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Published on: 19/09/2019
Coordination Chemistry
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1.
What is Co-ordination entity?
2.
Name the following :
(i) Ring that is attached to Fe2+ in hemoglobin.
(ii) Vitamin B12 is a co-ordination compound of this element.
(iii) Complex that is used in the hydrogenation of alkenes
3.
Arrange the following complex ions in the increasing order of crystal filed splitting energy (\({ \triangle }_{ 0 }\)) [CrCI6]3-, [Cr(CN)6]3-, [Cr(NH3)6]3+
4.
How many geometrical isomers are possible in the following co-ordination entities?
(i) [Cr(C2O4)3]3-
(ii) [CO(NH3)3Cl3]
5.
Calculate the magnetic moment of [Fe(H2O)6]2+, if atomic number of Fe is 26.
6.
Give the chemical formula of potassium trioxalato ferrate(III}
7.
Write the IUPAC name of [Cu(NH3)4]SO4
8.
Define 'Ligand' Give an example of neutral ligand.
9.
Write the IUPAC name of [Ni(H2O)6] (CI)2
10.
What is the coordination number of central metal ion in [Fe(C2O4)3]3-?
11.
Name the following complex using IUPAC names. [Co(en)2(ONO)CI]CI
12.
[Ti(H2O)6]3+ is coloured, while [Sc(H2O)6]3+ is colourless- explain.
13.
Arrange the following in order of increasing molar conductivity
(i) Mg[Cr(NH3)(Cl)5]
(ii) Cr(NH3)5Cl]3[CoF6]2
(iii) [Cr(NH3)3Cl3]
14.
Draw all possible geometrical isomers of the complex [Co(en)2Cl2]+ and identify the optically active isomer.
15.
Based on VB theory explain why [Cr(NH3)6]3+ is paramagnetic, while [Ni(CN)4]2- is diamagnetic.
1.
(i) Coordination entity is an ion or a neutral molecule, composed of a central atom, usually a metal and the array of other atoms or groups of atoms (ligands) that are attached to it. In the formula, the coordination entity is enclosed in square brackets.
(ii) For example, in potassium ferrocyanide, K4[Fe(CN)6], the coordination entity is [Fe(CN)6]4-.
2.
(i) Porphyrin
(ii) Cobalt
(iii) Wilkinson Catalyst [(PPh3)3 RhCl]
3.
(i) CFSE is higher when the complex contains strong field ligand as per spectro chemical series.
(ii) Thus, crystal field splitting energy increases in the order
[CrCI6]3- < [Cr(NH3)6]3+ < [Cr(CN)6]3-, Because the order of field strength is Cl- < NH3 < CN-
4.
(i) [Cr(C2O4)3]3- - It does not possess geometrical isomerism.
(ii) [CO(NH3)3Cl3] - Two geometrical isomers are possible.
5.
Magnetic moment (μ) = \(\sqrt { n(n+2) } \) BM
Fe (z = 26) = 1s2 2s2 2p6 3s2 3p6 4s2 3d6
Fe2+ = 1s2 2s2 2p6 3s2 3p6 3d6 4s0
∴μ = \(\sqrt { n(n+2) } \) = \(\sqrt { 4(4+2) } =\sqrt { 24 } \)
= 4. 89 BM
6.
K3[Fe(C2O4)3]
7.
Tetraammine copper (II) sulphate.
8.
Ligand is an atom or a group of atoms which is either negatively charged or has lone pair of electrons and from co-ordinate bond with the central metal or ion, e.g.H2O.
9.
Hexaqua Nickel Chloride
10.
Six
11.
Monochloro is (ethane-1, 2-diamine) nitrito- K O Cobalt (III) chloride.
12.
\({ }_{22} \mathrm{Ti}-{ }_{18}[\mathrm{Ar}] 4 \mathrm{s}^{2} 3 \mathrm{d}^{2} / {}_{21}\mathrm{Sc}-{ }_{18}[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d} \)
\({ }_{22} \mathrm{Ti}^{3+}-{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{1} /{ }_{18} \mathrm{Sc}^{3+}{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{0}\)
(i) In this complex the central metal ion is Ti3+, which has d1 configuration. This single electron occupies one of the t2g orbitals in the octahedral aqua ligand field. When white light falls on this complex the electron absorbs light and promotes itself to eg level. The spectral data show the absorption maximum is at 20000 cm-1 corresponding to the crystal field splitting energy \(\left(\Delta_{o}\right)\) 239.7 kJmol-1. The transmitted colour associated with this absorption is purple and hence the complex appears purple in colour.
(ii) Thus in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \mathrm{d}-\mathrm{d}\) transition takes place.
(iii) But in \(\left[\mathrm{Sc}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \mathrm{Sc}^{3+}\) has the outer electronic configuration of 3d0 where d-d transition is not possible and it is colourless.
13.
(i) \(\mathrm{Mg}\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right) \mathrm{Cl}_{5}\right]^{2-} \rightleftharpoons \mathrm{Mg}^{2+}+\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right) \mathrm{Cl}_{5}\right]^{2-} (2 ions)\)
(ii) \(\begin{aligned}
{\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}_3\left[\mathrm{CoF}_6\right]_2 \rightleftharpoons 3\right.} & {\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]^{2+} } \\
& (5 \text { ions })
\end{aligned}\)\(+2\left[\mathrm{CoF}_6\right]^{3-}\)
(iii) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]= \text{ No ions}\)
If no of ions increases, molar conductivity increases molar conductivity of the complex also INCREASES.
\(\therefore\) The order of the given compound is
[Cr(NH3)3Cl3]<Mg[Cr(NH3)3Cl3] < [Cr(NH3)5Cl3] [CoF6]2
(No ion) (2 ions) (5 ions)
14.
[Co (en)2 Cl2]+ This is an octahedral complex
15.
\(\text {(a) }\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}:{ }_{24} \mathrm{Cr} \Rightarrow{ }_{18}[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d}^{4} \)
\({ }_{21} \mathrm{Cr}^{3+} \Rightarrow{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{3}\)
(i) d2sp3 hybridisation (octahedral)
(ii) It has three unpaired electrons (n = 3)
(iii) So it is paramagnetic
(iv) Magnetic moment \(\left(\mu_{\mathrm{s}}\right)=\sqrt{\mathrm{n}(\mathrm{n}+2)} \mathrm{BM}\)
\(=\sqrt{3(3+2)}=\sqrt{15}=3.87 \mathrm{BM}\)
\((b) \ \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-:}{ }_{28} \mathrm{Ni} \Rightarrow[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d}^{8} ;{ }_{26} \mathrm{Ni}^{2+} \Rightarrow{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{8}\)
(i) dsp2 hybridisation
(ii) Geometry - square planar
(iii) No unpaired electrons- It is Diamagnetic
(iv) Magnetic moment (μs) = 0.
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