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Published on: 17/06/2021
QB365 provides detailed and simple solution for every book back questions in class 7 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
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Questions + Answers key
Take MCQ Maths Test1.
A family cleans a house for pongal celebration by dividing the work in the ratio 1:2:3. Express each portion of work as percentage.
2.
An alloy contains 26% of copper. What quantity of alloy is required to get 260g of copper?
3.
There are 50 students in a class. If 14% are absent on a particular day, find the number of students present in the class.
4.
Write the following percentage into fraction
125%
5.
Convert \(\cfrac { 7 }{ 4 } \) to percent.
1.
The total number of parts of the work is 1+ 2+ 3 = 6
That is, the work is divided into 3 portions as \(\cfrac { 1 }{ 6 } ,\cfrac { 2 }{ 6 } \) and \(\cfrac { 3 }{ 6 } \) .
Thus, the percentage of \(\quad \cfrac { { 1 }^{ th } }{ 6 } \quad \cfrac { 1 }{ 6 } \times 100\%=\cfrac { 100 }{ 6 }\% =16\cfrac { 2 }{ 3 }\% \)
Similarly, the percentage of \(\cfrac { { 2 }^{ th } }{ 6 } \) portion of work would be \(\cfrac { 2 }{ 6 } \times 100\%=\cfrac { 200 }{ 6 }\% =33\cfrac { 1 }{ 3 }\% \)
Similarly, the percentage of \(\cfrac { { 3 }^{ th } }{ 6 } \) portion of work would be \(\quad \cfrac { 3 }{ 6 } \times 100\%=\cfrac { 300 }{ 6 } =50\%\)
2.
Let the quantity of alloy required be Q g
Then 26 % of Q = 260 g
\(\cfrac { 26 }{ 100 } \times Q=260g\)
\(Q=\cfrac { 260\times 100 }{ 26 } g\)
Q = 1000 g
Therefore, the required quantity of alloy is 1000 g.
3.
Number of students absent on a particular day = 14% of 50
= \(\cfrac { 14 }{ 100 } \times 50=7\)
Therefore, the number of students present = 50 − 7 = 43 students.
4.
\(125\%=\cfrac { 125 }{ 100 } =\cfrac { 5 }{ 4 } \)
5.
We have \(\\ \cfrac { 7 }{ 4 } =\cfrac { 7 }{ 4 } \times \cfrac { 100 }{ 100 } =\cfrac { 7 }{ 4 } \times 100\%=\cfrac { 700 }{ 4 }\% =175\%\)
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Tamilnadu Stateboard 7th Standard Subjects
Tamilnadu Stateboard Standards
