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Published on: 21/10/2025
Download CBSE Class 11th Standard CBSE Chemistry question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 11th Standard CBSE Chemistry
Questions + Answers key
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1.
Define common ion effect.
2.
Although benzene is highly unsaturated it does not undergo addition reactions. Why?
3.
What is dry ice? Why is it so called?
4.
In Carius method, sulphur is estimated by precipitating it as which compound?
5.
What is meant by polar vortex?
6.
Why is acid rain considered as threat to Taj Mahal?
7.
Why is standard hydrogen electrode called reversible electrode?
8.
Write the general outer electronic configuration of s-, p-, d- and f- block elements.
9.
How many oxygen atoms are there in 18 g of water?
10.
Calculate the kinetic energy of 2g of oxygen at -23oC
11.
What would be IUPAC names and symbols for elements with atomic numbers 122,127,135,149 and 150?
12.
Express the following in SI unit. "5 feet 2 inch"
13.
If the concentration of glugose (C6H12O6) in blood is 0.9 g L-1, what will be the molarity of glugose blood?
14.
Convert the following into kg.
(a) "0.91 x 10-27 g( mass of electron)"
(b) "700g (mass of human DNA molecule )"
1.
The supervision in concentration of one of the ions by adding other ion as common ion is called common ion effect.
2.
It is due to delocalization of \(\pi\)-electrons in benzene it is highly stable.
3.
Carbon dioxide can be obtained as a solid in the form of dry ice by allowing the liquified CO2 to expand rapidly.
Unlike ordinary ice it does not melt and hence does not wet the surface on which it is kept. Thus it is called dry ice.
4.
BaSO4.
5.
A tight whirlpool of wind formed in the stratosphere which surrounds Antarctica is called polar vortex.
6.
Acids present in acid rain can react with marble (CaCO3) and damage the monument.
7.
A standard hydrogen electrode is called reversible electrode because it can react both as anode as well as cathode in an electrochemical cell
8.
(i) s-Block elements: ns1-2 where n = 2 - 7.
(ii) p-Block elements: ns2 np1-6 where n = 2 - 6.
(iii) d-Block elements: (n -1) d1-10nsO-2 where n = 4 - 7.
(iv) f-Block elements: (n - 2)f0-14 (n - 1) d0-1 ni where n = 6 - 7
9.
Molar mass of water is 18 g/ mol.
Number of oxygen atoms is 18 g of water = 6.02 x 1023
10.
Kinetic energy is given as \({ E }_{ k }=\frac { 3 }{ 2 } nRT\)
\(n=\frac { 2 }{ 32 } =\frac { 1 }{ 16 } mol,\)
\( R=8.314 \ JK^{ -1 }mol^{ -1 },\)
\( T=273-23=250 \ K\)
\( { E }_{ k }=\frac { 3 }{ 2 } \times \frac { 1 }{ 16 } \times 8.314\times 250=194.86J\)
11.
The roots 2,7,5,9 and 0 are referred as bi, sept, pent,enn and nil respectively. Therefore, their names and symbol are
| Z (Atomic number) | Name | Symbol |
| 122 | Unbibium | Ubb |
| 127 | Unbiseptium | Ubs |
| 135 | Untripentium | Utp |
| 149 | Unquadennium | Uqe |
| 150 | Unpentnilium | Upn |
12.
5 feet 2 inch = 1.5748 m
[\(\because \) 1 feet = 12 inch, 1m = 39.37 inch]
13.
In the given question 0.9g L-1 means that 1000 mL solution contains 0.9 g of glugose
Number of moles = 0.9g glucose = \(\frac { 0.9 }{ 180 } \)mol glugose
= \(5\times { 10 }^{ -3 }\)mol glugose.
(where molecular mass of glugose(C2H12O6) = \(12\times 6+12\times 1+6\times 16=180u)\)
i.e IL solution contains 0.05 mole glugose or the molarity of glucose is 0.005M.
14.
(a) 91 x 10-25
(b) 0.7 kg
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