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Published on: 02/09/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Maths Subject - Differentials and Partial Derivatives, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
Download Tamil Nadu 12th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
2.
If w (x, y, z) = x2 (y - z) + y2 (z - x) + z2(x - y), then \(\frac { { \partial }w }{ \partial x } +\frac { \partial w }{ \partial y } +\frac { \partial w }{ \partial z } \) is
xy + yz + zx
x(y + z)
y(z + x)
0
3.
Linear approximation for g(x) = cos x at \(x=\frac{\pi}{2}\) is
\(x+\frac{\pi}{2}\)
\(-x +\frac{\pi}{2}\)
\(x - \frac{\pi}{2}\)
\(-x - \frac{\pi}{2}\)
4.
If u(x, y) = x2+ 3xy + y - 2019, then \(\left.\frac{\partial u}{\partial x}\right|_{(4,-5)}\) is equal to
-4
-3
-7
13
5.
If \(f(x)=\frac{x}{x+1}\), then its differential is given by
\(\frac { -1 }{ ({ x+1) }^{ 2 } } dx\)
\(\frac { 1 }{ ({ x+1) }^{ 2 } } dx\)
\(\frac { 1 }{ x+1 } dx\)
\(\frac {- 1 }{ x+1 } dx\)
6.
If \(g(x, y)=3 x^{2}-5 y+2 y^{2}, x(t)=e^{t}\) and y(t) = cos t, then \(\frac{dg}{dt}\) is equal to
6e2t + 5 sin t - 4 cos t sin t
6e2t- 5 sin t + 4 cos t sin t
3e2t+ 5 sin t + 4 cos t sin t
3e2t - 5 sin t + 4 cos t sin t
7.
The approximate change in the volume V of a cube of side x metres caused by increasing the side by 1% is
0.3xdx m3
0.03x m3
0.03x2 m3
0.03x3 m3
8.
The change in the surface area S = 6x2 of a cube when the edge length varies from xo to xo+ dx is
12 xo+dx
12xo dx
6xo dx
6xo+ dx
9.
If we measure the side of a cube to be 4 cm with an error of 0.1 cm, then the error in our calculation of the volume is
0.4 cu.cm
0.45 cu.cm
2 cu.cm
4.8 cu.cm
10.
If f (x, y) = exy then \(\frac { { \partial }^{ 2 }f }{ \partial x\partial y } \) is equal to
xyexy
(1 +xy)exy
(1 +y)exy
(1 + x)exy
11.
If w (x, y) = xy, x > 0, then \(\frac { \partial w }{ \partial x } \) is equal to
xy log x
y log x
yxy-1
x log y
12.
If v (x, y) = log (ex + ey), then \(\frac { { \partial }v }{ \partial x } +\frac { \partial v }{ \partial y } \) is equal to
ex + ey
\(\frac{1}{e^x + e^y}\)
2
1
13.
If \(u(x, y)=e^{x^{2}+y^{2}}\),then \(\frac { \partial u }{ \partial x } \) is equal to
\(e^{x^{2}+y^{2}}\)
2xu
x2u
y2u
14.
The percentage error of fifth root of 31 is approximately how many times the percentage error in 31?
\(\frac{1}{31}\)
\(\frac15\)
5
31
15.
A circular template has a radius of 10 cm. The measurement of radius has an approximate error of 0.02 cm. Then the percentage error in calculating area of this template is
0.2%
0.4%
0.04%
0.08%
1.
(b)
2.
(d)
0
3.
(b)
\(-x +\frac{\pi}{2}\)
4.
(c)
-7
5.
(b)
\(\frac { 1 }{ ({ x+1) }^{ 2 } } dx\)
6.
(a)
6e2t + 5 sin t - 4 cos t sin t
7.
\({ f }_{ y }=\frac { 1 }{ 1+\frac { { x }^{ 2 } }{ { y }^{ 2 } } } \left( \frac { -x }{ { y }^{ 2 } } \right) =\frac { -\frac { x }{ { y }^{ 2 } } }{ \frac { { x }^{ 2 }+{ y }^{ 2 } }{ { { x }{ x }^{ 2 } } } } \)
= \(\frac { -x }{ { x }^{ 2 }+{ y }^{ 2 } } \)
\({ f }_{ x }=\frac { 1 }{ 1+\frac { { x }^{ 2 } }{ { { y }^{ 2 } } } } \left( \frac { 1 }{ y } \right) =\frac { \frac { 1 }{ y } }{ \frac { { x }^{ 2 }+{ y }^{ 2 } }{ { { y }^{ 2 } } } } \)
\(=\frac { y }{ { { x }^{ 2 }+{ y }^{ 2 } } } \)
\({ f }_{ xy }=\frac { \partial }{ \partial x } ({ f }_{ y })\)
\({ f }_{ xy }=-\left[ \frac { { (x }^{ 2 }+{ y }^{ 2 })(1)-x{ (2x) } }{ { ({ x }^{ 2 }+{ y }^{ 2 }) }^{ 2 } } \right] \)
\(=-\left[ \frac { { x }^{ 2 }+{ y }^{ 2 }-2{ x }^{ 2 } }{ { ({ x }^{ 2 }+{ y }^{ 2 }) }^{ 2 } } \right] \)
\(=-\left[ \frac { { y }^{ 2 }-{ x }^{ 2 } }{ { ({ x }^{ 2 }+{ y }^{ 2 }) }^{ 2 } } \right] \)
\(=\frac { x^{ 2 }-{ y }^{ 2 } }{ { ({ x }^{ 2 }+{ y }^{ 2 }) }^{ 2 } } \) ...(1)
\({ f }_{ xy }=\frac { \partial }{ \partial y } ({ f }_{ x })\)
\({ f }_{ xy }=\frac { ({ x }^{ 2 }+{ y }^{ 2 })(1)-y(2y) }{ ({ x }^{ 2 }+{ { y }^{ 2 }) }^{ 2 } } \)
\(=\frac { { x }^{ 2 }+{ y }^{ 2 }-2{ y }^{ 2 } }{ ({ x }^{ 2 }+{ { y }^{ 2 }) }^{ 2 } } \)
\(=\frac { { x }^{ 2 }-{ y }^{ 2 } }{ ({ x }^{ 2 }+{ { y }^{ 2 }) }^{ 2 } } \) ...(2)
∴ From (1) and (2), fxy = fyz
8.
(b)
12xo dx
9.
(d)
4.8 cu.cm
10.
(b)
(1 +xy)exy
11.
(c)
yxy-1
12.
(d)
1
13.
(b)
2xu
14.
(b)
\(\frac15\)
15.
(b)
0.4%
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