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Published on: 20/10/2025
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
Why group 18 elements are called inert gases? Write the general electronic configuration of group 18 elements.
2.
Complete the following reactions.
\(1. \mathrm{NaCl}+\mathrm{MnO}_{2}+\mathrm{4H}_{2} \mathrm{SO}_{4} \longrightarrow \)
\(2. \mathrm{NaNO}_{2}+\mathrm{HCl} \longrightarrow \)
\(3.\mathrm{P}_{4}+\mathrm{3NaOH}+\mathrm{3H}_{2} \mathrm{O} \longrightarrow \)
\(4. \mathrm{AgNO}_{3}+\mathrm{PH}_{3} \longrightarrow \)
\(5. \mathrm{Mg}+\mathrm{10HNO}_{3} \longrightarrow \)
\(6. \mathrm{KClO}_{3} \stackrel{\Delta}{\longrightarrow} \)
\(7. \mathrm{Cu}+Con. \ Hot \ \mathrm{H}_{2} \mathrm{SO}_{4} \longrightarrow\)
\(8. \mathrm{Sb}+\mathrm{Cl}_2 \longrightarrow \)
\(9. \mathrm{HBr}+\mathrm{H}_2 \mathrm{SO}_4 \longrightarrow \)
\(10. \mathrm{XeF}_6+\mathrm{H}_2 \mathrm{O} \longrightarrow \)
\(11. \mathrm{XeO}_6{ }^{4-}+\mathrm{Mn}^{2+}+\mathrm{H}^{+} \longrightarrow \)
\(12. \mathrm{XeOF}_4+\mathrm{SiO}_2 \longrightarrow \)
\(13. \mathrm{Xe}+\mathrm{F}_2 \frac{\mathrm{Ni} / 200 \mathrm{~atm}}{400^{\circ} \mathrm{C}}\).
3.
What type of hybridisation occur in
a) BrF5
b) BrF3
4.
Deduce the oxidation number of oxygen in hypofluorous acid – HOF.
5.
Suggest a reason why HF is a weak acid, whereas binary acids of the all other halogens are strong acids.
6.
7.
Give a reaction between nitric acid and a basic oxide.
8.
Give two equations to illustrate the chemical behaviour of phosphine.
9.
Write the valence shell electronic configuration of group-15 elements.
10.
Give the uses of argon.
11.
Write the molecular formula and structural formula for the following molecules.
a) Nitric acid
b) Dinitrogen pentoxide
c) phosphoric acid (PTA)
d) phosphine
12.
13.
How will you prepare chlorine in the laboratory?
14.
What is the hybridisation of iodine in IF7? Give its structure.
15.
CO is a reducing agent. Justify with an example.
16.
Write a note on zeolites.
17.
18.
Complete the following reactions.
a. \(B(OH)_3 + NH_3\longrightarrow \)
b. \(Na_{ 2 }B_{ 4 }{ O }_{ 7 }+{ { H }_{ 2 }{ SO }_{ 4 }+{ 5H }_{ 2 }O\longrightarrow }\)
c. \({ B }_{ 2 }{ H }_{ 6 }+2NaOH+2{ H }_{ 2 }O\longrightarrow \)
d. \({ B }_{ 2 }{ H }_{ 6 }+6{ CH }_{ 3 }OH\longrightarrow \)
e. \(4{ BF }_{ 3 }+3{ H }_{ 2 }O\longrightarrow \)
f. \(HCOOH+{ H }_{ 2 }{ SO }_{ 4 }\longrightarrow \)
g. \(2SiCl_{ 4 }+NH\)3
h. SiCl4 + 4C2H5OH \(\rightarrow\)
i. 2\(B+6NaOH\longrightarrow \)
j. \({ H }_{ 2 }{ B }_{ 4 }{ O }_{ 7 }\overset { Red\ hot }{ \rightarrow } \)
19.
Give one example for each of the following
(i) icosogens
(ii) Tetragens
(iii) pnictogens
(iv) chalcogens
20.
Write a short note on hydroboration.
21.
Describe the structure of diborane.
22.
Why fluorine is more reactive than other halogens?
23.
Give the oxidation state of halogen in the following.
a) OF2
b) O2F2
c) Cl2O3
d) I2O4
24.
Explain why fluorine always exhibit an oxidation state of -1?
25.
Chalcogens belongs to p-block. Give reason.
26.
What is inert pair effect?
27.
Give the structure of CO and CO2.
28.
Write a note on Fisher tropsch synthesis.
29.
What is catenation ? describe briefly the catenation property of carbon.
30.
Write a short note on anomalous properties of the first element of p-block.
1.
The elements of group 18 have a completely filled configuration of ns2np6.
Hence they are more stable and less reactive and so called as noble gases.
2.
\((i) \quad 4 \mathrm{NaCl}+\mathrm{MnO}_{2}+4 \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{Cl}_{2}+\mathrm{MnCl}_{2}+4 \mathrm{NaHSO}_{4}+2 \mathrm{H}_{2} \mathrm{O} \)
\((ii) \quad \mathrm{NaNO}_{2}+\mathrm{HCl} \rightarrow \mathrm{NaCl}+\mathrm{HNO}_{2} \)
\((iii) \quad \mathrm{P}_{4}+3 \mathrm{NaOH}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow 3 \mathrm{NaH}_{2} \mathrm{PO}_{2}+\mathrm{PH}_{3} \uparrow \)
\((iv) \quad 3 \mathrm{AgNO}_{3}+\mathrm{PH}_{3} \rightarrow \mathrm{Ag}_{3} \mathrm{P}+3 \mathrm{HNO}_{3} \)
\((v) \quad 4 \mathrm{Mg}+10 \mathrm{HNO}_{3} \rightarrow 4 \mathrm{Mg}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{N}_{2} \mathrm{O}+6 \mathrm{H}_{2} \mathrm{O} \)
\((vi) \quad 2 \mathrm{KClO}_{3} \stackrel{\Delta}{\longrightarrow} 2 \mathrm{KCl}+3 \mathrm{O}_{2} \uparrow \)
\((vii) \quad \mathrm{Cu}+Con. Hot \mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{CuSO}_{4}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{SO}_{2} \uparrow \)
\((viii) \quad 2 \mathrm{Sb}+3 \mathrm{Cl}_{2} \rightarrow 2 \mathrm{SbCl}_{3} \)
\((ix) \quad 2 \mathrm{HBr}+\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow 2 \mathrm{SO}_{2}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{Br}_{2} \)
\((x) \quad \mathrm{XeF}_{6}+3 \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{XeO}_{3}+6 \mathrm{HF} \)
\((xi) \quad 5 \mathrm{XeO}_{6}^{4-}+2 \mathrm{Mn}^{2+}+14 \mathrm{H}^{+} \rightarrow 2 \mathrm{MnO}_{4}^{-}+5 \mathrm{XeO}_{5}+7 \mathrm{H}_{2} \mathrm{O} \)
\((xii) \quad 2 \mathrm{XeOF}_{4}+\mathrm{SiO}_{2} \rightarrow 2 \mathrm{XeO}_{2} \mathrm{~F}_{2}+\mathrm{SiF}_{4} \)
\((xiii) \quad Xe+{ 3F }_{ 2 }\overset { Ni/200atm }{ \underset { 400^{ 0 }C }{ \longrightarrow } }XeF_6\)
3.
a) BrF5
Valence electron of bromine atom 7+ Number of fluorine atom (5) = 12
\(X=\frac{12}{2}=6\)
Hybridization: sp3d2 ;
Geometry: Square Pyramidal
b) BrF3
Valence electron of bromine atom 7+ Number of fluorine atom (3) = 10
X = \(\frac{10}{2}=5\)
Hybridization: sp3d2;
Geometry: Triangular bipyramidal (T - shaped)
4.
Oxidation number of F = -1
Oxidation number of H = +1
Oxidation number of O in HOF =x
(+1) + x + (-1) = 0
x = 0
Oxidation number of O in HOF = 0
5.
HF is a weak acid i.e. 0.1 M solution is only 10% ionised, but in 5M & 15M solution, HF is stronger acid due to chemical equilibrium.
\(\mathrm{HF}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{F}^{-} \)
\(\mathrm{HF}+\mathrm{F}^{-} \rightleftharpoons \mathrm{HF}_{2}^{-}\)
6.
7.
HNO3 reacts with basic oxides to form salts and water
ZnO + 2HNO3\(\longrightarrow \) Zn(NO3)2 + H2O
3FeO + 10HNO3 \(\longrightarrow \) 3Fe(NO3)3 + NO + 5H2O
8.
Thermal stability:
\(4 \mathrm{PH}_{3} \stackrel{317 \mathrm{~K}}{\longrightarrow} \mathrm{P}_{4}+6 \mathrm{H}_{2} \)
Combustion:
\(4 \mathrm{PH}_{3}+8 \mathrm{O}_{2} \stackrel{\Delta}{\longrightarrow} \underset{\text { Phosphorus pentoxide }}{\mathrm{P}_{4} \mathrm{O}_{10}+6 \mathrm{H}_{2} \mathrm{O}} \)
\(\mathrm{P}_{4} \mathrm{O}_{10}+6 \mathrm{H}_{2} \mathrm{O} \stackrel{\Delta}{\longrightarrow} 4 \mathrm{HPO}_{3}+4 \mathrm{H}_{2} \mathrm{O}\\ \quad \quad \quad \quad \quad \quad \quad \text{Meta phosphoric acid}\)
9.
(i) The general electronic configuration of 15 group elements is ns2np3.
(ii) Nitrogen \(\Rightarrow 2 \mathrm{~s}^{2} 2 \mathrm{p}^{3}\) (Valence shell)
(iii) Phosphorus \(\Rightarrow 3 \mathrm{~s}^{2} 3 \mathrm{p}^{3}\)
(iv) Arsenic \(\Rightarrow 4 \mathrm{~s}^{2} 4 \mathrm{p}^{3}\)
(v) Antimony \(\Rightarrow 5 s^{2} 5 p^{3}\)
(vi) Bismuth \(\Rightarrow 6 \mathrm{~s}^{2} 6 \mathrm{p}^{3}\)
10.
Argon prevents the oxidation of hot filament and prolongs the life in filament bulbs.
11.
12.
13.
Chlorine is prepared by the action of conc. sulphuric acid on chlorides in presence of manganese dioxide
4NaCl + MnO2 + 4H2SO4 \(\longrightarrow \)Cl2+ MnCl2 +4NaHSO4 + 2H2O
14.
(i) sp3d3 hybridisation
(ii) Pentagonal bipyramidal structure.
15.
CO acts as a strong reducing agent.
Example: 3CO + Fe2O3 \(\longrightarrow \) 2Fe + 3CO2
It reduces metallic. oxides into metals.
16.
(i) Zeolites are three-dimensional crystalline solids containing Al, Si and O in their regular three dimensional framework.
(ii) They are hydrated sodium alumino silicates with general formula Na2O(AI2O3).·x(SiO2)·yH2O
(x = 2 to 10; y = 2 to 6).
(iii) Zeolites have porous structure in which the monovalent sodium ions and water molecules are loosely held.
(iv) The Si and Al atoms are tetrahedrally coordinated with each other through shared oxygen atoms.
(v) Zeolites are similar to clay minerals but they differ in their crystalline structure.
(vi) Zeolites have a three dimensional crystalline structure looks like a honeycomb consisting of a network of interconnected tunnels and cages.
(vii) Water molecules moves freely in and out of these pores but the zeolite framework remains rigid
(viii) Another special aspect of this structure is that the pore/channel sizes are nearly uniform, allowing the crystal to act as a molecular sieve.
17.
18.
(a) B(OH)3 + NH3\(\overset { \Delta }{ \longrightarrow } \) BN + 3H2O
(Boron nitride)
(b) Na2B4O7 + H2SO4 + 5H2O \(\longrightarrow \) 4H3BO3 + Na2SO4
(Boric acid)
(c) B2H6 + 2NaOH + 2H2O \(\longrightarrow \)2NaBO2 + 6H2
(Sodium metaborate)
(d) B2H6 + 6CH3OH \(\longrightarrow \)2B(OCH3)3 + 6H2O
(Trimethyl borate)
(e) 4BF3 + 3H2O \(\longrightarrow \) H3BO3 + 3H+ + 3[BF4]-
(Boric acid)
(f) HCOOH + H2SO4 \(\longrightarrow \)CO + H2SO4. H2O
(Carbon monoxide)
(g) 2SiCl4 + NH3 \(\overset { 330K }{ \underset { ether }{ \longrightarrow } } \)Cl3Si- NH - SiCl3 + 2HCl
(Chlorosilazane)
(h) SiCl4 + 4C2H5OH\(\longrightarrow \)Si(OC2H5)4 + 4HCI
(Tetraethoxysilane)
(i) 2B + 6NaOH\(\longrightarrow \) 2Na3BO3 + 3H2
(j) H2B4O7 \(\xrightarrow[]{Redhot}\) 2B2O3 + H2O
19.
(i) Icosogens → B, Al, Ga, In, Tl
(ii) Tetragens → C, Si, Ge, Sn, Pb
(iii) Pnictogens → N, P, As, Sb, Bi
(iv) Chalcogens → O, S, Se, Te, Po
20.
Diborane adds on to alkenes and alkynes in ether solvent at room temperature. This reaction is called hydroboration.
\({ B }_{ 2 }{ H }_{ 6 }+6RCH=CHR\longrightarrow 2B(RCH_2-{ CH }R)_{ 3 }B\)
21.
(i) In diborane two BH2 units are linked by two bridged hydrogens.
(ii) It has eight B-H bonds.
(iii) Diborane has only 12 valance electrons.
(iv) The four terminal B-H- bonds is "2c - 2e" bond (two centre - two electron bond.)
(v) Two three centred B - H - B bonds two electrons each. "(3c - 2e)"
(vi) In diborane, the boron is "sp3" hybridised
(vii) Three of the four "sp3" hydridised orbitals contains single electron and the fourth orbital is empty.
22.
(i) Fluorine is more electro negative than other halogens.
(ii) Because except fluorine all the other halogens have positive oxidation state.
(iii) It has high electron affinity character
Example:
\(\mathrm{Cl}_{2}\mathrm{O} \Rightarrow+1 \text { oxidation state }(\mathrm{Cl}) \)
\(\mathrm{OF}_{2} \Rightarrow-1 \text { oxidation state }(\mathrm{F})\)
23.
(a) OF2
+ 2 + 2(x) = 0
+2 = -2x
2 x = -2 ⇒ x = -1
(b) O2F2
2(+1) + 2x = 0
2x = -2
x = -1
(c) Cl2O3
2(x) + 3(-2) = 0
2x = +6
x = +3
(d) I2O4
2(x) + 4(-2) = 0
2x = +8
x = +4
24.
(i) Fluorine is most electronegative atom.
(ii) It has only one unpaired electron.
25.
(i) The Chalcogens belong to group (16).
(ii) The group consists of elements: Oxygen, Sulphur, Selenium, Tellurium and Polonium.
(iii) These are ore forming elements as most of the ores are oxides and sulphides.
(iv) Chalcos meaning 'ore formers'.
26.
(i) In heavier post transition metals, the outers electrons (ns) have a tendency to remain inert and show reluctance to take part in the bonding, which is known as inert pair effect.
(ii) This effect is also observed in groups 14, 15 and 16.
27.
| Oxides of Carbon | Structure | Parameters |
| CO | ![]() |
Three electron pairs are shared between carbon and oxygen. The C-O bond distance is 1.128\(\overset{o}{A}\). |
| CO2 | ![]() |
Equal bond distance for the both C-O bonds. Two C-O sigma bond, It has 3c-4e bond. |
28.
The reaction of CO with hydrogen at a pressure of less than 50 atm using metal catalysts at 500 - 700 K yields saturated and unsaturated hydrocarbons.
\(nCO+(2n+1){ H_2 }\longrightarrow C_{ n }{ H }_{ (2n+2) }+{ nH }_{ 2 }O\)
\(nCO+2n{ H }_{ 2 }\longrightarrow { C }_{ n }{ H }_{ 2n }+{ nH }_{ 2 }O\)
29.
Catenation is an ability of an element to form chain of atoms.
The conditions for catenation.
(a) The valency of element is greater than or equal to two.
(b) Element should have an ability to bond with itself
(c) The self bond must be as strong as Its bond with other elements
(d) Kinetic inertness of catenated compound towards other molecules.
(e) Carbon possesses all the above properties and forms a wide range of compounds with itself and with other elements such as H, O, N, S and halogens.
30.
In p-block elements, the first member of each group differs from the other elements of the corresponding group. The following factors are responsible for this anomalous behaviour
(i) Small size of the first member.
(ii) High ionisation enthalpy and high electronegativity.
(iii) Absence of d-orbitals in their valance shell.
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