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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Science Test1.
If the loss in mass during a fission reaction is 0.20 g, how much energy will have been produced?
2.
Three hundred and fifty atoms of Ur-235 split. If 2.9 x 10-8 J of energy is released from each atom when fission occurs. What nuclear mass was converted into energy?
3.
If the following quantity of energy was released during fission, determine the loss in mass that would result.
(a) 8.5 x 1014 J
(b) 2.9 x 1017 J
4.
If 50 g was the loss in mass as a result of a fissionable r x n, how much energy was released?
5.
Determine the energy produced in the fission reaction whose mass difference is 3.251 x 10-28 kg.
1.
Given
Loss in mass, m = 0.20 g = 2 x 10-4 kg
To find: E = mc2
Solution
E = 2 x 10-4 x (3 x 108)2
E = 1.8 x 1013J
2.
Given
The energy released from one atom = 2.9 x 10-8 J
For 350 atoms, E = 2.9 x 10-8 x 350
To find: mass, m = ?
E = mc2,
\(m=\frac { E }{ { c }^{ 2 } } =\frac { 2.9\times { 10 }^{ 8 }350 }{ { ({ 3\times 10 }^{ 8 }) }^{ 2 } } \)
mass, m=1.13 x 10-22kg
3.
(a) Given
The energy released E = 8.5 x 1014 J
To find: Loss in mass, m = ?
Solution
\(m=\frac { E }{ { c }^{ 2 } } =\frac { 8.5\times { 10 }^{ 14 } }{ { ({ 3\times 10 }^{ 8 }) }^{ 2 } } \)
m = 9.4 x 10-3 kg
(b) Given
Energy released E = 2.9 x 1017 J
To find: Loss in mass, m =?
Solution
\(m=\frac { E }{ { c }^{ 2 } } =\frac { 2.9\times { 10 }^{ 17 } }{ { ({ 3\times 10 }^{ 8 }) }^{ 2 } } \)
= 3.2 kg
4.
Loss in mass, m = 50 g = 0.05 kg
Energy, E = mc2
= 0.05 x 3 x 108
Energy, E = 4.5 x 10-11 J
5.
Given
Mass defect = Difference in actual mass and mass of the product
∆m = 3.251 x 10-28 kg
Velocity of light, c = 3 x 108 ms-1
To find: Energy, E = ∆mc2 = ?
Solution
E = 3.251 x 10-28 x (3 x 108)2
E = 2.93 x 10-11J
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards
