Arranging the data in ascending order, we have,
365, 365, 547, 547, 730, 912, 1095, 1460, 1500, 1825, 2000.
The number of observations are 11, which is odd.
\(Median=\left( \cfrac { n+1 }{ 2 } \right) ^{ th }term\) 
= \(\left( \cfrac { 11+1 }{ 2 } \right) ^{ th }term\) 
= 6 ^th term = 912
Therefore, the median is 912.
Hence, the median lifetime of the LED bulb is 912 days.

Arranging the weights in ascending order, we have, 20, 24, 25, 29, 32, 35, 38, 40, 42, 45
Here, n = 10 , which is even.
Therefore, median weight = \(\cfrac { 1 }{ 2 } \left\{ \left( \cfrac { n }{ 2 } \right) ^{ th }term+\left( \cfrac { n }{ 2 } +1 \right) ^{ th }term \right\} \) 
= \(\cfrac { 1 }{ 2 } \left\{ \left( \cfrac { 10 }{ 2 } \right) ^{ th }term+\left( \cfrac { 10 }{ 2 } +1 \right) ^{ th }term \right\} \) 
= \(\cfrac { 1 }{ 2 } \left\{ { 5 }^{ th }tern+{ 6 }^{ th }term \right\} \) 
= \(\cfrac { 1 }{ 2 } \left\{ 32+35 \right\} kg=\cfrac { 67 }{ 2 } =33.5kg\) 
Hence, Median is 33.5 kg. 

Arranging the golf scores in ascending order, we have,
65, 68, 70, 73, 75, 78, 79
Here n = 7 , which is odd.
Therefore, Median = \(\left( \cfrac { n+1 }{ 2 } \right) ^{ th }term\) 
= \(\left( \cfrac { 7+1 }{ 2 } \right) ^{ th }term\) 
= \(\left( \cfrac { 8 }{ 2 } \right) ^{ th }term\) 
4^th term = 73
Hence, the Median is 73.

\(Mean=\cfrac { Mean\quad of\quad all\quad observations }{ Number\quad of\quad observations } \) 
\(38=\cfrac { 48+x+37+38+36+27+35+34+38+49+33 }{ 11 } \) 
\(38=\cfrac { 375+x }{ 11 } \) 
38 X 11 = 375 + x
418 = 375 + x
x = 418 – 375
x = 43
Hence, the value of x is 43.

\(Arthemetic\ Mean=\cfrac { Sum\ all\ observation }{ Number\ of\ observation } \) 
Thus, \(24=\cfrac { Sum\ of\ all\ observations }{ 9 } \) 
Sum of all observations = 9 x 24 = 216