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Published on: 04/09/2019
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Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Find the number of dots in the tenth figure of the following patterns.

2.
How many Triangles are there in each of the following figures?

3.
You have two red and two blue blocks. How many different towers can you build that are four blocks high using these blocks? List all the possibilities.
4.
Find the minimum number of straight lines used in forming the following figures.

5.

(i) Draw the next pattern.
(ii) Prepare a table for the number of dots used for each pattern.
(iii) Explain the pattern.
(iv) Find the number of dots in the 25th pattern.
6.
Using the numbers from 1 to 9
(i) Can you form a magic triangle?
(ii) How many magic triangles can be formed?
(iii) What are the sums of the sides of the magic triangle?

7.
Find the number of dots in the tenth figure of the following patterns.

8.
How many Triangles are there in each of the following figures?

9.
How many Triangles are there in each of the following figures?

1.
The number of dots given are 1, 4, 9, 11, 16, 25, ...
The no. of dots are in the pattern 1 \(\times\) 1, 2 \(\times\) 2, 3 \(\times\) 3, 4 \(\times\) 4, 5 \(\times\) 5 .... 10 \(\times\) 10
\(\therefore \) The number of dots in the 10th figure = 100.
2.
The single portions A, B, C, D, E, F, G and H are 8 triangles.
Taking the combination of 2 E & F, F & G, & H and E & H are 4 triangles.
There are 8 + 4 = 12 triangles.
3.
6 possibilities,
i) R - B - R - B
ii) R - R - B - B
iii) B - R - R - B
iv) B - R - B - R
v) B - B - R - R
vi) R - B - B - R
(R- RED, B- BLUE)
4.
There are 12 straight lines used which is minimum.
5.
(i) The next pattern is 
(ii)
| Pattern | 1 | 2 | 3 | 4 | 5 |
| Number of dots | 2 | 5 | 9 | 14 | 20 |
(iii)
| Pattern | Number of dots |
| 1 | 2 |
| 2 | 2+3 |
| 3 | 2+3+4 |
| 4 | 2+3+4+5 |
First number is 2
2nd number is 2 + 3 = 5
3rd number is 5 + 4 = 9
4th number is 9 + 5 = 14
5th number is 14 + 6 = 20
(iv) Number of dots in the 25th pattern is
| Pattern | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 |
| No. of dots | 2 | 5 | 9 | 14 | 20 | 27 | 35 | 44 | 54 | 65 | 77 | 90 | 104 | 119 | 135 | 152 | 170 | 189 | 209 | 230 | 252 | 275 | 299 | 324 | 350 |
\(\therefore \) Number of dots in the 25th pattern = 350.
6.
(i) Yes
(ii) 5
(iii)
Sums are 17, 19, 20, 21 and 23.
7.
The number of dots given are 1, 3, 6, 10, 15, ...
| Pattern | Number of dots |
| 1 | 1 |
| 2 | 3 |
| 3 | 6 |
| 4 | 10 |
| 5 | 15 |
1st number = 1
2nd number = 1 + 2 = 3
3rd number = 3 + 3 = 6
4th number = 6 + 4 = 10
5th number = 10 + 5 = 15
6th number will be 15 + 6 = 21
7th number will be 21 + 7 = 28
8th number will be 28 + 8 = 36
9th number will be 36 + 9 = 45
10th number will be 45 + 10 = 55
Number of dots in the 10th figure = 55.
8.
Taking smaller triangles we have AFB, BFG, BGC, CGH, HCD, DHI, DIE, EIJ, EJA and AJF \(\Rightarrow \)10 triangles.
Taking the combination of 2.
CGD, CID, DJE, DHE, EIA, EFA, AGB, AJB, BHC and BFC are 10 triangles.
Combining 3 at a time we have CED, DAE, EBA, ACB, BDC, CEF, DBJ, GDA, EBH, ACI => 10 triangles.
Other triangles are BCE, CAD, DBE, ADB and ACE are 5 triangles.
\(\therefore \) Total 10 + 10 + 10 + 5 = 35 triangles.
9.
(iii) Every part A, B, C, D, E, F, G, H, I, J, K, L, M, N, O and P are 16 triangles.
Combining two at a time. A & B, B & C, C & D, D & A, J & K, L & M, N & O, P & I are 8 triangles.
Taking the combination of 4, we have I, J, E & A; K, L, F and B, M, N, G and C, P, O, H and D are 4 triangles.
Taking 8 parts together we have QRS, RST, STQ, and TRQ are 4 triangles.
\(\therefore \) Total triangles = 16 + 8 + 4 + 4 = 32 triangles.
6th Standard Syllabus & Materials
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