Si (E.N. = 8) is more electropositive than C (E.N. = 2.5), therefore, Me₃Si (trimethylsilyl group) has greater +l-effect than that of Me₃C (r-butyl group). As a result, Me₃Si intesifies the -ve charge on the carboxylate ion relative to r-butyl group and hence Me₃CCH₂COOH is a stronger acid that Me₃SiCH₂COOH.

Due to absence of benzylic hydrogens, tert-butylbenzene does not-undergo oxidation to give benzoic acid while other alkylbenzenes such as toluene, ethyl benzene, n- propylbenzene and isopropylbenzene which contain one or more benzylic hydrogens (marked as 'a') undergo oxidation to form benzoic acid.

(i) Loss of a proton from an oxime gives a conjugate base which is stabilized by resonance but the conjugate base of NH₂OH is not.
(ii) To prepare iodoform from acetone, I⁺ is required which is supplied by IO^- ion but not by I^- ion as shown below:
(iii) During oxidation of toluene with CrO/H₂SO₄, the intermediate benzaldehyde formed readily undergoes oxidation to form benzoic acid due to the presence of H₂O in H₂SO₄,
\(\underset{Toluene}{C_6H_5-CH_3}\xrightarrow[\Delta]{CrO_3/H_2SO_4}\underset{Benzaldehyde}{C_6H_5-CHO}\xrightarrow{H_2O}\underset{Benzaldehyde\ hydrate}{C_6H_5CH(OH)_2}\xrightarrow{CrO_3/H_2SO_4}\underset{Benzalde\ acid}{C_6H_5COOH}\)
However, with CrO ₃3 in (CH₃CO)₂O, due to the absence of H₂O as soon as benzaldehyde is formed, it reacts with acetic anhydride to form benzylidene diacetate which does not undergo further oxidation. In this way, oxidation of benzaldehyde to benzoic acid is prevented. The gem-diacetate thus formed upon subsequent hydrolysis with alkali or acid gives benzaldehyde
\(\underset{Toluene}{C_6H_5CH_3}\xrightarrow[273-283K]{CrO_3/H_2SO_4}\underset{Benzylidene diacetate\\ (gem-diacelate)}{C_6H_5CH(OOH_3)_2}\xrightarrow[(Hydrolysis)]{H_3O^+}\underset{Benzaldehyde}{C_6H_5CHO}+\underset{Acetic\ acid}{2CH_3COOH}\)