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Published on: 16/08/2019
Work and Energy
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1.
Write the various energy transformations that occur in the following cases:
(a) Moving a car
(b) Going up in an escalator
(c) Rotating of an electric motor
(d) Release of an arrow from a bow
(e) Lighting of an electric bulb
(f) Tuning of an FM radio receiver
(g) Gas stove burner.
2.
Define the term work.State the conditions that need to be satisfied for work to be done.Give some situations in which work is done.
3.
Explain that the flying bird has potential and kinetic energy and give their expressions.
4.
Two bodies of equal masses move with uniform velocities of 2v and 3v respectively.Find the ratio of their kinetic energies.
5.
How does an object with energy do work?
6.
A pair of bullocks exerts a force of 140N on a plough.The field being ploughed is 15 m long.How much work is done in ploughing the length of the field?
7.
What is the work done when the direction of displacement and the direction of force F acting on a body are perpendicular to each other?
8.
An object of mass 40 kg is raised to a height of 5m above the ground.What is its potential energy?If the object is allowed to fall, find its kinetic energy when it is half-way down.
9.
Define 1 watt of power.
10.
A body of mass 25 kg is raised to the top of a building 10 m high and then dropped freely under gravity.
(a) Calculate the work done in raising the body to the top of the building.
(b) What is the value of the gravitational potential energy at the top of the building?
(c) By what factor will the gravitational potential energy of the same body increase if it is raised to the top of a multistorey building 30 m high?
(d) When will the kinetic energy of the body be maximum?
11.
A car weighing 1000 kg and travelling at 30 m/s stops at a distance of 50 m decelerating uniformly. What is the force exerted on it by the brakes?What is the work done by the brakes?
12.
What is the kinetic energy of an object?
13.
If a stone of mass m falls a vertical d, the decrease in gravitational potential energy is
mg/d
md2/2
mgd
md/g
14.
If the mass of a body is doubled, its kinetic energy of 1 joule relative to the ground when it is at a height of
0.102 m
1 m
9.8 m
32 m
15.
The kinetic energy of a body decreses by 10%.What is the percentage decrease in momentum?
10
20
30
None of these
16.
Ns is equivalent to
kg m s-2
kg m s-1
kg m s-3
Nm-1 s
17.
Joule is the unit of
power
work
momentum
force
18.
Work done is measure by
mass x velocity
mass x acceleration
force x distance
force x time
19.
(i) A battery lights a bulb.Describe the energy changes involved in the process.
(ii) Calculate the amount of work needed to stop a car of 500 kg moving at a speed of 36 kmh-1.
1.
(a) Heat energy produced in the engine into K.E. of the car.
(b) Electric energy into potential energy
(c) Electric energy into mechanical energy
(d) P.E. into K.E.
(e) Electrical energy into heat and light.
(f) Electrical energy into sound energy.
(g) Chemical energy into heat energy and light.
2.
Work is said to be done whenever a force a acts on a body moves in the direction of the force.
Two conditions need to be satisfied for work to be done.These are as follows:
(i) A force should act on the body.
(ii) The body must be displaced in the direction of the applied force.
If either of the above two conditions is not satisfied, then work is not done.
Examples: We give below some situations from daily life in which work is done.
(i) Push a pebble lying on a surface.The pebble moves through some distance.Here we apply a force on the pebble and the pebble gets displaced.So, we have done work on the pebble.
(ii) We apply a force to lift a book through a height.The book rises up.We have done work in moving up the book.
(iii) A bullock is pulling a cart.The cart moves.There is a force on the cart and the cart has moved.The bullock has done work on the cart.
3.
A flying bird has potential energy due to its height h above the ground.This energy is
Ep= mgh
Due to its velocity v, the flying bird has a kinetic energy given by
Ek= 1/2mv2.
4.
Let the mass of each body be m.
K.E. of the first body, K1 = 1/2m(2v)2
K.E. of the second body, K2 = 1/2m(3v)2
Ratio of the kinetic energies=K1/K2 = 1/2m.4v2 /1/2m.9v2 = 4/9 = 4:9
5.
An object that possesses energy can exert a force on another object.When this happens, energy is transferred from the former to the latter.The second object may move as it receives energy and therefore do some work.Thus, the first object has a capacity to do work.This implies that any object that possesses energy can do work.
6.
Here, Force(F) = 140N, Displacement (s) = 15m
Work done, W = Fs = 140 N x 15 m = 2100 J
7.
Zero.
This is because the component of the force acting on a body in the direction of its displacement is zero in this case.Moreover,
\(W=F\ s\ cos\ 90°=0\)
8.
Here, m = 40 kg, g = 10 ms-2, h = 5m
Potential energy of the object at a height of 5m,
Ep = mgh =40 x 10 x 5= 2000J
When the object is half-way down, let its velocity be v.Then
v2- u2 = 2gs
v2 - 02 = 2 x 10 x 2.5 or v2 = 50
Kinetic energy of the object, Ek=1/2 x 40 x 50 = 1000 J
9.
The SI unit of power is watt(W). The power of an agent is one watt if it does work at the rate of 1 joule per second.
1 watt = 1joule/1 second. or 1W = 1 Js-1
We can also say that power is 1 watt when the rate of consumption of energy is 1 Js-1 .
Bigger units of power are kilowatt, megawatt, and horsepower.
1 kilowatt =1000 watt or 1 kW = 1000 W
1 megawatt = 106 watt or 1 MW = 106 W
1 horse power =746 watt or 1 H.P = 746 W
10.
Here m = 25 kg, h = 10m, g = 10m/s2
(a) Work done = mgh =25 x 10 x 10J = 2500J
(b) Gravitational P.E.= Work done =2500J
(c) Gravitational P.E. at a height of 30m = 25 x 30 x 10J = 7500J
P.E. at 30 m height/P.E. at 10m height = 7500J/2500J = 3
Thus, P.E. increases by 3 times.
(d) K.E. of the body will be maximum just before the body strikes the ground.
11.
Here m = 1000 kg, u=30 m/s, v = 0, s = 50 m
v2 - u2 = 2as
0-302 = 2a.50 or a = -900/100 = -9 m/s2
Deceleration= 9m/s2
decelerating force, F = ma =1000 x 9 = 9000 N
Work done by the brakes, W = F.s = 9000 x 50J = 450000J
12.
Kinetic energy is the energy possessed by a body by the virtue of its motion. Every moving object possesses kinetic energy. A body uses kinetic energy to do work. Kinetic energy of hammer is used in driving a nail into a log of wood, kinetic energy of air is used to run wind mills, etc.
13.
(a)
mg/d
14.
(a)
0.102 m
15.
(d)
None of these
16.
(b)
kg m s-1
17.
(b)
work
18.
(c)
force x distance
19.
(i) First the battery converts chemical energy into electrical energy. Then the bulb converts this electrical energy into heat and light.
(ii) Here, m = 500 kg, v = 0 and
u = 36 kmh-1 = \(\frac{36\times 1000}{3600}\) = 10 ms-1
\(\therefore\) Work done = Change in kinetic energy
= \(\frac{1}{2}m(v^2-u^2)=\frac{1}{2}\times 500(0-10^2)\)
= \(\frac{1}{2}\times 500\times 100\) = - 25000 Js-1
So, it is negative because work is done to stop the car.
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