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CBSE 12th Standard Physics Subject Moving Charges And Magnetism Ncert Exemplar 1 Mark Questions 2021

Published on: 23/05/2021

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Std: 12th Standard CBSE - Physics

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Questions:

Generic 2

4 x 2 = 8

A bar magnet is cut into two equal parts as shown in the Fig. (a) One part is now kept over the other such that, the P₂is above P₁ as shown in the Fig.(b).
If M is the magnetic moment of the original magnet, what would be the magnetic moment of new combination of magnets so formed?

Why is a coil wrapped on a conducting frame in a galvanometer?

Give the magnitude of torque which acts on a coil carrying current placed in a uniform radial magnetic field.

A coil of N turns and radius R carries a current I. It is unwound and rewound to make a square coil of side a having same number of turns N.Keeping the currentI same, find the ratio of the magnetic moment of the square coil and the circular coil.

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Answers Key:

Generic 2

4 x 2 = 8

When the bar magnet is cut into two equal parts, as shown in the Fig. (a), P₁ behaves as N and P₂ behaves as S and magnetic moment of each part of magnet becomes \(\frac { M }{ 2 } \) . When pole P₂ is placed over pole P₁ as shown in Fig. (b), the Magnetic moment of the combination is zero i.e. \(\frac { M }{ 2 } -\frac { M }{ 2 } =0.\)

Eddy current in conducting frame help in stropping the coil soon,i.e.in making the galvanometer dead beat.

Torque, \(\tau \) = NBIA sin \(\theta\), where the terms have their usual meanings.

Ratio of magnetic moments,
\(\frac { M_{ s } }{ M_{ c } } =\frac { 2INA_{ s } }{ INA_{ c } } =\frac { 2\left( \frac { R }{ 2 } \right) ^{ 2 } }{ \left( R \right) ^{ 2 } } =\frac { 1 }{ 2 } \)