(i) Mean
Total = 22 + 15 + 10 +10 + 24 + 21 = 102
\(The\ mean\ =\quad \cfrac { Total }{ number } =\cfrac { 102 }{ 6 } =17\) 
The mean = 17
(ii) Mode
Ascending order of given data
10, 10, 15, 21, 22, 24
Here, 10 occurs two times
mode = 10
(iii) Median
n = 6, even number
The median = \(\cfrac { 1 }{ 2 } \left( \cfrac { { n }^{ th } }{ 2 } term+\left( \cfrac { n }{ 2 } +1 \right) ^{ th }term \right) \) 
= \(\cfrac { 1 }{ 2 } \left( \cfrac { 6 }{ 2 } ^{ th }term+\left( \cfrac { 6 }{ 2 } +1 \right) ^{ th }term \right) \) 
= \(\cfrac { 1 }{ 2 } \left( { 3 }^{ rd }term+{ 4 }^{ th }term \right) \) 
= \(\cfrac { 1 }{ 2 } \left( 15+21 \right) =\cfrac { 1 }{ 2 } \times 36=18\) 
Hence Mean = 17, Mode = 10 and Median = 18

(i) Mean
\(\text { Mean } =\frac{\text { Sum of observations }}{\text { Number of observations }} \)
\(=\frac{6+11+13+12+4+2}{6}=\frac{48}{6}=8 \)
(ii) Mode
Ascending order 2,4,6,11 ,12, 13
No term occurs more than once
No mode.
Hence Mean = 8 and Mode = No mode

(i) Mean
\(\text { Mean } =\frac{\text { Sum of Marks }}{\text { Number of students }} \)
\(=\frac{12+10+8+18+14+16}{6}=\frac{78}{6}\)
Mean = 13
(ii) Median
Ascending order
8, 10, 12,14, 16, 18
n = 6 (even)
\(\text { Median } =\frac{1}{2}\left\{\left(\frac{\mathrm{n}}{2}\right)^{\text {th }} \operatorname{term}+\left(\frac{\mathrm{n}}{2}+1\right)^{\text {th }} \text { term }\right\} \)
\(=\frac{1}{2}\left\{3^{\mathrm{rd}} \operatorname{term}+4^{\text {th }} \text { term }\right\} \)
\(=\frac{1}{2}\{12+14\}=\frac{26}{2}=13 \)
Median = 13
Hence Mean = 13 and median = 13

5.1,4.8,4.3,4.5,5.1,4.7,4.5,5.2,5.4,5.8,4.3,5.6, 5.2, 5.5
\(The\ mean\ of\ the\ data=\cfrac { Total }{ Number } \) 
= \(\cfrac { 5.1+4.8+4.3+4.5+5.1+4.7+4.5++5.2+5.4+5.8+4.3+5.6+5.2+5.5 }{ 14 } \) 
=  \(\cfrac { 70 }{ 14 } =5\) 
The mean of the data = 5

The mean height of 11 students =  150 cm
\(The\ mean=\cfrac { Total\ marks\ of\ students }{ Number\ of\ students } \) 
\(150=\cfrac { 154+145+y+y+y+4+160151+149+149+150+144+140 }{ 11 } \) 
150 x 11 = 1346+ 2y
1650 = 1346 + 2y
2y = 1650 - 1346 = 304
\(y=\cfrac { 304 }{ 2 } =152\) 
y = 15 Height of two students Y = 152 cm and
y + 4 = 152 + 4 = 156 cm