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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Maths Test1.
Construct a perpendicular bisector of the line segment AB = 6 cm.
2.
In Fig. find the value of x°
3.
From Fig find the measure of ∠ROS.
4.
Which of the following pair of adjacent angles will make a linear pair?
(i) 89°, 91°
(ii) 105°, 65°
(iii) 117°, 62°
(iv) 40°, 140°
5.
In Fig., find \(\angle \)AOC.
1.
Step 1: Draw a line. Mark two points A and B on it so that AB = 6 cm.
Step 2: Using compass with A as center and radius more than half of the length of AB, draw two arcs of same length, one above AB and one below AB.
Step 3: With the same radius and B as center draw two arcs to cut the arcs drawn in step 2. Mark the points of intersection of the arcs as C and D.
Step 4: Join C and D. CD will intersect AB. Mark the point of intersection as O CD is the required perpendicular bisector of AB.
Measure ∠AOC. Measure the length of AO and OB. What do you observe?
2.
98° + 23° + 76° + x° = 360°
197° + x° = 360°
x° = 360° - 197° = 163°
3.
We know that \(\angle\)QOR + \(\angle\)ROS + \(\angle\)SOP = 180°
26° + \(\angle\)ROS + 32° = 180°
\(\angle\)ROS + 58° = 180°
Subtracting 58° on both sides
We get, \(\angle\)ROS = 180° – 58° = 122°
4.
(i) Since 89° + 91° = 180°, this pair will be a linear pair.
(ii) Since 105° + 65° = 170° ≠ 180°, this pair cannot make a linear pair.
(iii) Since 117° + 62° = 179° ≠ 180°, this pair cannot make a linear pair.
(iv) Since 40° + 140° = 180°, this pair will be a linear pair.
5.
\(\angle \)AOC = \(\angle \)AOB + \(\angle \)BOC
= 46° + 51°
= 97°
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Tamilnadu Stateboard 7th Standard Subjects
Tamilnadu Stateboard Standards