100% FREE ACCESS10th Standard Syllabus & Materials
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Published on: 28/06/2019
frequently asked five mark problems chapter one
Download Tamil Nadu 10th Standard Science question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Science Test1.
A door is pushed, at a point whose distance from the hinges is 90 cm, with a force of 40 N. Calculate the moment of the force about the hinges.
2.
Calculate the velocity of a moving body of mass 5 kg whose linear momentum is 2.5 kg m s-1.
3.
At what height from the centre of the Earth the acceleration due to gravity will be 1/4th of its value as at the Earth.
1.
Formula: The moment of a force M = F × d
Given: F = 40 N and d = 90 cm = 0.9 m.
Hence, moment of the force = 40 × 0.9 = 36 N m.
2.
Linear momentum = mass × velocity
Velocity = linear momentum / mass. V = 2.5 / 5 = 0.5 m s-1
3.
Data: Height from the centre of the Earth,
R' = R + h
The acceleration due to gravity at that height, g' = g/4'
Formula: g = GM /R2, gʹ = GM /Rʹ2
\(\frac { g }{ g' } =\left( \frac { R' }{ R } \right) ^{ 2 }={ \left( \frac { R+h }{ R } \right) }^{ 2 }={ \left( 1+\frac { h }{ R } \right) }^{ 2 }\)
\(4=\left( 1+\frac { h }{ R } \right) ^{ 2 },\)
\(2=1+\frac { h }{ R } \quad or\quad h=R.\quad R'=2R\)
From the centre of the Earth, the object is placed at twice the radius of the earth.
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Tamilnadu Stateboard 10th Standard Subjects
Tamilnadu Stateboard Standards
