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Published on: 05/11/2020
12th Standard Maths Application of Differential Calculus English Medium Free Online Test One Mark Questions 2020 - 2021
Download Tamil Nadu 12th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
\(\underset { x\rightarrow 0 }{ lim } \frac { x }{ tanx } \) is _________
1
-1
0
∞
2.
The function -3x+12 is ________ function on R.
decreasing
strictly decreasing
increasing
strictly increasing
3.
If the slope of the curve 2y2 = ax2+b at (1,-1) is - 1, then the values of a, b is __________
2, 0
0, 2
0, 0
2, 2
4.
The angle made by any tangent to the curve y = x5 + 8x + 1 with the X-axis is a __________
obtuse
right angle
acute angle
no angle
5.
The least value of a when f f(x) = x2 + ax + 1 is increasing on (1, 2) is __________
-2
2
1
-1
6.
If a particle moves in a straight line according to s = t3-6t2-15t, the time interval during which the velocity is negative and acceleration is positive is __________
2 < t < 5
2 ≤ t ≤ 5
t ≥ 2
t ≤ 2
7.
One of the closest points on the curve x2 - y2 = 4 to the point (6, 0) is
(2,0)
\(\left( \sqrt { 5 } ,1 \right) \)
\(\left( 3,\sqrt { 5 } \right) \)
\(\left( \sqrt { 13 } ,-\sqrt { 3 } \right) \)
8.
The number given by the Rolle's theorem for the functlon x3 - 3x2, x ∈ [0, 3] is
1
\(\sqrt { 2 } \)
\(\frac { 3 }{ 2 } \)
2
9.
The slope of the line normal to the curve f(x) = 2cos 4x at \(x=\cfrac { \pi }{ 12 } \) is
\(-4\sqrt { 3 } \)
-4
\(\cfrac { \sqrt { 3 } }{ 12 } \)
\(4\sqrt { 3 } \)
10.
The volume of a sphere is increasing in volume at the rate of 3 πcm3 / sec. The rate of change of its radius when radius is \(\frac { 1 }{ 2 } \) cm
3 cm/s
2 cm/s
1 cm/s
\(\cfrac { 1 }{ 2 } cm/s\)
1.
(a)
1
2.
(b)
strictly decreasing
3.
(a)
2, 0
4.
(c)
acute angle
5.
(a)
-2
6.
(a)
2 < t < 5
7.
(c)
\(\left( 3,\sqrt { 5 } \right) \)
8.
(d)
2
9.
Given equation of the curve is y = 1 + x3 and the line is x + 12y = 12
Slope of the tangent to the curve
m1 = \(\frac { dy }{ dx } \) = 3x2 and the
Slope of the line = m2
= \(\frac{-1}{2}\) \(\left[ \because m=\frac { co-efficient\quad of\quad x }{ co-efficient\quad of\quad y } \right] \)
Since the slope of the tangent to the curve and the line are orthogonal, m1 m2 = - 1.
∴ 3x2\(\left( \frac { -1 }{ 2 } \right) \) = -1
⇒ \(\frac{x^2}{4}\) = 1
⇒ x2 = 4
⇒ x = ±2
When x = 2, y = 1 + 23 = 9
When x = -2, y = 1+ (-2)3
= 1-8 = -7
∴ Equation of the tangent at (2, 9) is
y-9 = 12(x-2) [∵ m1 = 3x2 = 3(2)2 = 12]
∴ y - 9 = 12x - 24
∴ 12x - y = 15
Equation of the tangent at (-2, -7) is
y + 7= 12(x + 2)
⇒ y + 7 = 12x + 24
⇒ 12x - y = -17
10.
(a)
3 cm/s
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Computer Applications

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