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Published on: 16/06/2021
QB365 provides detailed and simple solution for every book back questions in class 7 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
Download Tamil Nadu 7th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Subtract:
(i) 4k from 12k
(ii) 15q from 25q
(iii) 7xyz from 17xyz.
2.
If x = 2 and y = 3, then find the value of the following expressions
(i) 2x − 3y
(ii) x + y
(iii) 4y − x
(iv) x + 1 − y
3.
Write the variables, constants and terms of the following expressions.
(i)18 + x − y
(ii) 7p − 4q + 5
(iii) 29x + 13y
(iv) b + 2
4.
Solve:
(i) x + 5 = 8
(ii) p − 3 = 7
(iii) 2x = 30
\((iv) \frac{m}{6}=5 \)
(v) 7x + 10 = 80
5.
Simplify
(i) (x + y − z) + (3x − 5y + 7z) − (14x + 7y − 6z)
(ii) p + p + 2 + p + 3 − p − 4 − p − 5 + p + 10
(iii) n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
1.
(i) 4k from 12k
12k - 4k = (12-4)k = 8k
(ii) 15q from 25q
25q - 15q (25 - 15) q = 10q
(iii) 7xyz from 17xyz
17xyz -7xyz = (17 -7) xyz = 10xyz
2.
Given x = 2; y = 3.
(i) 2x - 3y = 2 (2) - 3 (3) = 4 - 9
= 4 + (Additive inverse of 9)
= 4 + (-9) = - 5
(ii) x + y =2 + 3 = 5
(iii) 4y - x = 4 (3) - 2 = 12 - 2 = 10
(iv) x + 1- y = 2 + 1 - 3 = 3 - 3 = 0
3.
| S.No | Expression | Variable | Constant | Terms |
| (i) | 18 + x - y | x,y | 18 | 18,x,y |
| (ii) | 7p - 4q + 5 | p,q | 5 | 7p,-4q,5 |
| (iii) | 29x + 13y | x,y | - | 29x,13y |
| (iv) | b + 2 | b | 2 | b,2 |
4.
(i) x + 5 = 8
x + 5 - 5 = 8 - 5
[Subtract 5 on both sides]
x = 3
(ii) p -3 = 7
P - 3 + 3 = 7 + 3
[ Add 3 on both sides]
P = 10
(iii) 2x = 30
\(\frac{2 x}{2}=\frac{30}{2}\)
[ Divide by 2 on both sides]
x = 15
\((iv) \frac{m}{6}=5 \)
\(\frac{m}{6} \times 6=5 \times 6 \)
[ Multiply by 6 on both sides]
m = 5 x 6
m = 30
(v) 7x + 10 = 80
7x + 10 - 10 = 80 - 10
[Subtract 10 on both sides]
7x = 70
\(\frac{7 x}{7}=\frac{70}{7}\)
[Divide by 7 onboth sides]
x = 10
5.
(i) (x +y - z) + (3x .: 5y + 7z) - (14x + 7y - 6z)
= (x +y -z) + (3x - 5y + 7z) + (-14x -7y + 6z)
= (x + 3x - 14x) + (y - 5y -7y) + (-z + 7z + 6z)
= (1 + 3 - 14) x + (1-5 -7) y + (-1 + 7 + 6) z
= -10x -11y + 12z
(ii) p + p + 2 + p + 3 - p - 4 - P - 5 + p + 10
= (p + p + p - p - p + p) + (2 + 3 -4-5 + 10)
=(1 + 1 + 1 - 1 - 1 + 1)p +(15 -9)
= 2p + 6
(iii) n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
n + (m + 1) + (n + 2) + (m + 3) + (n + 4) + (m + 5)
=(n + n + n) + (m + m + m) + (1 + 2 + 3 + 4 + 5)
= (1 + 1 + 1) n + (1 + 1 + l)m + 15
= 3m + 3n + 15
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Tamilnadu Stateboard 7th Standard Subjects
Tamilnadu Stateboard Standards
