Acetone is soluble in water due to the intermolecular hydrogen bonding between polar carbonyl group and water molecules. In benzophenone, the phenyl groups are bulkier so C = 0 cannot form hydrogen bonds with water due to steric hindrance.

HCHO + CaCO₃

Acetaldehyde is used:
(i) Acetaldehyde is used for silvering of mirrors
(ii) Paraldehyde is used in medicine as a hypnotic.
(iii) Acetaldehyde is used in the commercial preparation of number of organic compounds like acetic acid, ethyl acetate etc.,

Acetaldehyde and methyl ketones, containing \(\\ \\ { CH }_{ 3 }-\underset { \overset { | }{ O } }{ C } -group\) , when treated with halogen and alkali give the corresponding haloform. This is known as Haloform reaction
\({ CH }_{ 3 }-\underset { \overset { || }{ O } }{ C } -{ CH }_{ 3 }\overset { { 3Cl }_{ 2 } }{ \underset { Na }{ \longrightarrow } } { CCl }_{ 3 }-\underset { \overset { || }{ O } }{ C } -{ CH }_{ 3 }\overset { NaOH }{ \longrightarrow } { CHCl }_{ 3 }+{ CH }_{ 3 }-\underset { \overset { || }{ O } }{ C } -ONa\)

(i) Ethanal (CH₃CHO) is more reactive towards nucleophilic addition reaction than propanone (\({ CH }_{ 3 }-\underset { \overset { || }{ O } }{ C } -{ CH }_{ 3 }\)) because of steric and electronic reasons.
(ii) Greater the number of alkyl groups attached, less will be the reactivity of carbonyl compound towards nucleophilic addition.
(iii) Soethanal is more reactive than propanone.

(i) The Incident light is taken from left to right (i.e. object on the left of mirror).
(ii) All the distances are measured from the pole of the mirror (pole is taken as origin).
(iii) The distances measured to the right of pole along the principal axis are taken as positive.
(iv) The distances measured to the left of pole along the principal axis are taken as negative.
(v) Heights measured in the upward perpendicular direction to the principal axis are taken as positive.
(vi) Heights measured in the downward perpendicular direction to the principal axis, are taken as negative.

(i) C be the centre of curvature of the mirror.
(ii) Consider a light ray parallel to the principal axis is incident on the mirror at M and passes through the principal focus F after reflection. An.
(iii) The line CM is the normal to the mirror at M. Let i be the angle of incidence and the same will be the angle of reflection.
(iv) If MP is the perpendicular from M on the principal axis, then from the geometry.
(v) The angles ∠MCP = i and ∠MFP = 2i
(vi) From right -angle triangles ΔMCP and ΔMFP,
\(tani=\cfrac { PM }{ PC } \) and \(tan2i=\cfrac { PM }{ PF } \)
(vii) As the angles are small, tan i≈i
\(i=\cfrac { PM }{ PC } \) and \(2i=\cfrac { PM }{ PF } \) 
(viii) Simplifying
\(2\cfrac { PM }{ PC } =\cfrac { PM }{ PF } ;2PF=PC\)

(i) The image formed by a plane mirror is virtual, erect, and laterally inverted.
(ii) The size of the image is equal to the size of the object.
(iii The image distance far behind the mirror is equal to the object distance in front of it.
(iv) If an object is placed between two plane mirrors inclined at an angle e, then the number of images n formed is as,
\(n=\left( \cfrac { 360 }{ \theta } -1 \right) \)

The angle between the incident and deviated light ray is called angle of deviation of the light ray.

According to law of reflection,
(i) The incident ray, reflected ray and normal to the reflecting surface all are coplanar (i.e: lie in the same plane).
(ii) The angle of incidence i is equal to the angle of reflection r.
i = r

The compound with molecular formula C₈H₁₀

Compound (C) with molecular formula C₃H_SBr is

An alcohol:

An alkylhalide:

An alkene: