I = ?
Solution
Energy, E = Vlt \(\therefore I=\frac { E }{ Vt } \)
\(I=\frac { 1.2\times { 10 }^{ 3 }\times 2 }{ 120 } =20A\)
Current, I = 20A
2.
Given :
Potential difference, V = 110 V
Charge, q = 5 C
To find: Work done, W = ?
Solution
\(V=\frac { W }{ q } \therefore q\times V=W\)
W= 5 x 110 = 550 J
Work, W = 550J
3.
Given:
Amount work done W = 220 J
Quantity of charge q = 20 C
To find : Potential difference between
two points, V = ?
Solution :
\(V=\frac { W }{ q } =\frac { 220 }{ 20 } \)
=11V
Voltage, V = 11 volt
4.
Current flowing through the wire, I = 6 A
Time taken, t = 2 miniatures = 2 x 60 = 120 S
To find : Amount of charge passing
through wire, q = ?
Solution
\(I=\frac { q }{ t } \Rightarrow =6\times 120=720C\)
Charge, q = 720 C
5.
Given :
Charge passing through bulb, q = 30C
Current drawn by 100 W bulb, I = 680 x 10-3 A
To find: Time taken to pass
through the bulb t =? t=\(\frac{q}{I}\)
Solution :
\(I=\frac { q }{ t } =\frac { 30 }{ 680\times { 10 }^{ -3 } } \)
=441.173
Time required, t =7.35 min
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards
