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Published on: 19/09/2019
Transition and Inner Transition Elements
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
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1.
Draw the structure of permanganate ion.
2.
How are interstitial compounds formed?
3.
What is Zeigler - Natta catalyst?
4.
Write the equation involving the preparation of acetic acid from acetaldehyde.
5.
What is hydroformylation of olefins?
6.
Many industrial processes use transition metal or their compounds as catalyst. Why?
7.
Silver atom has completely filled d-orbitals (4d10) in its ground state. How can you say that it is a transition element?
8.
Why do transition metals have high enthalpy of hydration?
9.
Why is Ce4+ in aqueous solution is a good oxidising agent?
10.
What are coinage metals?
11.
Write ionic equation for the reaction between Cr2O7-2 ions and Fe2+ ions in acidic medium.
12.
Complete the following.
a. 3MnO42- + 4H+ ⟶?
b. C6H5CH3 \(\overset { acidified }{ \underset { KMnO_{ 4 } }{ \longrightarrow } } \)?
c. MnO4- + Fe2+ ⟶?
d. KMnO4 \(\overset { \triangle }{ \underset { Red\ hot }{ \longrightarrow } } \) ?
e. Cr2O72- + 6I- + 14H+ ⟶?
f. Na2Cr2O7 + 2KCl ⟶?
13.
What are actinides? Give three examples.
14.
Explain the oxidation states of 4d series elements.
15.
Justify the position of lanthanoids and actinoids in the periodic table.
1.
Permanganate ion has tetrahedral geometry in which the central Mn7+ is Sp3 hybridised.
2.
(i) An interstitial compound or alloy is a compound that is formed when small atoms like hydrogen, boron, carbon or nitrogen are trapped in the interstitial holes in a metal lattice.
(ii) They are usually non-stoichiometric compounds. Transition metals form a number of interstitial compounds such as TiC, ZrH1.92, Mn4N etc.
3.
A mixture of TiCl4 and trialkyl aluminium is used for polymerization.
4.
Preparation acetic acid from acetaldehyde.
5.
6.
Transition metal has energetically available d orbitals that can accept electrons from reactant molecule or metal can form bond with reactant molecule using its d electrons. For example, in the catalytic hydrogenation of an alkene, the alkene bonds to an active site by using its π electrons with an empty d orbital of the catalyst.
7.
(i) Silver in its +1 oxidation state, exhibits 4d105s0configuration.
(ii) But in some compounds, it also shows +2 oxidation state, so the configuration becomes 4d95s0
(iii) Here, d-orbital is not completely filled. Therefore silver is a transition element.
8.
Transition metal ions are smaller in case of size and have higher ionic charge, therefore they have high enthalpy of hydration.
9.
Ce4+ gains electrons to form Ce3+ ion therefore it is considered a good oxidising agent
10.
Cu, Ag and Au which have been used in making of coins in ancient times are called coinage metals
11.
Cr2O72- + 14H+ + 6Fe2+ ⟶ 2Cr3+ + 6Fe3+ + 7H2O
12.
a. 3MnO42- + 4H+ ⟶ 2MnO4- + MnO2 + 2H2O
(Manganate ion) (Permanganate ion) Manganese dioxide
b. C6H5CH3 \(\overset { acidified }{ \underset { KMnO_{ 4 } }{ \longrightarrow } } \) C6H5COOH
Toluene Benzoic Acid
c. 2MnO4- + 10Fe2++16H+ \(\underrightarrow { { 8H }^{ + } } \) 2Mn2++ 10Fe3+ + 8H2O
d. 2KMnO4 \(\overset { \triangle }{ \underset { Red\ hot }{ \longrightarrow } } \) K2MnO4 + MnO2 + O2
(Potassium Permanganate) (Potassium Manganate)
e. Cr2O72- + 6I- + 14H+ \(\underrightarrow { { (O) }}\) 2Cr3+ + 3I2 + 7H2O
(Iodide ion) Iodine
f. Na2Cr2O7 + 2KCl ⟶ K2Cr2O7 + 2NaCl
(Sodium dichromate) (Potassium dichromate)
13.
The fourteen elements following actinoids is from thorium to lawrencium are called actinides.
Examples: Uranium, Thorium, Neptunium
14.
The oxidation states of 4d metals vary from +3 for Y to +8 for Ru and Os.
The highest oxidation state of 4d elements are found in their compounds with the higher electronegative elements like O, F & Cl.
Example: In RuO4, OsO4 & WCl6
The oxidation state of Ru and Os is +8.
The oxidation state of W is +6.
Generally in going down a group, a stability of higher oxidation state increases while that of lower oxidation state decreases.
4d series (5th period) - Yttrium to Cadmium (10 elements)
| Elements | Oxidation states |
|---|---|
| Y | +3 |
| Zr | +3, +4 |
| Nb | +2, +3, +4, +5 |
| Mo | +2, +3, +4, +5, +6 |
| Tc | +2, +4, +5, +7 |
| Ru | +2, +3, +4, +5, +6, +7 +8 |
| Rh | +2, +3, +4, +6 |
| Pd | +2, +3, +4 |
| Ag | +1, +2, +3 |
| Cd | +2 |
15.
(i) The actual position of Lanthanides in the periodic table is at group number 3 and period number 6. However, in the sixth period after lanthanum, the electrons are preferentially filled in inner 4f sub shell and these fourteen elements following lanthanum show similar chemical properties.
(ii) Similarly the fourteen elements following actinium resemble in their physical and chemical properties. Hence they are placed separately bottom of the modern periodic table.
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