SECOND SUMMATIVE EXAMINATION -2018 ( Answer Key )

Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

Questions:

Fill in the blanks

5 x 1 = 5

The sum of three angles of a triangle is ___________.

Every triangle has at least __________ acute angles.

20 l – 1 l 500 ml = _________l _________ml

The HCF of two successive even numbers is _______________

The numbers 29 and________ are twin primes.

Generic 2

9 x 2 = 18

If one angle of an isosceles triangle is 70°, then find the possibilities for the other two angles.

What are the angles of an isosceles right angled triangle?

I am a closed figure with each of my three angles is 60°. Who am I?

Subtract 10 hours 20 minutes 35 seconds from 12 hours 18 minutes 40 seconds

10.

A child needs 100 g of vegetables per day. How many kg of vegetables will be needed for a school of strength 90.

11.

Murali has a bag that weighs 3 kg and 450 g. What is its weight in gram?

12.

Find the HCF of each set of numbers using prime factorisation method.
(i) 18, 24 (ii) 51, 85 (iii) 61, 76 (iv) 84, 120 (v) 27, 45, 81 (vi) 45, 55, 95

13.

Find the prime factorisation of each number by factor tree method and division method.
a) 60
b) 128
c) 144
d) 198
e) 420
f) 999

14.

Your friend says that every odd number is prime. Give an example to prove him/her wrong.

Multiple Choice Question

5 x 1 = 5

15.

The given triangle is ___________

(a)

a right angled triangle

(b)

an equilateral triangle

(c)

a scalene triangle

(d)

an obtuse angled triangle

16.

Discount = M.P. - _____________

(a)

Profit

(b)

S.P.

(c)

Loss

(d)

C.P.

17.

Number of ordinary years between two consecutive leap years is _______________

(a)

4 years

(b)

2 years

(c)

1 year

(d)

3 years

18.

9 m 4 cm is equal to ____________

(a)

94 cm

(b)

904 cm

(c)

9.4 cm

(d)

0.94 cm

19.

The only even prime number is

(a)

(b)

(c)

(d)

Generic 3

10 x 3 = 30

20.

Convert '5a' into Tree diagram

21.

Convert the tree diagram into numerical expression.

22.

Convert into a Tree diagram (9\(\times\)5) + (10\(\times\)12)

23.

Valarmathi sold her pearl set for Rs. 30,000 at profit of Rs. 5000. Find the cost price of the pearl set.

24.

Somu bought a second hand bike for Rs. 28,000 and spent Rs. 2,000 on its repair. He sold it for Rs. 30,000. Find his profit or loss.

25.

A table is bought for Rs. 4500 and sold for Rs. 4800. Find the profit or loss.

26.

Convert the following:
(i) 20 minutes into seconds
(ii) 5 hours 35 minutes 40 seconds into seconds
(iii) 3 ½ hours into minutes
(iv) 580 minutes into hours
(v) 25200 seconds into hours

27.

Mala's date of birth is 20-11-1999. What is her age on 05-10-2018?

28.

In a school, 200 litres of lemon juice is prepared. If 250 ml lemon juice is given to each student, how many students get the juice?

29.

Find the HCF of the numbers 40 and 56 by division method.

Generic 5

4 x 5 = 20

30.

Draw a line segment AB = 6.5 cm and mark a point M above it. Through M draw a line parallel to AB.

31.

Construct a line perpendicular to the given line through a point above it.

32.

Two angles of the triangles are given. Find the third angle.
(i) 80°, 60°
(ii) 75°, 35°
(iii) 52°, 68°
(iv) 50°, 90°
(v) 120°, 30°
(vi) 55°, 85°

33.

Can a triangle be formed with the following sides? If yes, name the type of triangle.
(i) 8 cm, 6 cm, 4 cm
(ii) 10 cm, 8 cm, 5 cm
(iii) 6.2 cm, 1.3 cm, 3.5 cm
(iv) 6 cm, 6 cm, 4 cm
(v) 3.5 cm, 3.5 cm, 3.5 cm
(vi) 9 cm, 4 cm, 5 cm

True or False

5 x 1 = 5

34.

Vanmathi bought 4 books each weighing 500 g. Total weight of 4 books is 2 kg.

(a)

True

(b)

False

35.

Meena bought 250 ml of buttermilk which is equal to 2.5 l.

(a)

True

(b)

False

36.

The HCF of 17 and 18 is 1

(a)

True

(b)

False

37.

The number of distinct prime factors of 105 is 3.

(a)

True

(b)

False

38.

If a number is divisible by 6, then it must be divisible by 3.

(a)

True

(b)

False

Visit QB365-SLMS - https://www.qb365.in/slms/

Answers Key:

Fill in the blanks

5 x 1 = 5

()
180°

()
two

()
18 l 500 ml

()
31

Generic 2

9 x 2 = 18

Given
One angle of an isoceles triangle is 70.
Two angles are same.
Therefore the possibilities for the other two angles are 70, 40 (or) 55, 55.

Isoceles right angled Triangle
Two angles are equal and one angle is right angle.
Therefore the three angles are 45^o, 45^o, 90^o.

All angles are equal.
I am an equilateral triangle.

Therefore Answer is 1 hour 58 min 5 secs

10.

Total strength of the school = 90
Weight of vegetables for each child per day = 100 g
Total weight of vegetables for 90 children per day = 90 \(\times\) 100 g
= 9000 g
= 9 kg vegetables need per day.

11.

weight of Murali's bag = 3 kg and 450 g ,
= (3 \(\times\) 1000 g) + 450 g 1 Kg = 1000 g
= 3000 g + 450 g
= 3450 g

12.

i) 18, 24

Therefore HCF = 2 \(\times\) 3 = 6
ii) 51, 85

Therefore HCF = 17
iii) 61, 76

Therefore HCF = 1
iv) 84, 120

Therefore HCF = 3 \(\times\) 2 \(\times\) 2 = 12
v) 27, 45, 81

Therefore HCF = 3 \(\times\) 3 = 9
vi) 45, 55, 95

Therefore HCF = 5

13.

a) 60
i) Division method:

Therefore 60 = \(2 \times 2 \times 3 \times 5\)
(ii) Factor Tree method:

b) 128
i) Division method:

Therefore 128 = \(2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2\)
(ii) Factor Tree method:

Therefore 128 = \(2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2\)
c) 144
i) Division method:

Therefore 144 = \(2\times 2 \times 2 \times 2 \times 3 \times 3\)
ii) Factor Tree method:

Therefore 144 = \(2 \times 2 \times 2 \times 2 \times 3 \times 3 .\)
d) 198
i) Division method:

Therefore 144 = \(2 \times 3 \times 3 \times 11\)
ii) Factor Tree method:

Therefore 144 = \(2 \times 3 \times 3 \times 11\)
e) 420
i) Division method:

Therefore 420 = \(2 \times 2 \times 3 \times 5 \times 7\)
ii) Factor Tree method.

Therefore 420 = \(2 \times 2 \times 3 \times 5 \times 7\)
f) 999
i) Division method:

Therefore 999 = \(3 \times 3 \times 3 \times 37\)
ii) Factor Tree method:

Therefore 999 = \(3 \times 3 \times 3 \times 37\)

14.

Answer : Given statement is false.
Example : Let the odd number be 9.
9 is an odd number, but not prime.
Therefore, every odd number is not prime.

Multiple Choice Question

5 x 1 = 5

15.

(b)
an equilateral triangle

16.

(b)
S.P.

17.

(d)
3 years

18.

(b)
904 cm

19.

Generic 3

10 x 3 = 30

20.

21.

Tree diagram

Numerical Expression 15-(6+9).

22.

23.

Given
Valarmathi sold her pearl set
s.p = Rs. 30,000
profit = Rs. 5,000
c.p = s.p - profit
= 30,060 - 5,000
c.p = Rs. 25,000

24.

Somu bought a bike =Rs. 28,000
He spent = 2,000
c.p = Rs. 30,000
s.p = Rs. 30,000
Therefore s.p = c.p
Therefore No profit / No loss

25.

C.P. = Rs. 4500
S.P. = Rs. 4800
Here, C.P. < S.P. \(\Rightarrow\) Profit = S.P. - C.P.
= Rs. 4800 - Rs. 4500 = Rs. 300

26.

(i) 20 minutes into seconds
1 min = 60 seconds
Therefore 20 min = 60 \(\times\) 20 = 1200 seconds
(ii) 5 hours 35 minutes 40 seconds into seconds.
1 hour = 3600 seconds
5 hour = 5 \(\times\) 3600 = 18000 sec.
1 min = 60 see
35 min = 35 \(\times\) 60 = 2100 see
Therefore 5 hours 35 minutes 40 seconds
= (18000 + 2100 + 40) sec
= 20140 seconds
(iii) 3 1/2 hours into minutes
1 hour = 60 min
7 1/2 hours = 60 \(\times\) 7/2 = 210 minutes
(iv) 580 minutes into hours
60 min = 1 hour
580 min = 1/60 \(\times\) 580
= 58/6 = 9 4/6
= 9 hours 40 min (4 / 6 = 40 min)
(v) 25200 seconds into hours.
3600 sec = 1 hour
25200 sec = 1 /3600 \(\times\) 25200 = 252 / 36 = 7 hours

27.

Convert in the format : YYYY/MM/DD

Mala's age : 18 yrs 10 months 15 days

28.

Total Quantity of Lemon Juice
= 200 l - 200000 ml
Each student get = 250 ml
No. of students get the juice
= 200000 ml
250ml
= 800 ml
800 students got the juice

29.

The product of common factors of 40 and 56
= 2 \(\times\) 2 \(\times\) 2 = 8 and so, HCF (40, 56) = 8
Dividing by the common factor 2, (in 3 steps)
HCF = Product of common factors
= 2 \(\times\) 2 \(\times\) 2 = 8

Generic 5

4 x 5 = 20

30.

Step 1: Draw a line. Mark two points A and B on the line such that AB = 6.5 cm. Mark a point M anywhere above the line.
Step 2: Place the set square below AB in such a way that one of the edges that form a right angle lies along AB. Place the scale along the other edge of the set square as shown in the figure.
Step 3: Holding the scale firmly, Slide the set square along the edge of the scale until the other edge of the set square reaches the point M. Through M draw a line as shown.
Step 4: The line MN is parallel to AB. That is, MN ║AB

31.

Step 1: Draw a line PQ. Take a point X anywhere above the line PQ.
Step 2: Place one of the arms of the right angle of a set square along the line PQ and the other arm of its right angle touches the point X.
Step 3: Draw a line through the point X meeting PQ at Y.
Step 4: The line XY is perpendicular to the line PQ at Y. That is, XY \(\bot \) PQ

32.

(i) 80°, 60°
The sum of 3 angles of triangle = 180°
Let A = 80° , B = 60° , C = ?
A + B + C = 180°
80° + 60° + C = 180°
= 180° - (80° + 60°)
C = 180° - 140° = 40°
Therefore third angle = 40°
(ii) 75°, 35°
The sum of 3 angles of triangle = 180°
Let A = 75°, B = 35°, C = ?
A + B + C = 180°
75° + 35° + C = 180°
= 180° - (75° + 35°)
C = 180° - 110° = 70°
Therefore third angle = 70°
(iii) 52°, 68°
The sum of 3 angles of triangle = 180°
Let A = 52°, B = 68°, C = ?
A + B + C = 180°
52 + 68 + C = 180°
= 180° - (52° + 68°)
C = 180° - 120° = 60°
Therefore third angle = 60°
(iv) 50°, 90°
The sum of 3 angles of triangle = 180°
Let A = 50°, B = 90°, C = ?
A + B + C = 180°
50° + 90° + C = 180°
= 180° - (50° + 90°)
C = 180° - 140° = 40°
Therefore third angle = 40°
(v) 120°, 30°
The sum of 3 angles of triangle = 180°
Let A = 120°, B = 30°, C = ?
A + B + C = 180°
75° + 35° + C = 180°
= 180° - (120°+ 30°)
C = 180° - 150 = 30°
Therefore third angle = 30°
(vi) 55°, 85°
The sum of 3 angles of triangle = 180°
Let A = 55°, B = 85°, C = ?
A + B + C = 180°
55° + 85° + C = 180°
= 180° - (55° + 85°)
C = 180° - 140°= 40°
Therefore third angle = 40°

33.

(i) 8 cm, 6 cm, 4 cm
The sum of two smaller sides
= 6 cm + 4 cm = 10 cm > 8 cm, the third side.
It is greater than the third side
So, yes a triangle can be formed.
Type: Scalene triangle.
(ii) 10 cm, 8 cm, 5 cm.
The sum of two smaller sides
= 8 cm + 5 cm = 13 cm > 10 cm, the third side.
It is greater than the third side.
Therefore, yes a triangle can be formed.
Type: Scalene triangle.
(iii) 6.2 cm, 1.3 cm, 3.5 cm.
The sum oftwo smaller sides
= (1.3 + 3.5) cm = 4.8 cm < 6.2 cm It is
lesser than the third side.
Therefore, no a triangle cannot be formed.
(iv) 6 cm, 6 cm, 4 cm.
The sum of two smaller sides
= 6 cm + 4 crn = 10 cm > 6 cm, the third side.
It is greater than the third side.
Therefore, yes a triangle can be formed
Type: Isoceles triangle.
(v) 3.5 cm, 3.5 cm, 3.5 cm
The sum of two smaller sides = (3.5 + 3.5) cm = 7 cm > 3.5 cm
Therefore, it s greater than the third side.
Yes a triangle can be formed.
Type: Equilateral triangle
(vi) 9 cm, 4 cm, 5 cm
The sum of two smaller sides = 4 cm + 5 cm = 9 cm = 9 cm
Therefore, it s equal to the third side.
No, a triangle cannot be formed.