12th Standard Syllabus & Materials

12th Standard

TN 12th English Poem - 6 - Incident of the French Camp Sample Question Papers Study Material - QB365 Set A

NEW

12th Standard

TN 12th English Prose - 6 - On the Rule of the Road Sample Question Papers Study Material - QB365 Set A

NEW

12th Standard

TN 12th English Prose - 5 - The Chair Sample Question Papers Study Material - QB365 Set A

NEW

12th Standard

TN 12th English Supplementary - 4 - The Midnight Visitor Sample Question Papers Study Material - QB365 Set A

NEW

12th Standard

TN 12th English Poem - 4 - Ulysses Sample Question Papers Study Material - QB365 Set A

NEW

12th Standard

TN 12th English Prose - 4 - The Summit Sample Question Papers Study Material - QB365 Set A

12th Standard English Medium Chemistry Subject Carbonyl Compounds Book Back 3 Mark Questions with Solution Part - I updated Book back Questions

Published on: 13/05/2022

QB365 provides detailed and simple solution for every Book back Questions in class 12 Chemistry Subject. It will helps to get more idea about question pattern in every book back questions with solution.

latest Book back Questions

Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

Questions + Answers key

Take MCQ Chemistry Test

QB365 Student Learing Managemnet System

Std: 12th Standard - Chemistry

chapter: - Book back Questions

Visit QB365-SLMS - https://www.qb365.in/slms/ Complete Questions and Answers

Questions:

Generic 5

2 x 5 = 10

An alkene (A) on ozonolysis gives propanone and aldehyde (B). When (B) is oxidised (C) is obtained. (C) is treated with Br₂/P gives (D) which on hydrolysis gives (E). When propanone is treated with HCN followed by hydrolysis gives (E). Identify A, B, C, D and E.

Identify A, B, C and D
\(\text { ethanoic acid } \stackrel{\mathrm{SOCl}_{2}}{\longrightarrow} \mathrm{A} \stackrel{\mathrm{Pd} / \mathrm{BaSO}_{4}}{\longrightarrow} \mathrm{B} \stackrel{\mathrm{NaOH}}{\longrightarrow} \mathrm{C} \stackrel {\longrightarrow}{\triangle} \mathrm{D}\)

Generic 2

3 x 2 = 6

A carbonyl compound A having molecular formula C₅H₁₀O forms crystalline precipitate with sodium bisulphate and gives positive iodoform test. A does not reduce Fehling solution. Identify A.

What is the action of HCN on
(i) propanone
(ii) 2,4-dichlorobenzaldehyde
iii) ethanal

How will you convert benzaldehyde into the following compounds?
(i) benzophenone
(ii) benzoic acid
(iii) α-hydroxyphenylaceticacid.

Visit QB365-SLMS - https://www.qb365.in/slms/

Answers Key:

Generic 5

2 x 5 = 10

Compound	Name
A	Acetylchloride
B	Acetaldehyde
C	3 - Hydroxy butanal
D	Crotonaldehyde

Generic 2

3 x 2 = 6

An carbonyl compound having molecular formula C₅H₁₀O giving positive iodoform test. It does not reduce Fehling solution.So it is 2- pentanone.

∴ (A) is 2-pentanone.