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Published on: 13/12/2019
Term 2 Geometry
Download Tamil Nadu 7th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
In the given isoceles triangle IJK (Figure), if ㄥIKL = 1280, find the value of x.
2.
In the ΔABC shown in the figure, find the angel z.
3.
In ΔPQR, find the exterior angle, ㄥSRQ.
4.
If two angles of a triangle having measures 650 and 350, find the measure of the third angle.
5.
Can the following angles form a triangle?
(i) 800, 700, 500
(ii) 560, 640, 600
6.
If the given two triangles are congruent, then identify all the corresponding sides and also write the congruent angles.
7.
Using the diagram find the value of x.
8.
In a right angled triangle MNO, ㄥN = 900, MO is extended to P. If ㄥNOP = 1280, find the other two angles of ΔMNO.
9.
Observe the figure and find the value of
ㄥA + ㄥN + ㄥG + ㄥL + ㄥE + ㄥS.
10.
Two line segments \(\overset { \_ \_ }{ AD } \) and \(\overset { \_ \_ }{ BC } \) intersect at O. Joining \(\overset { \_ \_ }{ AB } \) and \(\overset { \_ \_ }{ DC } \) we get two triangles, Δ AOB and Δ DOC as shown in the figure. Find the ㄥA and ㄥB.
11.
In ΔABC and ΔPQR, ㄥA = 500 =ㄥP, PQ = AB, and PR = AC. By which property ΔABC and ΔPQR are congruent?
SSS property
SAS property
ASA property
RHS property
12.
In the given figure, AD = CD and AB = CB. Identify the other three pairs that are equal.
ㄥADB = ㄥCDB, ㄥABD = ㄥCBD, BD = BD
AD = AB, DC = CB, BD = BD
AB = CD, AD = BC, BD = BD
ㄥADB = ㄥCDB, ㄥABD = ㄥCBD, ㄥDAB = ㄥDBC
13.
Two students drew a line segment each. What is the condition for them to be congruent?
They should be drawn with a scale.
They should be drawn on the same sheet of paper.
They should have different lengths.
They should have the same length.
14.
Which of the following rule is not sufficient to verify the congruency of two triangles.
SSS rule
SAS rule
SSA rule
ASA rule
15.
Which of the following methods are used to check the congruence of plane figures?
translation method
superposition method
substitution method
transposition method
16.
If two plane figures are congruent then they have
same size
same shape
same angle
same shape and same size
17.
If an exterior angle of a triangle is 1150 and one of the interior opposite angles is 350, then the other two angles of the triangle are
450, 600
650, 800
650, 700
1150, 600
18.
In a ΔABC, AB = AC. The value of x is ____.
800
1000
1300
1200
19.
In the given figure, which of the following statement is true?
x + y + z = 1800
x + y + z = a + b + c
x + y + z = 2(a + b + c)
x + y + z = 3(a + b + c)
20.
The angles of a triangle are in the ratio 2: 3: 4. Then the angles are
20, 30, 40
40, 60, 80
80, 20, 80
10, 15, 20
1.
Exterior angle = sum of two interior opposite angles
1280 = x + x
128 = 2x
\(\frac { 128 }{ 2 } =\frac { 2x }{ 2 } \) [on both sides, divide by 2]
x = 640
2.
Exterior angle = sum of two interior opposite angles
1350 = z + 400
Subtract 400 on both sides
1350 − 400 = z + 400 − 400
z = 950
3.
Let, ㄥSRQ = x
Exterior angle = sum of two interior opposite angles
x = 380 + 440 = 820
4.
Given angles are 650 and 350.
Let the third angle be x
650 + 350 + x = 1800
1000 + x = 180°
x = 1800 – 1000
x = 800
5.
(i) Given angles 800, 700, 500
Sum of the angles = 800 + 700 + 500 = 2000 ≠ 1800
The given angles cannot form a triangle.
(ii) Given angles 560, 640, 600
Sum of the angles = 560+ 640+ 600 = 1800
The given angles can form a triangle.
6.
Corresponding sides
\(\overline{P Q} \text { matches } \overline{M N}\)
\(\overline{Q R} \text { matches } \overline{L M}\)
\(\overline{P R} \text { matches } \overline{L N}\)
Congruent angles
<P = <N
<R = <L
<Q = <M
7.
This is an equilateral triangle.
Each angle of this triangle is 60o.
x = 60o + 60o
[Exterior angle = sum of two opposite interior angles]
x = 120o
8.
Sum of two interior opposite angles = Exterior angle
\(\angle M+\angle N=128^{\circ}\)
\( \angle M+90^{\circ} =128^{\circ} \)
\(\angle M =128^{\circ}-90^{\circ}=38^{\circ} \)
\(\angle M+\angle N+\angle O =180^{\circ} \)
\(38^{\circ}+90^{\circ}+\angle O =180^{\circ} \)
\(128^{\circ}+\angle O =180^{\circ} \)
\(\angle O =180^{\circ}-128^{\circ}=52^{\circ} \)
9.
\(\angle A+\angle N+\angle G+\angle L+\angle E+\angle S\)
\(=\underbrace{\angle A+\angle E+\angle G}_{\text {Sum of three angles of } \Delta}+\underbrace{\angle S+\angle N+\angle L}_{\text {Sttm of three angles of } \Delta}\)
= 180o + 180o = 360o
10.
From the figure,
\(
\angle O+\angle D+\angle C =180^{\circ}
\)
\(\angle O+70^{\circ}+30^{\circ} =180^{\circ}
\)
\(\angle O+100^{\circ} =180^{\circ}
\)
\(\angle O =180^{\circ}-100^{\circ}
\)
\(\angle O =80^{\circ}\)
\(\Delta AOB,\)
\(
\angle O+\angle A+\angle B =180^{\circ}
\)
\(80^{\circ}+3 x+2 x =180^{\circ} \Rightarrow 80^{\circ}+5 x=180^{\circ}
\)
\(5 x =180^{\circ}-80^{\circ}=100^{\circ}
\)
\(x =\frac{100^{\circ}}{5}=20^{\circ}
\)
\(
\angle A=3 x=3 \times 20^{\circ}=60^{\circ}
\)
\(\angle B=2 x=2 \times 20^{\circ}=40^{\circ}\)
11.
(a)
SSS property
12.
(a)
ㄥADB = ㄥCDB, ㄥABD = ㄥCBD, BD = BD
13.
(d)
They should have the same length.
14.
(c)
SSA rule
15.
(b)
superposition method
16.
(d)
same shape and same size
17.
(b)
650, 800
18.
(a)
800
19.
(c)
x + y + z = 2(a + b + c)
20.
(b)
40, 60, 80
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