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Download CBSE Class 11th Standard CBSE Chemistry question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 11th Standard CBSE Chemistry
Questions + Answers key
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1.
Comment on the thermodynamic stability of NO(g), given
\(\frac { 1 }{ 2 } N_{ 2 }(g)+\frac { 1 }{ 2 } { O }_{ 2 }(g)\rightarrow NO(g);\Delta _{ r }H^{ \circ }=90kJmol^{ -1 }\)
\( NO(g)+\frac { 1 }{ 2 } O_{ 2 }(g)\rightarrow NO_{ 2 }(g)\Delta _{ r }H^{ \circ }=-74kJmol^{ -1 }\)
2.
Heat has randomising influence on a system and temperature is the measure of average chaotic motion of particles in the system. Write the mathematical relation which relates these three parameters.
3.
Identify the state functions and path functions out of the following. Enthalpy, entropy, heat, temperature, work, free energy.
4.
Heat capacity (Cp) is an extensive property but specific heat (C) is an intensive property. What will be the relation between Cp and C for 1mole of water?
1.
The positive value of ΔrH indicates that heat is absorbed during the formation of NO(g). This means that NO(g) has higher energy than the reactants (N2 and O2). Hence, NO(g) is unstable.
The negative value of ΔrH indicates that heat is evolved during the formation of NO2(g) from NO(g) and O2(g). The product, NO2(g) is stabilized with minimum energy.
Hence, unstable NO(g) changes to stable NO2(g).
2.
Heat has randomising influence on a system and temperature is the measure of average chaotic motion of particles in the system. The mathematical relation which relates these three parameters is ΔS=qrev/T
Here, ΔS = change in entropy
qrev= heat of reversible reaction
T = temperature
3.
State function Enthalpy, entropy, temperature, free energy. Path function Heat, work.
4.
Specific heat, C=4.18Jg−1K−1 (for water)
Heat capacity, Cp=18 × 4.18JK−1=75.24JK−1
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