Distance around a square field = 200 rods
Length of this rod = 140 cm
Total distance around a squared field
= 200 \(\times\) 140= 28000 cm
So, perimeter of this squared field
= 28000 cm= 280 m
Sides of this field = \(\frac{280}{4}\) = 70 m

1800 m

Here, length of string will be the perimeter of regular hexagon.
∴ Perimeter of regular hexagon = 30 
We know that, a regular hexagon has 6 equal sides
Perimeter of a regular hexagon = 6 \(\times\) Length of a side
\(\therefore \quad Length\quad of\quad a\quad side=\frac { Perimeter\quad of\quad a\quad regular\quad hexagon }{ 6 } \)
\(=\frac { 30 }{ 6 } cm=5cm\)
Hence, the length of each side of a regular hexagon is 5cm.

Let ABCD be a park whose lengths are BC, AD and widths are AB, CD respectively.

Here, AB = CD = 80 m and BC = DA = 150 m
Now, sum of the lengths of four sides
=AB+ BC + CD +DA
= 80 m + 150 m + 80 m + 150 m
= (80 + 150 + 80 + 150) m = 460 m
∴  Perimeter of the park = Sum of the lengths of four sides of the park =460m
Hence, the distanee eovered by Meera is 460 m.

Given, perimeter of a regular hexagon =30 cm
A regular hexagon has 6 sides.
∴ The perimeter of regular hexagon = 6 \(\times\) Length of a side
⇒30 = 6 \(\times\) Length of a side
∴ The length of a side=\(\frac{30}{6}\)=5cm
Hence, length of each side of a regular hexagon is 5 cm.

75 cm² (approx)

140 cm

The perimeter of the given figure is 20 cm.

The perimeter of the given figure is 133 cm.

Perimeter of a squared park = 4 \(\times\) Length of a side = 4 \(\times\) 60 = 240 m
Distance covered in one round = 240 m
Distance covered in three rounds = 3 \(\times\) 240 m = 720 m

Given, four regular hexagons, as shown in the figure:

Perimeter of the design = 28 cm
∴ Perimeter of the given design = Sum of all outer sides of the four hexagons.
Here, this figure has 14 outer equal sides.
∴Perimeter of the design = 14 \(\times\) Length of one side of hexagon
⇒ 28 = 14\(\times\) Length of one side of hexagon
Length of one side of hexagon=\(\frac{28}{14}=2cm\) 

Given, length of the piece of land = 5 m
and breadth of the piece of land = 4 m
Area of the piece of land = Length \(\times\) Breadth
= 5 m \(\times\) 4 m= 20 sq m
Given, side of one square flower bed = 1m
∴  Area of one square flower bed = Side \(\times\) Side
= (1m \(\times\) 1rn) = 1sq m
Then, area of 5 such flower beds = 5 \(\times\) Area of one square flower bed
= 5 \(\times\) 1sq m = 5 sq m
Now, area of the remaining part of land
= Area of the piece of land - Area of 5 square flower beds
= (20 - 5)sq m =15 sq m
Hence, the area of the remaining part of the land is 15 sq m.

Number of tiles =\(\frac { Area\quad of\quad the\quad floor }{ Area\quad of\quad one\quad tile } =\frac { 40\times 30 }{ 2\times 2 } =\frac { 1200 }{ 4 } \)
=300

Area of rectangular park = I x b = 30 x 20 = 600 sq m.

We know that, standard unit of area is cm² or m².

Diagonal of a square = \(\sqrt2\) x Side

The region enclosed by a plane closed figure is called its area.