\(\mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O}+\mathrm{O} \)
\(\mathrm{H}_{2} \mathrm{SO}_{3}+\mathrm{O} \longrightarrow \mathrm{H}_{2} \mathrm{SO}_{4} \)
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\( \mathrm{H}_{2} \mathrm{SO}_{3}+\mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{SO}_{4}+\mathrm{H}_{2} \mathrm{O} \)
or \(\mathrm{SO}_{3}^{2-}+\mathrm{H}_{2} \mathrm{O}_{2} \longrightarrow \mathrm{SO}_{4}^{2-}+\mathrm{H}_{2} \mathrm{O} \)

The values possessed by UK scientists are control of environmental pollution and generation of new sources of energy which are highly efficient.

It produce more energy per unit mass of fuel and does not create pollution.

The value possessed by the office bearer of Green Park Association are best to use of rainwater, saving water for drinking irrigation, domestic purpose etc.

Yes, because these are unsaturated fats and hence,good for health. They do not form cholesterol if taken in small quantity.

0.2 L(or 200 mL) of 5M solution will contain 
\(\frac { 340\times0.2 }{ 2 } =34g{ H }_{ 2 }{ O }_{ 2 }\)
\(\underset { 2\times 34=68g }{ { 2H }_{ 2 }O_{ 2 } } \rightarrow { 2H }_{ 2 }O+\underset { 2\times 16=32g }{ { O }_{ 2 } } \)
\(\because \ 68g \ { H }_{ 2 }O_{ 2 }\) on decomposition will give 32g\(O_{ 2 }\)
\(\therefore \ 34g \ { H }_{ 2 }O_{ 2 }\) on decomposition will give
\(\frac { 32\times 34 }{ 68 } =16g{ O }_{ 2 }\)

Molar mass of \({ H }_{ 2 }{ O }_{ 2 }=34 \ gmol^{ -1 }\)
1L of 5M solution of \({ H }_{ 2 }O_{ 2 }\)will contain 34 x 5g \({ H }_{ 2 }O_{ 2 }\)
2L of 5M solution of \({ H }_{ 2 }O_{ 2 }\)will contain 34 x 5 x 2 = 340g \({ H }_{ 2 }O_{ 2 }\)
Mass of \({ H }_{ 2 }O_{ 2 }\)present in 2L of 5 molar solution = 340g

I.Highly pure Dihydrogen (hydrogen gas ) can be prepared by the following methods.
Fairly pure hydrogen can be obtained by treating pure magnesium or pure aluminium with chemically pure H₂SO₄ or HCl diluted with distilled water. The gas is passed over P₂O₅
and is collected by the displacement of mercury.
\(Mg(s)+{ H }_{ 2 }{ SO }_{ 4 }(aq)\rightarrow Mg{ SO }_{ 4 }(aq)+{ H }_{ 2 }(g)\)
Highly pure hydrogen gas can be obtained by electrolyzing a warm solution of  Ba(OH)₂ in a U tube using nickel electrodes. The gas is purified by passing it over heated platinum gauze when traces of oxygen combine with hydrogen forming water.
The gas is then dried by passing it over caustic potash sticks and photash sticks and phophorous pentoxide. Hydrogen is finally absorbed in palladium and the impurities remain unadsorbed. On heating palladium under reduced pressure, pure hydrogen is liberated.

It is LiH because it has significant covalent character due to the smallest alkali metal Li. LiH is very stable. It is almost unreactive towards oxygen and chlorine.
It reacts with \({ Al }_{ 2 }{ Cl }_{ 6 }\) to form lithium aluminium hydride.
\(8LiH+{ Al }_{ 2 }{ Cl }_{ 6 }\longrightarrow 2LiAl{ H }_{ 4 }+6LiCl\)

\(CO(g)+{ H }_{ 2 }(g)\xrightarrow [ \Delta ]{ Catalyst } { CH }_{ 3 }OH(l)\)

\({ H }_{ 2 }(g)+{ M }_{ m }{ O }_{ 0 }(s)\underrightarrow { \Delta } \)