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Published on: 01/09/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Chemistry Subject - p - Block Elements - I, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
What are the factors responsible for the anomalous behaviour of first element the p-block.
2.
A double salt which contains fourth period alkali metal (A) on heating at 500K gives (B). Aqueous solution of (B) gives white precipitate with BaCl2 and gives a red colour compound with alizarin. Identify A and B.
3.
A hydride of 2nd period alkali metal (A) on reaction with compound of Boron (B) to give a reducing agent (C). Identify A, B and C.
4.
How will you convert boric acid to boron nitride?
5.
Write a note on metallic nature of p-block elements.
6.
Give the uses of silicones.
7.
1.
(i) In p-block elements, the first member of each group differs from the other elements of the corresponding group. The following factors are responsible for this anomalous behaviour.
(ii) Small size of the first member.
(iii) High ionisation enthalpy and high electronegativity.
(iv) Absence of d-orbitals in their valence shell.
2.
1. A double salt which contains fourth-period alkali metal (A) is potash alum
K2SO4 Al2(SO4)3 - 24 H₂O
2. On heating potash alum (A) 500 k give anhydrous potash alum (or) burnt alum (B).
\(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot 24 \mathrm{H}_{2} \mathrm{O} \stackrel{500 \mathrm{~K}}{\longrightarrow} \mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}+24 \mathrm{H}_{2} \mathrm{O}\)
[Potash alum (A)] [Burnt alum (B)]
3. Aqueous solution of burnt alum, has sulphates ion, potassium ion and aluminium ion. Sulphate ion reacts with BaCl₂ to form a white precipitate of Barium Sulphate
(SO4)2 + BaCl2 → BaSO4 + 2 Cl¯
Aluminium ion reacts with alizarin solution to give a red colour compound.
3.
A hydride of 2nd period alkali metal (A) is lithium hydride (LiH).
Lithium hydride (A) reacts with diborane (B) to give lithium borohydride (C) which is acts as a reducing agent.
B2H6 + 2 LiH \(\xrightarrow[]{ether}\) 2 LiBH4
[Diborane (B)] [Lithium hydride (A)] [Lithium borohydride (C)]
Result:
| Compound | Formula | Name |
| A | LiH | Lithium hydride |
| B | B2H6 | Diborane |
| C | LiBH4 | Lithium borohydride |
4.
Fusion of urea with B(OH)3' in an atmosphere of ammonia at 800 - 1200 K gives boron nitride.
B(OH)3 + NH3 \(\overset { \Delta }{ \longrightarrow } \) BN+ 3H2O
5.
Generally on descending a group the ionisation energy decreases and hence the metallic character increases.
6.
(i) Silicones are used for low temperature lubrication and in vacuum pumps, high temperature oil baths etc.
(ii) They are used for making water proofing clothes.
(iii) They are used as insulting material in electrical motor and other appliances.
(iv) They are mixed with paints and enamels to make them resistant towards high temperature, sunlight, dampness and chemicals.
7.
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