7th Standard Syllabus & Materials
7th Standard
Tamilnadu 7th Standard Maths T2 - தகவல் செயலாக்கம் Important Questions And Answers Study Material - QB365 Set B
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - தகவல் செயலாக்கம் Important Questions And Answers Study Material - QB365 Set A
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - வடிவியல் Important Questions And Answers Study Material - QB365 Set C
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - வடிவியல் Important Questions And Answers Study Material - QB365 Set B
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - வடிவியல் Important Questions And Answers Study Material - QB365 Set A
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - இயற்கணிதம் Important Questions And Answers Study Material - QB365 Set C
Published on: 13/05/2022
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Questions + Answers key
Take MCQ Maths Test1.
Sugarcane juice of 1.51 has to be shared equally among five members. What is the share of each member.
2.
Naren bought 7.4 kg of mangoes. On the way home, he gave 4.650 kg of mangoes to his sister’s family. Find the weight of the remaining mangoes.
3.
Subtract 2.85 from 4.97.
4.
Add the following : (i) 30.9 + 52.73 (ii) 25.67 + 33.856
5.
Find 0.52 – 0.08 using decimal grid models.
1.
Quantity of sugarcane juice = 1.51
Number of persons to be shared = 5.
Individual share = \(\cfrac { 1.5 }{ 5 } 0.3l\)
Therefore, the individual share is 0.3 litres.
2.
Mangoes bought by Naren = 7.4 kg
Mangoes given to Naren’s sister = 4.650 kg
Mangoes left for Naren’s family = 7.400 − 4.650
Weight of remaining mangoes = 2.750 kg
Therefore, the weight of the remaining mangoes is 2.750 kg.
3.
4.97 – 2.85 = ?
Let us use the place value grid.
| Decimal No | Ones | Tenth | Hundredth |
|---|---|---|---|
| 4.97 | 4 | 9 | 7 |
| 2.85 | 2 | 8 | 5 |
| 2.12 | 2 | 1 | 2 |
Therefore, 4.97 – 2.85 = 2.12.
4.
(i) 30.9 + 52.73
Let us use the place value grid.
(Since the digits in the decimal place of 52.73 is 2 and 30.9 is 1, we should add 0 at the hundredth place of 30.9 to equalize the digits in the decimal place)
| Decimal No. | Tens | Ones | Tenth | Hundredth |
| 30.9 | 3 | 0 | 9 | 0 |
| 52.73 | 5 | 2 | 7 | 3 |
| 83.63 | 8 | 3 | 6 | 3 |
Therefore, 30.9 + 52.73 = 83.63.
(ii) 25.67 + 33.856
Let us use
the place value grid.
| Decimal No. | Tens | Ones | Tenth | Hundredth | Thousandth |
| 25.67 | 2 | 5 | 6 | 7 | 0 |
| 33.856 | 3 | 3 | 8 | 5 | 6 |
| 59.526 | 5 | 9 | 5 | 2 | 6 |
Therefore, 25.67 + 33.856 = 59.526.
5.
Here \(0.52=\cfrac { 52 }{ 100 } \) and \(0.08=\cfrac { 8 }{ 100 } \). First shade the region 0.52 then cross out 0.08, which is \(\cfrac { 8 }{ 100 } \) from the shaded area. The left out shaded region without cross marks is the difference. So, 0.52 − 0.08 = 0.44 .
7th Standard Syllabus & Materials
7th Standard
Tamilnadu 7th Standard Maths T2 - இயற்கணிதம் Important Questions And Answers Study Material - QB365 Set B
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - இயற்கணிதம் Important Questions And Answers Study Material - QB365 Set A
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - அளவைகள் Important Questions And Answers Study Material - QB365 Set C
NEW7th Standard
Tamilnadu 7th Standard Maths T2 - அளவைகள் Important Questions And Answers Study Material - QB365 Set B
Tamilnadu Stateboard 7th Standard Subjects
Tamilnadu Stateboard Standards
