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Published on: 01/10/2019
Applied Statistics
Download Tamil Nadu 12th Standard Business Maths and Statistics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
Fit a trend line by the method of semi-averages for the given data.
| Year | 1990 | 1991 | 1992 | 1993 | 1994 | 1995 | 1996 | 1997 |
| Sales | 15 | 11 | 20 | 10 | 15 | 25 | 35 | 30 |
2.
3.
The following data gives the readings for 8 samples of size 6 each in the production of a certain product. Find the control limits using mean chart.
| Sample | 1 | 2 | 3 | 4 | 5 | 6 |
| Mean | 300 | 342 | 351 | 319 | 326 | 333 |
| Range | 25 | 37 | 20 | 28 | 30 | 22 |
Given for n = 6, A2 = 0.483,
4.
Fit a trend line by the method of semi-averages for the given data.
| Year | 2000 | 2001 | 2002 | 2003 | 2004 | 2005 | 2006 |
| Production | 105 | 115 | 120 | 100 | 110 | 125 | 135 |
5.
The following data gives readings of 10 samples of size 6 each in the production of a certain product. Draw control chart for mean and range with its control limits.
| Sample | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Mean | 383 | 508 | 505 | 582 | 557 | 337 | 514 | 614 | 707 | 753 |
| Range | 95 | 128 | 100 | 91 | 68 | 65 | 148 | 28 | 37 | 80 |
6.
The data shows the sample mean and range for 10 samples for size 5 each. Find the control limits for mean chart and range chart.
| Sample | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Mean | 21 | 26 | 23 | 18 | 19 | 15 | 14 | 20 | 16 | 10 |
| Range | 5 | 6 | 9 | 7 | 4 | 6 | 8 | 9 | 4 | 7 |
7.
Calculate the seasonal index for the quarterly production of a product using the method of simple averages.
| Year | I Quarter | II Quarter | III Quarter | IV Quarter |
| 2005 | 255 | 351 | 425 | 400 |
| 2006 | 269 | 310 | 396 | 410 |
| 2007 | 291 | 332 | 358 | 395 |
| 2008 | 198 | 289 | 310 | 357 |
| 2009 | 200 | 290 | 331 | 359 |
| 2010 | 250 | 300 | 350 | 400 |
8.
9.
Given below are the data relating to the sales of a product in a district.
Fit a straight line trend by the method of least squares and tabulate the trend values.
| Year | 1995 | 1996 | 1997 | 1998 | 1999 | 2000 | 2001 | 2002 |
| Sales | 6.7 | 5.3 | 4.3 | 6.1 | 5.6 | 7.9 | 5.8 | 6.1 |
10.
Given below are the data relating to the production of sugarcane in a district.
Fit a straight line trend by the method of least squares and tabulate the trend values.
| Year | 2000 | 2001 | 2002 | 2003 | 2004 | 2005 | 2006 |
| Prod.of Sugarcane | 40 | 45 | 46 | 42 | 47 | 50 | 46 |
1.
Since the number of years is even(eight), we can equally divide the given data it two equal parts and obtain the averages of first four years and last four years.

| Year | Production | Average |
| 1990 | 15 | \(\frac{15+11+20+10}{4}=14\) |
| 1991 | 11 | |
| 1992 | 20 | |
| 1993 | 10 | |
| 1994 | 15 | \(\frac{15+25+35+30}{4}=26.25\) |
| 1995 | 25 | |
| 1996 | 35 | |
| 1997 | 30 |
2.

3.
| Sample | 1 | 2 | 3 | 4 | 5 | 6 | Total |
| Mean | 300 | 342 | 351 | 319 | 326 | 333 | 1971 |
| Range | 25 | 37 | 20 | 28 | 30 | 22 | 162 |
\(\overset { = }{ X } =\frac { \sum { \overset { - }{ X } } }{ number\ of\ samples } =\frac { 1971 }{ 6 } =328.5\quad \quad \overset { - }{ R } =\frac { \sum { R } }{ n } =\frac { 162 }{ 6 } =27\)
The control limits for \(\overset {-}{X}\) chart is
\(UCL=\overset { = }{ X } +{ A }_{ 2 }\overset { - }{ R } =328.5+0.483(27)=341.54\)
\(CL=\overset { = }{ X } =328.5\)
\(LCL=\overset { = }{ X } -{ A }_{ 2 }\overset { - }{ R } =328.5+0.483(27)=315.45\)
4.
Since the number of years is odd(seven), we will leave the middle year’s production value and obtain the averages of first three years and last three years.

| Year | Production | Average |
| 2000 | 105 | \(\frac{105+115+120}{3}=113.33\) |
| 2001 | 115 | |
| 2002 | 120 | |
| 2003 | 100(left out) | |
| 2004 | 110 | \(\frac{110+125+135}{3}=123.33\) |
| 2005 | 125 | |
| 2006 | 135 |
5.
| Sample | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Total |
| Mean | 383 | 508 | 505 | 582 | 557 | 337 | 514 | 614 | 707 | 753 | 5460 |
| Range | 95 | 128 | 100 | 91 | 68 | 65 | 148 | 28 | 37 | 80 | 840 |
\(\overset { = }{ X } =\frac { \sum { \bar { X } } }{ 10 } =\frac { 5460 }{ 10 } =546\)
The control limits for \(\overset{-}{X}\) chart is
\(UCL=\overset { = }{ X } +{ A }_{ 2 }\bar { R } =546+0.483(84)=586.57\)
\(CL=\overset { = }{ X } =546\)
\(LCL=\overset { = }{ X } -{ A }_{ 2 }\bar { R } =546-0.483(84)=505.43\)
\(\bar { R } =\frac { \sum { R } }{ n } =\frac { 840 }{ 10 } =84\)
The control limits for Range chart is
\(UCL={ D }_{ 4 }\bar { R } =2.004(84)=168.336\)
\(CL=\bar { R } =84\)
\(LCL={ D }_{ 3 }\bar { R } =0(84)=0\)
6.
| Sample | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | Total |
| Mean | 21 | 26 | 23 | 18 | 19 | 14 | 14 | 20 | 16 | 10 | 182 |
| Range | 5 | 6 | 9 | 7 | 4 | 6 | 8 | 9 | 4 | 7 | 65 |
\(\overset { = }{ X } =\frac { \sum { \overset { - }{ X } } }{ numberofsamples } =\frac { 182 }{ 10 } =18.2\quad \overset { - }{ R } =\frac { \sum { R } }{ n } =\frac { 65 }{ 10 } =6.5\)
The control limits for \(\overset{-}{X}\) chart is
\(UCL=\overset { = }{ X } +{ A }_{ 2 }\bar { R } =18.2+0.577(6.5)=21.95\)
\(CL=\overset { = }{ X } =18.2\)
\(LCL=\overset { = }{ X } -{ A }_{ 2 }\bar { R } =18.2-0.577(6.5)=14.5795\)
The control limits for Range chart is
\(UCL={ D }_{ 4 }\bar { R } =2.114(6.5)=13.741\)
\(CL=\bar { R } =65\)
\(LCL={ D }_{ 3 }\bar { R } =0(6.5)=0\)
7.
Computation of Seasonal Index by the method of simple averages.
| Year | I Quarter | II Quarter | III Quarter | IV Quarter |
| 2005 | 255 | 351 | 425 | 400 |
| 2006 | 269 | 310 | 396 | 410 |
| 2007 | 291 | 332 | 358 | 395 |
| 2008 | 198 | 289 | 310 | 357 |
| 2009 | 200 | 290 | 331 | 359 |
| 2010 | 250 | 300 | 350 | 400 |
| Quarterly Total |
1463 | 1872 | 2170 | 2321 |
| Quarterly Averages |
243.83 | 312 | 361.67 | 386.83 |
S.I for I Quarter = \(\frac{Average\ of \ I\ quarter }{Grand\ average} \times100\)
Grand Average = \(\frac{1304.333}{4}=326.0833\)
S.I for I Q = \(\frac{243.8333}{326.0833} \times100= 74.77;\)
S.I for II Q = \(\frac{312}{326.0833} \times100=95.68;\)
S.I for III Q = \(\frac{361.6667}{326.0833} \times 100=110.91; \)
S.I for IV Q = \(\frac{386.833}{326.0833} \times 100=118.63\)
8.
9.
Computation of trend values by the method of least squares.
In case of EVEN number of years, let us consider
\(X=\frac{\text{(x-Arithimetic mean of two middle years)}}{0.5}\)
| Year(x) | Sales(Y) | X=\(\frac{(x-1998.5)}{0.5}\) | XY | X2 | Trend Values (Yt) |
| 1995 | 6.7 | -7 | -46.9 | 49 | 5.6166 |
| 1996 | 5.3 | -5 | -26.5 | 25 | 5.7190 |
| 1997 | 4.3 | -3 | -12.9 | 9 | 5.8214 |
| 1998 | 6.1 | -1 | -6.1 | 1 | 5.9238 |
| 1999 | 5.6 | 1 | 5.6 | 1 | 6.0261 |
| 2000 | 7.9 | 3 | 23.7 | 9 | 6.1285 |
| 2001 | 5.8 | 5 | 29.0 | 25 | 6.2309 |
| 2002 | 6.1 | 7 | 42.7 | 49 | 6.3333 |
| N = 8 | 47.8 | \(\sum X\) = 0 | 8.6 | 168 |
\(a=\frac { \sum { Y } }{ n } =\frac { 47.8 }{ 8 } =5.975;\quad b=\frac { \sum { XY } }{ { \sum { X } }^{ 2 } } =\frac { 8.6 }{ 168 } =0.05119\)
Therefore, the required equation of the straight line trend is given by
Y = a + bX; Y = 5.975 + 0.05119 X.
When X = 1995, Yt = 5.975 + 0.05119\(\left( \frac { 1995-1998.5 }{ 0.5 } \right) =5.6166\)
When X = 1996, Yt = 5.975 + 0.05119\(\left( \frac { 1996-1998.5 }{ 0.5 } \right) =5.7190\)
similarly other values can be obtained.
10.
Computation of trend values by the method of least squares (ODD Years).
| Year(x) | Production of Sugarcane(Y) | X=(x–2003) | X2 | XY | Trend values(Yt) |
| 2000 | 40 | -3 | 9 | -120 | 42.04 |
| 2001 | 45 | -2 | 4 | -90 | 43.07 |
| 2002 | 46 | -1 | 1 | -46 | 44.11 |
| 2003 | 42 | 0 | 0 | 0 | 45.14 |
| 2004 | 47 | 1 | 1 | 47 | 46.18 |
| 2005 | 50 | 2 | 4 | 100 | 47.22 |
| 2006 | 46 | 3 | 9 | 138 | 48.25 |
| N=7 | \(\sum Y\)=316 | \(\sum X\)=0 | \(\sum X\)2=8 | \(\sum XY\)=29 | \(\sum Yt\)=316 |
\(a=\frac { \sum { Y } }{ n } =\frac { 316 }{ 7 } =45.143;\quad b=\frac { \sum { XY } }{ { \sum { X } }^{ 2 } } =\frac { 29 }{ 28 } =1.036\)
Therefore, the required equation of the straight line trend is given by
Y = a + bX
Y = 45.143 + 1.036 (x - 2003)
The trend values can be obtained by
When X = 2000 , Yt = 45.143 + 1.036(2000–2003) = 42.035
When X = 2001, Yt = 45.143 + 1.036(2001–2003) = 43.071,
similarly other values can be obtained.
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