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Published on: 09/10/2019
Exponents and Powers
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Questions + Answers key
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1.
Express the following numbers in normal form:
5.8 x 105
2.
Express the following numbers in the standard form:
90040000000
3.
Simplify:
\({(-2)^2\times (-3)^3\over (-1)^5\times (-4)^2}\)
4.
Simplify:
\({4^5\times 7^3\over 4^4\times 2\times7}\)
5.
Express the following in exponential form:
[(23)2 x 36]. X 56
6.
Express the following in exponential form:
32x33x55
7.
Express the following numbers in standard form.
(i) 31865000000
(ii) 3908.78
8.
By what number should we multiply (-8)-1 to obtain a product equal to 10-1?
9.
Simplify \(\frac { { 5 }^{ -2 }\times { 3 }^{ -3 }\times (125)^{ 2/3 } }{ (27)^{ -2/3 }\times (32)^{ -1/5 } } \).
10.
Express the following in usual form.
1.75 x 10-3
1.
580000
2.
9.004 X 1010
3.
\(27\over4\)
4.
98
5.
306
6.
155
7.
(i) 3.1865 x 1010
(ii) 3.90 x 103
8.
\(-\frac { 4 }{ 5 } \)
9.
\(\frac { { 5 }^{ -2 }\times { 3 }^{ -3 }\times (125)^{ 2/3 } }{ (27)^{ -2/3 }\times (32)^{ -1/5 } } \)
∵ 125 = (5)3 = 5 x 5 x 5
So, (125)2/3 =(5)3 x 2/3 =52 and 27=(3)3
∴ (27)-2/3 = {(3)3}-2/3 =\({ (3 })^{ 3\times \frac { -2 }{ 3 } }\) =(3)2
32 = 2 x 2 x 2 x 2 x 2 = (2)5
So, (32)-1/5 = {(2)5}-1/5 = \({ (2) }^{ 5\times \frac { (-1) }{ 5 } }\)=(2)-1
Now \(\frac { { 5 }^{ -2 }\times { 3 }^{ -3 }\times { 5 }^{ 2 } }{ (3)^{ -2 }\times (2)^{ -1 } } \) \(\left[ \because a^{ -m }=\frac { 1 }{ { a }^{ m } } \right] \)
= 5-2 x 3-3 x 32 x 21 x 52
=5-2+2 x 3-3+2 x 21
am x an =am+n
=50 x 3-1 x 21 = 1 x \(\frac { 1 }{ 3 } \times 2=\frac { 2 }{ 3 } \).
10.
Given, 1.75 x1 0-3
1.75 = 175 x 10-2
So, 1.75 x 10-3 =175 x 10-3 x 10-2
=175 x 10-5 \(\left[ \because \frac { 1 }{ { 10 }^{ 5 } } ={ 10 }^{ -5 } \right] \)
= 0.00175
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CBSE 7th Standard CBSE Subjects
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