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Published on: 22/01/2020
Organic Nitrogen Compounds
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1.
Can aniline be prepared by Gabriel phthalimide reaction? Justify your answer.
2.
Write a note on Libermann's nitroso test.
3.
Convert methyl amine (1° primary amine) to 2°, 3° amine and Quarternary ammonium salt.
4.
Identify the compounds A,B,C in the following reactions
(i) \(CH_{ 2 }CO{ NH }_{ 2 }\xrightarrow [ NaOH ]{ { Br }_{ 2 } } A\underrightarrow { { HNO }_{ 2 } } B\xrightarrow [ { I }_{ 2 } ]{ RedP } C\)
(ii) \({ C }_{ 2 }{ H }_{ 5 }Cl\underrightarrow { AgCN } A\underrightarrow { Sn/HCl } B\underrightarrow { { HNO }_{ 2 } } C\)
5.
\({ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }\xrightarrow [ 273k,HCl ]{ { HNO }_{ 2 } } A\xrightarrow [ { Cu }_{ 2 }({ CN })_{ 2 } ]{ KCN } B \stackrel { { H }_{ 3 }O }\rightarrow C\)
Identify A, Band C.
6.
Explain why amines are more basic than amides.
7.
What happens when aniline is treated with bromine?
8.
What are amines? How are they classified?
9.
Nitrobenzene does not undergo Friedel Crafts reaction - Give reason.
10.
There are two isomers with the formula CH3NO2. How will you distinguish between them?
11.
Write down the possible isomers of the C4H9NO2 give their IUPAC names.
12.
Write short notes on the following
i. Hofmann’s bromide reaction
ii. Ammonolysis
iii. Gabriel phthalimide synthesis
iv. Schotten – Baumann reaction
v. Carbylamine reaction
vi. Mustard oil reaction
vii. Coupling reaction
viii. Diazotisation
ix. Gomberg reaction
13.
Identify compounds A, B and C in the following sequence of reactions.
i) \({ C }_{ 6 }{ H }_{ 5 }NO_{ 2 }\overset { Fe/HCL }{ \longrightarrow } A\overset { HN{ O }_{ 2 } }{ \underset { 273K }{ \longrightarrow } } B\overset { { C }_{ 6 }{ H }_{ 5 }OH }{ \longrightarrow } C\)
ii) \({ C }_{ 6 }{ H }_{ 5 }N_{ 2 }cl\overset { CuCN }{ \longrightarrow } A\overset { H_{ 2 }O/H^{ + } }{ \longrightarrow } B\overset { NH_3 }{ \longrightarrow } C\)
iii) \({ C }{ H }_{ 3 }{ C }{ H }_{ 2 }I\overset { NaCN}{ \longrightarrow } A\overset {OH^-}{ \underset {Partial hydrolysis}{ \longrightarrow } } B\overset {NaOH+Br_2 }{ \longrightarrow } C\)
iv) \({ C }{ H }_{ 3 }NH_{ 2 }\overset { CH_3 Br }{ \longrightarrow } A\overset { CH_{ 3 }COCl}{ \longrightarrow } B\overset { B_2H_6 }{ \longrightarrow } C\)
v) \({ C }_{ 6 }{ H }_{ 5 }NH_{ 2 }\overset { (CH_{ 3 }CO)_{ 2 }O }{ \underset { Pyridine }{ \longrightarrow } } A\overset { HNO_{ 3 } }{ \underset { H_{ 2 }SO_{ 4 },288K }{ \longrightarrow } } B\overset { { H }_{ 2 }O/{ H }^{ + } }{ \longrightarrow C } \)
vi)

vii) \({ C }{ H }_{ 3 }CN_{ 2 }NC\overset { HgO }{ \longrightarrow } A\overset { H_{ 2 }O }{ \longrightarrow } B\overset { i) NaN{ O }_{ 2 }/HCL }{ \underset { ii){ H }_{ 2 }O }{ \longrightarrow } } \)
14.
How will you convert nitrobenzene into
i. 1,3,5 - trinitrobenzene
ii. o and p- nitrophenol
iii. m – nitro aniline
iv. azoxybenzene
v. hydrozobenzene
vi. N – phenylhydroxylamine
vii. aniline
15.
What happens when
i. 2 – Nitropropane boiled with HCl
ii. Nitrobenezene undergo electrolytic reduction in strongly acidic medium.
iii. Oxidation of tert – butylamine with KMnO4
iv. Oxidation of acetoneoxime with trifluoroperoxy acetic acid
1.
No, aniline cannot be prepared by Gabriel phthalimide reaction. This method involves the treatment of potassium phthalimide with aryl halides. But aryl halides does not undergo nucleophilic substitution under ordinary conditions.
2.
Alkyl and aryl secondary amines react with nitrous acid to give N - nitroso amine as yellow oily liquid which is insoluble in water
This reaction is known as Libermann's nitroso test.
3.
4.
5.
6.
In simple amines the lone pair of electrons is on nitrogen and hence available for protonation. In amides, on the other hand, the electron pair on nitrogen is delocalized to the carbonyl oxygen through resonance.
7.
Aniline decolourises bromine water with the formation of white precipitate which is 2,4,6-tribromo aniline
8.
(i) Amines are compounds derived from ammonia by replacing one or more hydrogen atoms by alkyl or aryl group.
(ii) They are classified as primary, secondary and tertiary amines.
(a) When one of the hydrogen atoms in NH3 is replaced by alkyl, it is primary amine CH3NH methyl aminefl
(b) If two hydrogen atoms of amine group are replaced by alkyl groups, it is a secondary amine (CH3)2 NH- dimethylamine (2°).
(c) If three hydrogen atoms of amine group are replaced by alkyl groups, it is a tertiary amine. (CH3)3 N-trimethylamine (3°). Aromatic amine - C6H5NH2 Aline
9.
Nitrobenzene does not undergo Friedel - Crafts reactions due to the strong deactivating nature of -NO2 group.
10.
a) Primary and secondary nitroalkanes, having α-H, also show an equilibrium mixture of two tautomers namely nitro - and aci - form
b) Difference:
| S.No | Nitro form | Aci - form |
| 1. | Less acidic in nature. | More acidic |
| 2. | Dissolves in NaOH slowly | Dissolves in NaOH instantly |
| 3. | Decolourises FeCl3 solution | With FeCl3 gives reddish brown colour |
| 4. | Electrical conductivity is low | Electrical conductivity is high |
11.
| Isomerism | Structural formula of isomers |
| Chain isomerism: They differ in the length of carbon chain. |
|
| Position isomerism: They differ in the position of nitro group. |
|
| Functional isomerism: Nitroalkanes exhibit functional isomerism with alkylnitrites |
\( \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{NO}_{2} \text { and } \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2}-\mathrm{O}-\mathrm{N}=\mathrm{O}\\ \quad 1 - nitrobutane \quad \quad \quad \quad \quad \quad \quad butyl \ nitrite\) |
12.
Hoffmann's bromide reaction:
When Amides are treated with bromine in the presence of aqueous or ethanolic solution of KOH, primary amines with one carbon atom less than the parent amides are obtained.
\(\underset { \quad \quad \quad amide\\ R=Alkyl(or)Aryl }{ R-\overset { \underset { || }{ O } }{ C } -{ NH }_{ 2 } } \overset { { Br }_{ 2 }/KOH }{ \longrightarrow } \underset { Primary\quad amine }{ R-{ NH }_{ 2 }+{ K }_{ 2 }{ CO }_{ 3 } } +KBr+{ H }_{ 2 }O\)
(ii) Hoffmann's ammonolysis:
When Alkyl halides (or) benzylhalides are heated with alcoholic ammonia in a sealed tube, mixtures of 1°, 2° and 3° amines and quaternary ammonium salts are obtained.
\( { CH }_{ 3 }-Br\overset { \ddot { N } { H }_{ 3 } }{ \underset { \Delta }{ \longrightarrow } } \underset { { 1 }^{ 0 }-amine }{ { CH }_{ 3 }-\ddot { N } { H }_{ 2 } } \overset { { CH }_{ 3 }-Br }{ \longrightarrow } \underset { { 3 }^{ o }-amine }{ \left( { CH }_{ 3 } \right) _{ 2 }\ddot { N } H } \overset { { CH }_{ 3 }Br }{ \longrightarrow } \underset { 3^{ o }-amine }{ \left( { { CH }_{ 3 } } \right) _{ 3 }\ddot { N } } \overset { CH_{ 3 }Br }{ \longrightarrow } \underset { Quartenary \ ammonium\ bromide }{ \left( { CH }_{ 3 } \right) _{ 4 }\overset { + }{ N } { Br }^{ - } } \)
This is a nucleophilic substitution, the halide ion of alkyl halide is substituted by the -NH2 group. The product primary amine so formed can also has a tendency to act as a nucleophile and hence if excess alkyl halide is taken, further nucleophilic substitution takes place leading to the formation of quarternary ammonium salt. However, if the process is carried out with excess ammonia, primary amine is obtained as the major product. The order of reactivity of alkylhalides with amines
RI > RBr > RCl
(iii) Gabriel phthalimide synthesis:
Gabriel synthesis is used for the preparation of Aliphatic primary amines. Phthalimide on treatment with ethanolic KOH forms potassium salt of phthalimide which on heating with alkyl halide followed by alkaline hydrolysis gives primary amine. Aniline cannot be prepared by this method because the arylhalides do not undergo nucleophilic substitution with the anion formed by phthalimide.
(iv) Schotten - Baumann reaction :
Aniline reacts with benzoylchloride (C6H5COCI) in the presence of NaOH to give N - phenyl benzamide. This reaction is known as Schotten - Baumann reaction. The acylation and benzoylation are nucleophilic substitutions.
\(\underset { Aniline }{ { C }_{ 6 }{ H }_{ 5 }-{ NH }_{ 2 } } +\underset { Benzoyl\quad chloride }{ { C }_{ 6 }{ H }_{ 5 }-\overset { \underset { || }{ O } }{ C } -Cl } \overset { Pyridine }{ \longrightarrow } \underset { N-phenyl\quad benzamide }{ { C }_{ 6 }{ H }_{ 5 }-NH-\overset { \underset { || }{ O } }{ C } -{ C }_{ 6 }{ H }_{ 5 } } +HCl\)
(v) Carbylamine reaction :
Aliphatic (or) aromatic primary amines react with: chloroform and alcoholic KOH to give isocyanides (carbylamines), which has an unpleasant smell. This reaction is known as carbylamines test. This test used to identify the primary amines.
\(\underset { Ethylamine }{ { C }_{ 2 }{ H }_{ 5 }-{ NH }_{ 2 } } +\underset { Chloroform }{ { CHCl }_{ 3 }+3KOH } \longrightarrow \underset { Ethylisocyanide }{ { C }_{ 2 }{ H }_{ 5 }-NC } +3KCl+3{ H }_{ 2 }O\)
(vi) Mustard oil reaction:
(a) When primary amines are treated with carbon disulphide (CS2), N - alkyldithio carbonic acid is formed which on subsequent treatment with HgCI2, gives an alkyl isothiocyanate.
(b) When aniline is treated with carbon disulphide, or heated together, S-diphenylthio urea is formed, which on boiling with strong HCI, phenyl isothiocyanate (phenyl mustard oil), is formed.
These reactions are known as Hofmann - Mustard oil reaction. This test is used to identify the primary amines.
(vii) Coupling reactions (or) p-hydroxyazobenzene, p-aminoazobenzene, 2-phenyl azo-4-methyl phenol:
Benzene diazonium chloride reacts with electron rich aromatic compounds like phenol, aniline to form brightly coloured azo compounds. Coupling generally occurs at the para position. If para position is occupied then coupling occurs at the ortho position. Coupling tendency is enhanced if an electron donating group is present at the para - position to -N2CI- group. This is an electrophilic substitution.
Aryl fluorides and iodides cannot be prepared by direct halogenation and the cyano group cannot be introduced by nucleophilic substitution of chlorine in chlorobenzene. For introducing such a halide group. cyano group -OH, NO2, etc.. benzenediazonium chloride is a very good intermediate Diazo compounds obtained from the coupling reactions of diazonium salts are coloured and are used as dyes.
(viii) Diazotisation :
Aniline reacts with nitrous acid at low temperature (273 - 278 K) to give benzene. Diazonium chloride which is stable for a short time and slowly decomposes even at low temperatures.This reaction is known as diazotization
(ix) Gomberg reaction :
Benzene diazonium chloride reacts with benzene in the presence of sodium hydroxide to give biphenyl. This reaction in known as the Gomberg reaction
13.
+CO2
14.
Nitrobenzene into 1,3,5 - trinitro benzene
Nitrobenzene 1,3,5 - trinitro benzene
ii. Nitrobenzene into o - and p - nitro phenols
iii. Nitrobenzene into m - nitro aniline
+ 6NH3 + 2H2O + 3S
iv. Nitrobenzene into azoxybenzene
+3H2O
v. Nitrobenzene into hydrazobenzene
vi. Nitrobenzene into N - phenyl hydrazobenzene
vii. Nitrobenzene into aniline
15.
i) 2 - nitro propane is boiled with HCI:
It gives acetone.
ii) Nitrobenzene on electrolytic reduction in strongly acidic medium:
It gives aniline, phenyl hydroxylamine and p - amino phenol
iii) Oxidation of text – butylamine with KMnO4:
It gives 2 - methyl - 2- nitro propane is obtained.
iv) Oxidation of acetoneoxime with trifluoroperoxy acetic acid.
It gives 2 - nitro propane.
12th Standard Syllabus & Materials
12th Standard
TN 12th Tamil அருமை உடைய செயல் - செய்யுள்-தேவாரம் Sample Question Papers Study Material - QB365 Set A
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