10th Standard Syllabus & Materials
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TN 10th English Prose - 4 - The Attic Important Questions And Answers Study Material - QB365 Set A
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TN 10th English Prose - 3 - Empowered Women Navigating The World Important Questions And Answers Study Material - QB365 Set A
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Published on: 04/12/2020
10th Standard Mathematics Numbers and Sequences English Medium Free Online Test 1 Mark Questions 2020-2021
Download Tamil Nadu 10th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
If p, q, r, x, y, z are in A.P, then 5p + 3, 5r + 3, 5x + 3, 5y + 3, 5z + 3 form ____________
a G.P
an A.P
a constant sequence
neither an A.P nor a G.P
2.
3.
Sum of infinite terms of G.P is 12 and the first term is 8. What is the fourth term of the G.P?
\(\frac { 8 }{ 27 } \)
\(\frac { 4 }{ 27 } \)
\(\frac { 8 }{ 20 } \)
\(\frac { 1 }{ 3 } \)
4.
How many terms are there in the G.P : 5, 20, 80, 320,..., 20480
5
6
7
9
5.
The first term of an A.P. whose 8th and 12th terms are 39 and 59 respectively is ____________
5
6
4
3
6.
44 ≡ 8 (mod12), 113 ≡ 85 (mod 12), thus 44 x 113 ≡______(mod 12):
4
3
2
1
7.
If 3 is the least prime factor of number 'a' and 7 is least prime factor of number 'b', then the least prime factor of a + b is ____________
a + b
2
5
10
8.
If a and b are the two positive integers when a > b and b is a factor of a then HCF (a, b) is ____________
b
a
ab
\(\frac { a }{ b } \)
9.
If the sequence t1, t2, t3... are in A.P. then the sequence t6, t12, t18,.... is
a Geometric Progression
an Arithmetic Progression
neither an Arithmetic Progression nor a Geometric Progression
a constant sequence
10.
If A = 265 and B = 264 + 263 + 262 +...+ 20 Which of the following is true?
B is 264 more than A
A and B are equal
B is larger than A by 1
A is larger than B by 1
11.
An A.P. consists of 31 terms. If its 16th term is m, then the sum of all the terms of this A.P. is
16 m
62 m
31 m
\(\frac { 31 }{ 2 } \) m
12.
The first term of an arithmetic progression is unity and the common difference is 4. Which of the following will be a term of this A.P.
4551
10091
7881
13531
13.
74k \(\equiv \) ________ (mod 100)
1
2
3
4
14.
The sum of the exponents of the prime factors in the prime factorization of 1729 is
1
2
3
4
15.
Using Euclid’s division lemma, if the cube of any positive integer is divided by 9 then the possible remainders are
0, 1, 8
1, 4, 8
0, 1, 3
0, 1, 3
1.
(b)
an A.P
2.
(c)
3.
(a)
\(\frac { 8 }{ 27 } \)
4.
(c)
7
5.
(c)
4
6.
(a)
4
7.
(b)
2
8.
(a)
b
9.
(b)
an Arithmetic Progression
10.
(i) To check if h is one – one, we assume that h(b1) = h(b2)
Then we get 2.47b1 + 54.10 = 2.47 b2 + 54.10
2.47b1 = 2.47b2 ⇒ b1 = b2
Thus, h(b1) = h(b2) ⇒ b1 = b2, So, the function h is one – one.
(ii) If the length of the thigh bone b = 50, then the height is
h(50) = (2.47 x 50) + 54.10 = 177.6 cms
(iii) If the height of a person is 147.96 cms, then h(b) =147.96 and so the length of the thigh bone is given by 2.47b + 54.10 = 147.96.
b = \(\frac { 93.86 }{ 2.47 } \)
Therefore, the length of the thigh bone is 38 cms.
11.
(i) To check if h is one – one, we assume that h(b1) = h(b2)
Then we get 2.47 b1 + 54.10 = 2.47 b2 + 54.10
2.47b1 = 2.47b2 ⇒ b1 = b2
Thus, h(b1) = h(b2) ⇒ b1 = b2, So, the function h is one – one.
(ii) If the length of the thigh bone b = 50, then the height is
h(50) = (2.47 x 50) + 54.10 = 177.6 cms
(iii) If the height of a person is 147.96 cms, then h(b) = 147.96 and so the length of the thigh bone is given by 2.47b + 54.10 = 147.96.
b = \(\frac { 93.86 }{ 2.47 } \)
Therefore, the length of the thigh bone is 38 cms.
12.
(c)
7881
13.
(a)
1
14.
(c)
3
15.
(a)
0, 1, 8
10th Standard Syllabus & Materials
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards