11th Standard Syllabus & Materials
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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Chemistry Test1.
When will be Kp < Kc? Give two example
2.
Write the Kc for the reaction CO2(g) + H2O(l) \(\leftrightharpoons \) H+(aq)+ HCO3-(aq).
3.
When will be KP < KC? Give two example
4.
Give two examples of equilibrium reactions where Kp > KC
5.
Show that KP = KC with two examples
1.
When Δng = - ve, Kp < KC
KP = Kc . (RT)Δng. If Kp = Kc . (RT)-1
KP < KC .
Examples:
2H2(g) + O2(g) ⇌ 2H20(g)
Δng= 2 - 3 = -1
KP = KC.RT-1
2SO2(g) + O2(g) ⇌ 2SO3(g)
Δng = 2 - 3 = - 1 KP= KC.(RT)-1
ஃKP
2.
H2O(l) is a pure liquid and its concentration remains constant.
So,\({ K }_{ C }=\cfrac { \left[ { H }^{ + } \right] _{ aq }\times \left[ HCO_{ 3 }^{ - } \right] _{ aq } }{ \left[ CO_{ 2 } \right] _{ g } } \)
3.
When Δng = - ve, KP< KC
KP = KC . (RT)Δng. If KP = KC . (RT)-ve
KP < KC .
Examples:
2H2 + O2(g) ⇌ 2H20(g)
△ng = 2 - 3 = -1
KP x, = Kc'. RT-1
2SO2(g) + O2(g) ⇌ 2SO3(g)
Δng= 2 - /3 = - 1 KP = KC.(RT)-1
\(\therefore\) KP
4.
KP = KC. (RT)Δng. If Δng = +ve, Kp > KC.
Examples:
(i) 2NH3(g) ⇌ N2(g) + 3H2(g)
Δng = 4 - 2 = 2 K = K (RT)2 g 'P c
(ii) PCI5(g) ⇌ PCI3(g) + CI2(g)
Δng = 2 - 1 = 1 KP = KC (RT)1
So,KP > KC
5.
KP, = Kc (RT)'Δng.If Δng = 0, Kp = Kc .
Examples:
(i) H2(g) + I2(g) \(\rightleftharpoons \) 2HI(g)
Δng = 2 - 2 = 0 g
(ii) N2(g) + O2(g)\(\rightleftharpoons \) 2NO(g)
Δng= 2 - 2 = 0
11th Standard Syllabus & Materials
11th Standard
TN 11th Tamil பீடு பெற நில் - செய்யுள் - காவடிச்சிந்து Important Questions And Answers Study Material - QB365 Set A
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