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12th Standard English Medium Physics Subject Ray Optics Creative 3 Mark Questions with Solution Part - I

Published on: 18/06/2021

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Std: 12th Standard - Physics

chapter: - Creative Questions

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Questions:

Generic 3

5 x 3 = 15

The image of a candle is formed by a convex lens on a screen. The lower half of the lens is painted black to make it completely opaque. Draw the ray diagram to show the image formation. How will this image be different from the one obtained when the lens is not painted black?

An object is placed at the principal focus of a convex lens. Determine the position of the image making use of the lens equation.

Define refractive index of a medium.

What is focus (or) focal point of a mirror?

Write the conditions for nature of objects and images.

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Answers Key:

Generic 3

5 x 3 = 15

The full size of the image will be obtained. But the intensity of image will be reduced. This is because the number of rays of light refracted through different parts of the lens will be reduced.
.

From the lens equation
\(\cfrac { 1 }{ v } -\cfrac { 1 }{ -f } =\cfrac { 1 }{ f } \)
or \(\cfrac { 1 }{ v } =0\)
∴v = ∞
So, the image is formed at infinity.

Refractive index of a transparent medium is defined as the ratio of speed of light in vacuum (or air) to the speed of light in that medium refractive index n of a medium.
= \(\cfrac { speed\ of lightin\ vacuum\left( c \right) }{ speed\ of \ light\ inmedium\left( v \right) } \)

(i) When light rays incident on a spherical mirror, after reflection, the rays converge at a point on the principal axis for concave mirror or appear to diverse from a point for convex Mirror.
(ii) This point is called the focus or focal point (F) of the mirror.

	Nature of object image	Condition
(i)	Real Image	Rays actually converge at the image.
(ii)	Virtual Image	Rays appear to diverge from the image
(iii)	Real Object	Rays actually diverge from the object
(iv)	Virtual Object	Rays appear to converge at the object.