Yes, a body in translatory motion shall have angular momentum unless fixed point about which angular momentum is taken lies on the line of motion of body
\(|\overrightarrow{L}|=rp sin \theta\)
= 0 only when \(\theta=0^{0} or 180^{0}\)

Mass of the sphere, m = 20 kg
Radius r = 0.25 m
Angular velocity 0 = 5 rad s^-1
Angular momentum \(L=I\omega =\frac{2}{5} mr^{2}\omega\)
\(=\frac{2}{5}\times 20 \times (0.25)^{2}\times 5 = 40 \times (0.0625)=2.5\)
L = 2.5 kg m² s^-1.

\(\overrightarrow{r}=7\hat{i}+4\hat{j}-2\hat{k}\)
\(\overrightarrow{F}=4\hat{i}-3\hat{j}+5\hat{k}\)
Torque,\(\overrightarrow{\tau}=\overrightarrow{r}\times \overrightarrow{F}\)
\(\overrightarrow{\tau}=\left| \begin{matrix} \hat { i } & \hat {j } & \hat {k } \\ 7 &4 & -2 \\ 4 & -3 & 5 \end{matrix} \right| \)
\(\overrightarrow{\tau}=\hat{i}(20-6)-\hat{j}(35+8)+\hat{k}(-21-16)\)
\(\overrightarrow {\tau}=(14\hat{i}-43\hat{j}-37\hat{k})Nm\)

Relation between angular momentum and rotational K.E.
Angular momentum, L = IW.
Rotational K.E., EK = \(\frac{1}{2}\)
\(2I={ (I\omega ) }^{ 2 }\)
\({ x }_{ k }=\frac { { L }^{ 2 } }{ 2I } \)
\(\sqrt { { E }_{ k } } =\frac { L }{ \sqrt { 2I } } \)
\(\frac { \sqrt { { E }_{ k } } }{ L } =\frac { I }{ \sqrt { 2I } } =constant\)
If I = 1, graph will be hyperbola.

Lifting a table from the floor by two persons. Pushing the car by two persons.