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12th Standard English Medium Physics Subject Ray Optics Creative 2 Mark Questions with Solution Part - II

Published on: 18/06/2021

QB365 provides detailed and simple solution for every Creative Questions in class 12 Physics Subject. It will helps to get more idea about question pattern in
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Std: 12th Standard - Physics

chapter: - Creative Questions

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Questions:

Generic 2

5 x 2 = 10

A lens whose radii of curvature are different is forming the image of an object placed on its axis. If the surfaces of the lens facing the object and image are interchanged will the position of the image change?

The image of an object formed by a lens on the screen is not in sharp focus. Suggest a method to get a dear focussing of the image on the screen without disturbing the positions of the object, the lens or the screen.

For the same angle of incidence, the angles of refraction in media P, Q and R are 35°, 25°, 15° respectively. In which medium will the velocity of light be minimum?

The image of a candle formed by a convex lens is obtained on a screen. Will full size of the image be obtained if the lower half of the lens is painted completely opaque?

How does the angular separation between fringes in single-slit diffraction experiment change when the distance of separation between the slit and screen is doubled?

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Answers Key:

Generic 2

5 x 2 = 10

No, we know that
\(\cfrac { 1 }{ f } \left( { \mu }_{ 2 }-1 \right) \left( \cfrac { 1 }{ { R }_{ 1 } } -\cfrac { 1 }{ { R }_{ 2 } } \right) \)
When we interchange R and R, the value of f does not change except for the sign. So, the image will be formed at the same position.

For getting a sharp image, we have to use light of suitable wavelength. This is because focal length of a lens depends upon wavelength.

\(\\ \mu =\cfrac { c }{ v } =\cfrac { sini }{ sinr } \)
It follows that: v of sin r Since r is minimum in medium R, therefore, sin r and hence the velocity of light is minimum in medium R.

The full size of the image will be obtained. But the intensity of image will be reduced. This is because the number of rays of light refracted through different parts of the lens will be reduced.

Angular separation is \(\\ \theta =\cfrac { \beta }{ D } =\cfrac { D\frac { \lambda }{ d } }{ D } =\cfrac { \lambda }{ d } \)
Since θ is independent of D, angular separation would remain same.