(a) 361
(b) 441.

1, 0

Rs 2160

We have, 968 x 73 + 968 x 27
       = 968 (73 + 27) [taking 968 as common term]
       = 968 x 100 = 96800.

According to the patterns of whole number,

If we multiply 0 by itself, it gives same number
i.e. 0 x 0 = 0, and similarly, 1 x 1 = 1.
\(\therefore\) The required whole numbers are 0 and 1.

Largest 3-digit number = 999 and smallest 4-digit number = 1000
\(\therefore\) Product = 999 x 1000 = 999000.

We start from 10, make 3 jumps to the left, we reach at 7.

So, 10 - 3 = 7.

We start from 5, make 2 jumps to the right, we reach at 7.

So, 5 + 2 = 7.

We know that, successor is one more than tbe given whole number.
(a) Successor of 299 = 299 + 1 = 300
(b) Successor of 2923 = 2923 + 1 = 2924.

We know that, predecessor is one less than the given whole number.
(a) Predecessor of 96 = 96 - 1 = 95
(b) Predecessor of 9998 = 9998 - 1 = 9997.

It is clear that the next two steps will be
         123456 x 8 + 6 = 987654
and  1234567 x 8 + 7 = 9876543
Pattern of the working is given below:
                               11 + 1 = 12
                      111 + 11 + 1 = 123
            1111 + 111 + 11 + 1 = 1234
11111 + 1111 + 111 + 11 + 1 = 12345
\(\therefore\)   1 x 8 + 1 = 9 = 1+ 8 x 1
   12 x 8 + 2 = 98 = (11 + 1) x 8 + 2
123 x 8 + 3 = 987 = (111 + 11 + 1) x 8 + 3
        1234 x 8 + 4 = 9876
                           = (1111 + 111 + 11 + 1) x 8 + 4
      12345 x 8 + 5 = 98765
                           = (11111 + 1111 + 111 + 11 + 1) x 8 + 5
and the next two steps will be work as
    123456 x 8 + 6 = 987654
                           = (111111 + 11111 + 1111 + 111 + 11 + 1) x 8 + 6
   1234567 x 8 + 7 = 9876543
                           = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) x 8 + 7.

Yes, if the product of two whole numbers is zero, then one or both of them will be zero. Since, we know that the product of any whole number with zero is always zero i.e. a x 0 = 0, where a is any whole number and 0 x 0 = 0. Some examples are as follows:

There are many examples of such type. Five of them are as follows:

Whole numbers between 32 and 53 are as follows:
33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49,  50, 51 and 52.
Hence, total number of whole numbers between 32 and 53 is 20.
Alternate Method
We can find the total numbers by using (b - a) - 1.
Where, a = First number and b = Last number
Here, a = 32, b = 53
Whole numbers between 32 and 53 = (b - a) - 1
                                                    = (53 - 32) -1 [putting the values of a and b)
                                                    = 21 - 1 = 20.