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Published on: 09/10/2019
Haloalkanes and Haloarenes
Download Tamil Nadu 11th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
Compare the bond length C-X in haloarenes and C-X in haloalkanes
2.
Explain how bromo ethane reacts with
(i) alcoholic KCN
(ii) alcoholic AgCN
3.
Explain ammonolysis of haloalkanes.
4.
Write the possible isomers for the formula C4H9Cl with structures and names.
5.
Among ortho, meta and para substituted diahalobenzenes which has high melting point? Give reason with example.
6.
Enlist the applications of haloalkanes.
7.
Two isomers (A) and (B) have the same molecular formula C2H4Cl2. Compound (A) reacts with aqueous KOH gives compound (C) of molecular formula C2H4O. Compound (B) reacts with aqueous KOH gives compound(D) of molecular formula C2H6O2. Identify (A), (B), (C) and (D).
8.
A hydrocarbon C3H6 (A) reacts with HBr to form compound (B). Compound (B) reacts with aqueous potassium hydroxide to give (C) of molecular formula C3H6O.what are (A) (B) and (C). Explain the reactions.
9.
Simplest alkene (A) reacts with HCl to form compound (B).Compound (B) reacts with ammonia to form compound (C) of molecular formula C2H7N.Compound (C) undergoes carbylamine test. Identify (A), (B), and (C)
10.
An organic compound (A) with molecular formula C2H5Cl reacts with KOH gives compounds (B) and with alcoholic KOH gives compound (C). Identify (A),(B), and (C)
1.
(i) Due to this double bond character of C-X bond in haloarenes, the C-X bond length is shorter length and stronger than in haloalkanes.
(ii) Example:
2.
(i) Bromoethane reacts with alcoholic KCN to form ethyl cyanide.
\(\underset { Bromoethane }{ { CH }_{ 3 }-{ CH }_{ 2 }Br+KCN } \xrightarrow [ ]{ Alcohol } \underset { Ethyl\quad eyaine }{ { CH }_{ 3 }-{ CH }_{ 2 }CN } +KBr\)
(ii) Bromoethane reacts with alcoholic AgCN to form alkyl isocyanide
\({ CH }_{ 3 }-{ CH }_{ 2 }Br+AgCN\xrightarrow [ ]{ Alcohol } \underset { Ethyl\quad eyaine }{ { CH }_{ 3 }-{ CH }_{ 2 }NC } +AgBr\)
3.
With excess of haloalkanes, ammonia react to give primary, secondary, tertiary amines along with quarternary ammonium salt:
\(\underset { Ethyl \ bromide }{ { CH }_{ 3 }-{ CH }_{ 2 }Br+{ NH }_{ 3 } } \xrightarrow [ -HBr ]{ Alcohol } \underset { Ethylamine({ 1 }^{ 0 }) }{ { CH }_{ 3 }-{ CH }_{ 2 }{ NH }_{ 2 } } +HBr\)
4.
C4H9Cl (4 isomers):
(i) CH3-CH2-CH2-CH2Cl 1-Chlorobutane
(ii) 2-Chlorobutane
(iii) 1-Chloro-2-methylpropane
(iv) 2-Chloro-2-methylpropane
5.
The boiling points of isomeric dihalobenzene are pearly the same. The melting point of para isomer is generally higher than the melting points of ortho and meta isomers. The higher melting point of p-isomer is due to its symmetry which leads to more close packing of its molecules in the crystal lattice and consequently strong intermolecular attractive force which requires more energy for melting. p-Dihalobenzene> o-Dichlorobenzene> m-Dichloro benzene.
6.
Uses of haloalkane :
Chloroform : As a solvent in pharmaceutical industry and for producing pesticides and drugs As an anaesthetic.
As a preservative for anatomical specimens.
Iodoform : Iodoform is used as an antiseptic for dressing wounds.
Carbon tetrachloride : Carbon tetrachloride is used as dry cleaning agent. It is used as a solvent for oils, fats and waxes. As the vapour of CCl4 is non - combustible, it is used under the name pyrene for extinguishing the fire in oil or petrol.
7.
\(\overset { \underset { | }{ Cl } }{ \underset { \overset { | }{ Cl } }{ CH } } -{ CH }_{ 3 }\quad (A)\) 1, 1,-dichloro ethane
\(\underset { \overset { | }{ Cl } }{ { CH }_{ 2 } } -\underset { \overset { | }{ Cl } }{ { CH }_{ 2 } } \) (B) 1, 2, dichloro ethane
\(\overset { \underset { | }{ Cl } }{ \underset { \overset { | }{ Cl } }{ CH } } -{ CH }_{ 3 }\underset { aq\quad KOH }{ \longrightarrow } \left[ \overset { \underset { | }{ OH } }{ \underset { \overset { | }{ OH } }{ CH } } -{ CH }_{ 3 } \right] \underset { -{ H }_{ 2 }) }{ \longrightarrow } { CH }_{ 3 }CHO\)
(A) (C)
1, 1, dichloro ethane Acetaldhyde
\(A \ \ \overset { \underset { | }{ Cl } }{ \underset { \overset { | }{ Cl } }{ CH } } -{ CH }_{ 3 }\) -1,1 dichloro ethane
B \(\underset { \overset { | }{ Cl } }{ { CH }_{ 2 } } -\underset { \overset { | }{ Cl } }{ { CH }_{ 2 } } \)-1, 2 dichloro ethane
C CH3CHO -Acetaldehyde
D \(\underset { \overset { | }{ OH } }{ { CH }_{ 2 } } -\underset { \overset { | }{ OH } }{ { CH }_{ 2 } } \)-Ethyleneglycol
8.

9.
CH2 =CH2 +HCI⟶CH3 -CH2CI
(A) (B)
Ethene Chloroethane
CH3CH2CI+ NH3⟶CH3CH2NH2
(B) (C)
Chloroethane Ethyl amine
A CH2 =CH2 Ethene
B CH3CH2CI Chloroethane
C CH3CH2NH2 Ethylamine
10.

11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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