9th Standard Syllabus & Materials
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Published on: 25/07/2019
Motion
Download Tamil Nadu 9th Standard Science question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Science Test1.
Distinguish distance and displacement.
2.
Define velocity?
3.
An object travels 16m in 4s and then another 16m in 2s. What is the average speed of the object?
4.
Speed is never ______
fraction
negative
zero
positive
5.
In a 100 m race, the winner takes 10 s to reach the finishing point. The average speed of the winner is ___________ ms-1.
5
10
20
40
6.
The force responsible for drying of clothes in a washing machine is
Centripetal force
Centrifugal force
Gravitational force
Electrostatic force
7.
Unit of acceleration is
ms-1
ms-2
ms
ms2
8.
Slope of the velocity - time graph gives
speed
displacement
distance
acceleration
9.
Acceleration is a _____ quantity.
10.
The graph of uniform motion is _____
11.
Area under velocity тАТ time graph shows ____________
12.
Consider an object is rest at position x = 20m. Then its displacement – time graph will be straight line to _____________ the axis.
13.
Speed is a ____________ quantity whereas velocity is a ____________ quantity
14.
Giant wheel moves a vertical linear path.
15.
For a freely falling body the acceleration 'a' is replaced by s.
16.
If the velocity – time graph of a particle is a straight line inclined to X-axis then its displacement – time graph will be a straight line?
17.
Distance covered by a particle never becomes zero but displacement becomes zero
18.
The motion of a city bus in a heavy traffic road is an example for uniform motion
19.
Distance
20.
Speed
21.
Uniform acceleration
22.
Constant retardation
23.
Motion of a body covering equal distances in equal interval of time
24.
Derive equations of motion by graphical method.
25.
A racing car has a uniform acceleration of 4 ms-2. What distance it covers in 10 s after start?
26.
A student takes 15 minutes to travel from his home to school with a uniform speed of 5km/h. What is the distance of his school from the home?
27.
What is acceleration?
28.
What is speed?
29.
Define distance.
1.
| Distance | Displacement |
| (1) The actual length of the path travelled by a moving body. |
The change in position of a moving body in a particular direction. |
| (2) It is a scalar quantity. | It is a vector quantity. |
2.
Velocity is the rate of change of displacement.
3.
Total distance travelled by the object = 16 m + 16 m = 32m
Total time taken = 4s + 2s = 6s
Average speed \(=\frac { Total\ distance\ travelled }{ total\ time\ taken } =\frac { 32m }{ 6s } =\frac { 32 }{ 6 } =5.33m{ s }^{ -1 }\)
Therefore, the average speed of the object is 5.33ms-1
4.
(b)
negative
5.
(b)
10
6.
(b)
Centrifugal force
7.
(b)
ms-2
8.
(d)
acceleration
9.
( )
Vector
10.
( )
Straight line
11.
( )
magnitude of the displacement
12.
( )
Parallel to
13.
( )
scalar, vector
14.
(b)
15.
(b)
16.
(a)
17.
(a)
18.
(b)
19.
m
20.
m/s
21.

22.

23.

24.

Graph shows the change in velocity with time for an uniformly accelerated object. The object starts from the point 'D' in the graph with velocity 'u'. lts velocity keeps increasing and after time 't' it reaches the point 'B'.on the graph.
The initial velocity of the object = u = OD = EA.
The final velocity of the object = v = OC = EB
Time = t = OE = DA
Also from the graph we know that, AB = DC
First equation of motion:
By definition, acceleration = change in velocity / time
= (final velocity - initial velocity)/ time
= (OC - OD) / OE
= DC / OE
a =DC / t
DC = AB = at
From the graph EB = EA + AB
v = u + at ... (1)
This is first equation of motion.
Second equation of motion:
From the graph the distance covered by the object during time t is given by the area of quadrangle DOEB.
s = area of the quadrangle DOEB
= area of the rectangle DOEA + area of the triangle DAB
= (AE x OE) + (1/2 x AB x DA)
s = ut + 1/2 at2 ... (2)
This is second equation of motion.
Third equation of motion:
From the graph the distance covered by the object during time t is given by the area of the quadrangle DOEB. Here DOEB is a trapezium. Then
S = area of trapezium DOEB
= 1/2 x sum of length of parallel side x distance between parallel sides
= 1/2 x (OD + BE) x OE
S = 1/2 x (u + v) x t
since a = (v - u) / t or t = (v - u) / a.
Therefore s = 1/2 x (v + u) x (v - u) / a
2as = v2 - u2
v2 = u2 + 2 as ......(3)
This is third equation of motion.
25.
Acceleration (a) =4 m / s
Time (t) =10 second
distance (s) = ?
Initial velocity = 0
According to second equation of motion
\(s =u t+1 / 2 a t^{2}┬а \)
\(=0+1 / 2 \times 4 \times(10)^{2}┬а \)
\(=0+\frac{1}{\not 2} \times \not4^{2} \times 100┬а\)
= 0 + 200
= 200
Distance covers = 200 m.
26.
Speed = 5 km/m = \(\frac { 5000 }{ 3600 } \) m/s
Time = 15 min = 15 x 60 sec
Distance = Speed x time
=\(\frac { 5000 }{ 3600 } \) x 15 x 60 = 1250 m
27.
Acceleration is the rate of change of velocity or it is the change of velocity in unit time.
28.
Speed is the rate of change of distance or the distance travelled in unit time.
Speed = \(\frac { Distance\ travelled }{ time\ taken } \).
29.
The actual length of the path travelled by a moving body irrespective of the direction is called the distance travelled by the body.
9th Standard Syllabus & Materials
9th Standard
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Tamilnadu Stateboard 9th Standard Subjects
Tamilnadu Stateboard Standards