7th Standard Syllabus & Materials
7th Standard
Tamilnadu 7th Standard Maths T2 - தகவல் செயலாக்கம் Important Questions And Answers Study Material - QB365 Set B
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - தகவல் செயலாக்கம் Important Questions And Answers Study Material - QB365 Set A
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - வடிவியல் Important Questions And Answers Study Material - QB365 Set C
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - வடிவியல் Important Questions And Answers Study Material - QB365 Set B
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - வடிவியல் Important Questions And Answers Study Material - QB365 Set A
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - இயற்கணிதம் Important Questions And Answers Study Material - QB365 Set C

Published on: 17/06/2021
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Questions + Answers key
Take MCQ Maths Test1.
Find the value of the following
(i) 3.26 x 10
(ii) 3.26 x 100
(iii) 3.26 x 1000
(iv) 7.01 x 10
(v) 7.01 x 100
(vi) 7.01 x 1000
2.
Latha purchased a churidar material of 3.75 m at the rate of Rs 62.50 per metre. Find the amount to be paid.
3.
Multiply 3.2 x 2.1
4.
Round 189.0007 upto 3 places of decimal.
5.
Round 99.95 to the nearest tenth place.
1.
(i) 3.26 x 10 = 32.6
(ii) 3.26 x 100 = 326.0
(iii) 3.26 x 1000 = 3260.0
(iv) 7.01 x 10 = 70.1
(v) 7.01 x 100 = 701.0
(vi) 7.01 x 1000 = 7010.0
2.
Cost of churidhar material = Rs. 62.50 per metre
Length of churidhar material = 3.75 m
Amount to be paid = 3.75 x 62.50
= Rs. 234.3750
= Rs.234.38 (rounded to two decimals)
3.
Let us try to represent the product of decimal
numbers (3.2 x 2.1) as the area of a rectangle. Let us
consider a rectangular portion as shown in Fig. 1.9.
The rectangular portion is split into 3 wholes and 2 tenth along it’s length (Fig. 1.10).
Since, 3 wholes and 2 tenth is multiplied with 2.1, we split the same area into 2 wholes and 1 tenth along its breadth (Fig. 1.11).
Here, each row contains 3 wholes and 2 tenth. Each column contains 2 wholes and 1 tenth. The entire area model represents 6 wholes, 7 tenth and 2 hundredth.
Therfore, 3.2 x 2.1 = 6.72.
4.
Round 189.0007 upto 3 places of decimal means rounding to the nearest thousandth place.
Underline the digit in the thousandth place of 189.0007 gives 189.0007 In 189.0007 we observe that the digit next to the thousandth place value is 7, which is greater than 5.
Therefore, we should add 1 to the underlined digit. Hence, we get 189.001. So the rounded value of 189.0007 upto 3 places of decimal is 189.001.
So the rounded value of 189.0007 upto 3 places of decimal is 189.001
5.
Underline the digit to be rounded 99.95.
Since the digit right to the tenth place is 5, we add 1 to the tenth place (underlined digit) of 99.95 and we get 100.0.
Look at the number line shown below
So, the rounded value of 99.95 is 100.0.
7th Standard Syllabus & Materials
7th Standard
Tamilnadu 7th Standard Maths T2 - இயற்கணிதம் Important Questions And Answers Study Material - QB365 Set B
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - இயற்கணிதம் Important Questions And Answers Study Material - QB365 Set A
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - அளவைகள் Important Questions And Answers Study Material - QB365 Set C
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - அளவைகள் Important Questions And Answers Study Material - QB365 Set B
Tamilnadu Stateboard 7th Standard Subjects
Tamilnadu Stateboard Standards