7th Standard Syllabus & Materials
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Published on: 13/12/2019
Term 2 Number System
Download Tamil Nadu 7th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Megala and Mala bought two watermelons weighing 13.523 kg and 13.52 kg. Which is a heavier one?
2.
Velan bought 8.36 kg of potato and Sekar bought 6.29 kg of potato. Which is heavier?
3.
Express the numbers given in expanded form in the place value grid. Also write its decimal representation.
40 + 6 + \(\frac { 7 }{ 10 } +\frac { 2 }{ 100 } +\frac { 6 }{ 1000 } \)
4.
Praveen goes trekking with his friends. He has to record the distance in kilometres in his sports book. Can you help him?
The trekking record for four days are given below
4 m
5.
The height of a person is 165 cm. Express this height in metre.
6.
Expand the following decimal numbers.
5678.358
7.
Expand the following decimal numbers.
237.6
8.
Express the following in metres using decimal.
16 cm
9.
Express the following in metres using decimal.
375 mm
10.
Write the decimal numbers for the following pictorial representation of numbers.
11.
The decimal number which lies between 4 and 5 is ____
4.5
2.9
1.9
3.5
12.
Between which two whole numbers 1.7 lie?
2 and 3
3 and 4
1 and 2
1 and 7
13.
78.56 ☐ 78.57
<
>
=
≠
14.
37.70 ☐ 37.7
=
<
>
≠
15.
0.009 is equal to
0.90
0.090
0.00900
0.900
16.
3 + \(\frac { 4 }{ 100 } +\frac { 9 }{ 1000 } \) = ?
30.49
3049
3.0049
3.049
17.
A cricket pitch is about 264 cm wide. It is equal to ____ m.
26.4
2.64
0.264
0.0264
18.
The decimal representation of 30 kg and 43 g is ____ kg.
30.43
30.430
30.043
30.0043
19.
To convert grams into kilograms, we have to divide it by
10000
1000
100
10
20.
The place value of 3 in 85.073 is _______
tenths
hundredths
thousands
thousandths
21.
Write the following fractions as decimals.
\(\frac { 9 }{ 1000 } \)
22.
Find the decimal form of the following fractions.
153 + 96 + 7 + \(\frac { 5 }{ 10 } \) + \(\frac { 2 }{ 1000 } \)
23.
Convert the following into simplest fractions.
0.04
1.
13.523 = 10 + 3 + \(\frac { 5 }{ 10 } +\frac { 2 }{ 100 } +\frac { 3 }{ 1000 } \)
13.52 = 10 + 3 + \(\frac { 5 }{ 10 } +\frac { 2 }{ 100 } +\frac { 0 }{ 1000 } \)
In this case, the two numbers have same digits upto hundredths place. But the thousandth place of 13.523 is 3, which is greater than 0, which is the thousandth place of 15.32.
So, 13.523 > 13.520
2.
Compare 8.36 and 6.29
Comparing the whole number part, we get 8 > 6.
Therefore, 8.36 > 6.29
3.
| Tens | Ones | Tenths | Hundredths | Thousandths |
| 4 | 6 | 7 | 2 | 6 |
40 + 6 + \(\frac { 7 }{ 10 } +\frac { 2 }{ 100 } +\frac { 6 }{ 1000 } \) = 46.726
4.
4 m = \(\frac { 4 }{ 1000 } \)km = 0.004 km
5.
Given, height of the person = 165 cm.
Hence, the height of the person = \(\frac { 165 }{ 100 } \) = 1.65 m
Since, 1 cm = \(\frac { 1 }{ 100 } \) m = 0.01 m
6.
5678.358 = 5000 + 600 + 70 + 8 \(+\frac{3}{10}+\frac{5}{100}+\frac{8}{1000}\)
= 5 x 1000 + 6 x 100 + 7 x 10 + 8 x 1 \(+3 \times \frac{1}{10}+5 \times \frac{1}{100}+8 \times \frac{1}{1000}\)
(Expanded form)
(OR)
= 5 x 103 + 6 x 102 + 7 x 101 + 8 x 10o + 3 x 10-1 + 5 x 10-2 + 8 x 10-3 (powers often)
7.
237.6 = 200 + 30 + 7 + \(\frac{6}{10}\)
= 2 x 100 + 3 x 10 + 7 x 1 + \(\frac{6}{10}\)
(Expanded Form)
= 2 x 102 + 3 x 101 + 7 x 10o + 6 x 10-1
(Powers of ten)
8.
\(1 \mathrm{~cm}=\frac{1}{100} m=0.01 \mathrm{~m}\)
16 cm = 16 x 1 cm
\(=16 \times \frac{1}{100} m
\)
\(=\frac{16}{100} m=0.16 \mathrm{~m}
\)
9.
\(1 \mathrm{~mm}=\frac{1}{10} \mathrm{~cm}=0.1 \mathrm{~cm}\)
375 mm = 375 x 1 mm
\(=375 \times \frac{1}{10} \mathrm{~cm}=\frac{375}{10} \mathrm{~cm}\)
375 mm = 37.5 cm
10.
21.3
11.
(a)
4.5
12.
(c)
1 and 2
13.
(a)
<
14.
(a)
=
15.
(c)
0.00900
16.
(d)
3.049
17.
(b)
2.64
18.
(c)
30.043
19.
(b)
1000
20.
(d)
thousandths
21.
In \(\frac { 9 }{ 1000 } \), tenth and hundredth place is zero.
Therefore, \(\frac { 9 }{ 1000 } \) = 0.009
22.
153 + 96 + 7 + \(\frac { 5 }{ 10 } \) + \(\frac { 2 }{ 1000 } \) = 256 + 5 x \(\frac { 1 }{ 10 } \) + 0 x \(\frac { 1 }{ 100 } \) + 2 x \(\frac { 1 }{ 1000 } \)
= 256.502 (since hundredths place is not there, it is taken as '0' )
23.
0 04 = \(\frac { 4 }{ 100 } =\frac { 1 }{ 25 } \)
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